If your shell supports process substitution (Bash-style follows, see docs):

diff <(jq --sort-keys . A.json) <(jq --sort-keys . B.json)

Objects key order will be ignored, but array order will still matter. It is possible to work-around that, if desired, by sorting array values in some other way, or making them set-like (e.g. ["foo", "bar"] → {"foo": null, "bar": null}; this will also remove duplicates).

Alternatively, substitute diff for some other comparator, e.g. cmp, colordiff, or vimdiff, depending on your needs. If all you want is a yes or no answer, consider using cmp and passing --compact-output to jq to not format the output for a potential small performance increase.

Use jq to first sort all keys. Then diff to do the diffing:

jq -S . A.json > A-sorted.json
jq -S . B.json > B-sorted.json
diff A-sorted.json B-sorted.json

The above example is for Linux but both jq and diff is available for Windows. It seems Windows has an alternative diff tool called fc, perhaps this could be used instead of diff.

To compare json files you should convert them so they have same order of keys. Very good tool for this job is jq (https://stedolan.github.io/jq/) where you can do:

jq -S . fileA.json > fileA_fmt.json
jq -S . fileB.json > fileB_fmt.json

then, you can use your favourite tool for text file comparison. I like kdiff3 for GUI or just plain diff when in pure command-line e.g.:

diff fileA_fmt.json fileB_fmt.json