There are two principal ways to create vectors in MATLAB. One is the *|(:)|* operator, and the other is the *|linspace|* function. The principal difference is that with the *|colon|* operator, you define the _interval_ between successive elements and let the _length_ of the resulting vector vary, and in *|linspace|*, you define the _length_ of the vector and the function calculates the _interval_ to fit the length.

@Kyle Weaver I recommend 'MATLAB Learning Material' and 'References' for further understanding. % Define the range of t with 450 data points between -4*pi and 4*pi t = % write the linspace command here % Calculate y for each t using the given function: y = sin(t) y = % write the function 'y' command here % Plotting y as a function of t plot(t, y) xlabel('t') ylabel('y') title('Plotting Sine Functions') grid on MATLAB Learning Material: MATLAB Onramp | Self-Paced Online Courses - MATLAB & Simulink (mathworks.com) References Generate linearly spaced vector - MATLAB linspace (mathworks.com) Sine of argument in radians - MATLAB sin (mathworks.com) --------------------------------------------------------------------------------------------------------------------------------------------------- If you find the solution helpful and it resolves your issue, it would be greatly appreciated if you could accept the answer. Also, leaving an upvote and a comment are also wonderful ways to provide feedback. Professional Interests Technical Services and Consulting Embedded Systems | Firmware Developement | Simulations Electrical and Electronics Engineering Feel free to contact me.

Maybe you can just do:

n=261;
linspace(1,n,(n-1)*360);

MATLAB provides functions that do basic things, like create linearly spaced vectors using the colon operator or linspace. It is up to the user to find ways to make these functions do the things we want. n = -2:0.5:0; x = 4.^n; % ans = % 0.0625 0.125 0.25 0.5 1

The only difference between linspace and logspace is that they go one step further and take the power of 10 for every element in the linspace array.

As such, you'd simply take your equation for linspace you generated, take the result and raise it to the power of 10. However, with your code, you are relying on the previous result and that is already raised to the power of 10. Therefore, you'll need to take the anti-log to convert the previous result back to a linear form, then use the same logic was used to generate the linspace, then raise it back to the power of 10. Therefore, the relationship is:

xx[n] = 10^(log10(xx[n-1]) + ((b-a)/(n-1))) 

You can certainly simplify this, taking advantage of the fact that 10^(log10(z)) = z, as long as z > 0. We can also split up the terms in the power using the property that 10^(m + n) = (10^m) * (10^n). Therefore:

xx[n] = xx[n-1] * (10^((b-a)/(n-1)))

As such, simply take your previous result multiply with 10^((b-a)/(n-1))

a = 1; b = 5; n = 7;

x = logspace(1,5,7);
xx = zeros(1,n); xx(1) = 10^a;
for i=2:n
    xx(i) = xx(i-1)*(10^((b-a)/(n-1))); %// Change 
end

We get for both x and xx:

>> format long g;
>> x

x =

  Columns 1 through 4

                        10          46.4158883361278          215.443469003188                      1000

  Columns 5 through 7

          4641.58883361278          21544.3469003189                    100000

>> xx

xx =

  Columns 1 through 4

                        10          46.4158883361278          215.443469003188                      1000

  Columns 5 through 7

          4641.58883361278          21544.3469003188                    100000