str.toCharArray().lengthshould work.Or how about:
str.lastIndexOf("")Probably even runs in constant time :)
Another one
Matcher m = Pattern.compile("$").matcher(str); m.find(); int length = m.end();One of the dumbest solutions:
str.split("").length - 1Is this cheating:
new StringBuilder(str).length()? :-)
str.toCharArray().lengthshould work.Or how about:
str.lastIndexOf("")Probably even runs in constant time :)
Another one
Matcher m = Pattern.compile("$").matcher(str); m.find(); int length = m.end();One of the dumbest solutions:
str.split("").length - 1Is this cheating:
new StringBuilder(str).length()? :-)
String blah = "HellO";
int count = 0;
for (char c : blah.toCharArray()) {
count++;
}
System.out.println("blah's length: " + count);
Videos
You can access the count variable in the String class by setting the count variable accessibility as true though it may through security exceptions sometimes. For instance :
Field var = String.class.getDeclaredField("count");
var.setAccessible(true);
String str = "variable";
int count = var.getInt(str);
Reference : http://docs.oracle.com/javase/6/docs/api/java/lang/reflect/AccessibleObject.html
I'll quote the best, most absurd answer from the linked SO question. This one only uses constructors and equals(), so arguably it doesn't use any methods of String. All credit should go to the original answerer.
"Just to complete this with the most stupid method I can come up with: Generate all possible strings of length 1, use equals to compare them to the original string; if they are equal, the string length is 1. If no string matches, generate all possible strings of length 2, compare them, for string length 2. Etc. Continue until you find the string length or the universe ends, whatever happens first."
Hi, I've been trying to find a name for my method that returns the length of an object. A quick google search showed that it's conventional to name getters getX(). However, when I investigated the first standard class that came to mind - String, I found it having the length() method instead of expected getLength(). Why is that? How should I name a length method in my own class then?
https://docs.oracle.com/javase/8/docs/api/java/lang/String.html#length--
The normal model of Java string length
String.length() is specified as returning the number of char values ("code units") in the String. That is the most generally useful definition of the length of a Java String; see below.
Your description1 of the semantics of length based on the size of the backing array/array slice is incorrect. The fact that the value returned by length() is also the size of the backing array or array slice is merely an implementation detail of typical Java class libraries. String does not need to be implemented that way. Indeed, I think I've seen Java String implementations where it WASN'T implemented that way.
Alternative models of string length.
To get the number of Unicode codepoints in a String use str.codePointCount(0, str.length()) -- see the javadoc.
To get the size (in bytes) of a String in a specific encoding (i.e. charset) use str.getBytes(charset).length2.
To deal with locale-specific issues, you can use Normalizer to normalize the String to whatever form is most appropriate to your use-case, and then use codePointCount as above. But in some cases, even this won't work; e.g. the Hungarian letter counting rules which the Unicode standard apparently doesn't cater for.
Using String.length() is generally OK
The reason that most applications use String.length() is that most applications are not concerned with counting the number of characters in words, texts, etcetera in a human-centric way. For instance, if I do this:
String s = "hi mum how are you";
int pos = s.indexOf("mum");
String textAfterMum = s.substring(pos + "mum".length());
it really doesn't matter that "mum".length() is not returning code points or that it is not a linguistically correct character count. It is measuring the length of the string using the model that is appropriate to the task at hand. And it works.
Obviously, things get a bit more complicated when you do multilingual text analysis; e.g. searching for words. But even then, if you normalize your text and parameters before you start, you can safely code in terms of "code units" rather than "code points" most of the time; i.e. length() still works.
1 - This description was on some versions of the question. See the edit history ... if you have sufficient rep points.
2 - Using str.getBytes(charset).length entails doing the encoding and throwing it away. There is possibly a general way to do this without that copy. It would entail wrapping the String as a CharBuffer, creating a custom ByteBuffer with no backing to act as a byte counter, and then using Encoder.encode(...) to count the bytes. Note: I have not tried this, and I would not recommend trying unless you have clear evidence that getBytes(charset) is a significant performance bottleneck.
java.text.BreakIterator is able to iterate over text and can report on "character", word, sentence and line boundaries.
Consider this code:
def length(text: String, locale: java.util.Locale = java.util.Locale.ENGLISH) = {
val charIterator = java.text.BreakIterator.getCharacterInstance(locale)
charIterator.setText(text)
var result = 0
while(charIterator.next() != BreakIterator.DONE) result += 1
result
}
Running it:
scala> val text = "Thîs lóo̰ks we̐ird!"
text: java.lang.String = Thîs lóo̰ks we̐ird!
scala> val length = length(text)
length: Int = 17
scala> val codepoints = text.codePointCount(0, text.length)
codepoints: Int = 21
With surrogate pairs:
scala> val parens = "\uDBFF\uDFFCsurpi\u0301se!\uDBFF\uDFFD"
parens: java.lang.String = surpíse!
scala> val length = length(parens)
length: Int = 10
scala> val codepoints = parens.codePointCount(0, parens.length)
codepoints: Int = 11
scala> val codeunits = parens.length
codeunits: Int = 13
This should do the job in most cases.