lambda x,y: x*y is an anonymous function otherwise equivalent to
def foo(x, y):
return x*y
To understand its use in reduce(lambda ...), consider the example from the docs:
reduce(lambda x, y: x+y, [1, 2, 3, 4, 5]) calculates ((((1+2)+3)+4)+5).
Similarly, reduce(lambda x,y:x*y,[3,4,5]) calculates ((3*4)*5).
Answer from unutbu on Stack Overflow
Why do you need to state both 'x' and 'y' before the ':'?
Because a lambda is (conceptually) the same as a function, just written inline. Your example is equivalent to
def f(x, y) : return x + y
just without binding it to a name like f.
Also how do you make it return multiple arguments?
The same way like with a function. Preferably, you return a tuple:
lambda x, y: (x+y, x-y)
Or a list, or a class, or whatever.
The thing with self.entry_1.bind should be answered by Demosthenex.
I believe bind always tries to send an event parameter. Try:
self.entry_1.bind("<Return>", lambda event: self.calculate(self.buttonOut_1.grid_info(), 1))
You accept the parameter and never use it.
Creating a simple lambda function that checks if 2 variables exist!
How to write a lambda function that is conditional on two variables (columns) in python - Stack Overflow
Need some help with variables in qtile
You've fallen into a trap that often catches a lot of people out (me included).
If you loop over a variable and want to pass that specific value to a lambda function, you need to do something like lambda value=i: logger.warning(f"{value}").
[SymPy] Confused with lambda function arguments
What exactly is the problem you're trying to solve?
More on reddit.comI want to get better at creating lambda function, I don't understand the format of how to create one yet so I tried with this, but its not working :( I want to make this into a single line lambda function:
var_1 = 1
var_2 = 'lettuce'
def check_exists(var1=None,var2=None):
if var1 and var2:
return True
else:
return FalseThis didn't work, I'm not sure why, could someone explain?
lambda var_1, var_2 : if var_1 and var_2 else False
I see the error: SyntaxError: invalid syntax
Use where:
df['dummyVar '] = df['x'].where((df['x'] > 100) & (df['y'] < 50), df['y'])
This will be much faster than performing an apply operation as it is vectorised.
Like this:
f = lambda x, y: x if x>100 and y<50 else y
Lambda(s) in Python are equivalent to a normal function definition.
def f(x, y):
return x if x>100 and y<50 else y
NB: The body of a Lambda must be a valid expression. This means you cannot use things like: return for example; a Lambda will return the last expression evaluated.
For some good reading see:
- Defining Functions
- Lambdas