You should console.log() your javascript by placing the following in you ajax post:

error : function(e){
   console.log(e);
}

You can then see what errors you are getting in your browsers' developers tools panel.

You should also be aware that that Laravel posts require a csrf token unless you have explicitly turned them off, which means you will need to add this token in to your post as well. So you should end up with:

$("#submit").on('click', function() {
    $.ajax({
        url:'/app/Http/Controllers/Search/search_address', // Is this what you meant, is this the route you set up?
        type: 'POST',
        data: {'data': objs, '_token' : '<?=csrf_token()?>'},
        success : function(data){
          // Do what you want with your data on success
        },
        error : function(e){
           console.log(e);
        }
    });
});

Notice that I've embedded php inside the javascript, which is just to illustrate the point. Ideally javascript is kept in it's own files, so you would then need to find a way to pass this token through. I personally use knockoutjs for this type of thing (AngularJS is also popular), but you can easily do something like:

<input type="hidden" id="_token" value="{{ csrf_token() }}" />

in your HTML, then pull this value from inside your ajax request:

data: {'data': objs, '_token' : $('#_token').val()}

EDIT

I've just noticed your url, it looks like you are trying to access the controller directly. You need to set up a route in your routes.php file, such as:

Route::post('/searchAddress', 'YourController@search_address');

Then use:

url: /searchAddress

in your ajax request.

Try this way:

In your controller

public function provider() 
{

  $sites = [
    0 => "Mon", 
    1 => "Tue", 
    2 => "Wed", 
    3 => "Thu",
    4 => "Fri", 
    5 => "Sat",
    6 => "Sun"
  ];

  $response = [
     'msg' => 'Success',
     'status' => 1,
     'data' => $sites
  ];

  return response()->json($response);

}

In your view file

<script>
    $(document).ready(function(){
        getdata();
    });

    function getdata(){
       var ajx = new XMLHttpRequest();
       ajx.onreadystatechange = function(){
           if(ajx.readyState == 4 && ajx.status == 200){
               var demo = JSON.parse(ajx.responseText);
               console.log(demo.data);
           }
       }

       ajx.open("GET",'/resultsprovirder',true);
       ajx.send();
    }
</script>

You will get your data in demo.data or check your console.

you can use json_encode()

var array = {{ json_encode($theArray) }};

or parse the json string using JSON.parse()

var array = JSON.parse('{{ json_encode($theArray) }}');

A better way to do is, create one form with hidden variable than when you are calling you javascript check() function, store the array value in the hidden variable and than use javascript form.submit() method.

when you working in javascript and need data in javascript then why you need view part. Actually, I just read your comment. If in Ajax

so I suggest send array with json_encode and populate that data into view with javascript. simply right below in controller

response()->json(['status'=>200,'data'=>$dicomfilearray])

Update So ,you not sending ajax request so, simply. do like below.

controller:-

$data = json_encode($dicomfilearray);
    return view('your-view',compact('data'));

javascript

var dicomarray = '{{ $data }}';

    public class AssignmentViewModels
    {
        public string title { get; set; }
        public string id { get; set; }
        public string class { get; set; }
        public string date { get; set; }
        public string description { get; set; }
    }


    public JsonResult updateAssignment(string title, string id, string class, string date, string description)
    {
        var model = new AssignmentViewModels();// if you have a list of data return, make "List<AssignmentViewModels>()" ,& in Ajax sucess method, make a foreach loop & collect the data.
        model = repository._update(title,id,class,date,description);//return updated data
        return Json(model, JsonRequestBehavior.AllowGet);
    }


    var URL = ResolvedUrl.replace('ActionName', 'updateAssignment').replace('ControllerName', 'YourController');
    var data = { title: title, id: id, class: subject, date: date, description: description };
    $.get(URL, data, function (result) {
            if ($('#h2')[0]) {
                $('#h2').val(result.title);// no need to use JSON.parse
            }
    }

HTML

<input type="hidden" id="club-id" value="<?php echo $club->id ?>" />

Javascript

var club_id = $('#club-id').val().trim();