One simple way is to append your list items in a StringBuilder
List<Integer> list = new ArrayList<>();
list.add(1);
list.add(2);
list.add(3);
StringBuilder b = new StringBuilder();
list.forEach(b::append);
System.out.println(b);
you can also try:
String s = list.stream().map(e -> e.toString()).reduce("", String::concat);
Explanation: map converts Integer stream to String stream, then its reduced as concatenation of all the elements.
Note: This is normal reduction which performs in O(n2)
for better performance use a StringBuilder or mutable reduction similar to F. Bรถller's answer.
String s = list.stream().map(Object::toString).collect(Collectors.joining(","));
Ref: Stream Reduction
Answer from Shailesh Aswal on Stack OverflowWhat are some common issues faced when converting a list to a string in Java?
How can you remove brackets when converting a list to a string in Java?
What are the differences between hashmap and hashtable in Java?
One simple way is to append your list items in a StringBuilder
List<Integer> list = new ArrayList<>();
list.add(1);
list.add(2);
list.add(3);
StringBuilder b = new StringBuilder();
list.forEach(b::append);
System.out.println(b);
you can also try:
String s = list.stream().map(e -> e.toString()).reduce("", String::concat);
Explanation: map converts Integer stream to String stream, then its reduced as concatenation of all the elements.
Note: This is normal reduction which performs in O(n2)
for better performance use a StringBuilder or mutable reduction similar to F. Bรถller's answer.
String s = list.stream().map(Object::toString).collect(Collectors.joining(","));
Ref: Stream Reduction
There is a collector joining in the API.
It's a static method in Collectors.
list.stream().map(Object::toString).collect(Collectors.joining(","))
Not perfect because of the necessary call of toString, but works. Different delimiters are possible.
In Java 8 or later:
String listString = String.join(", ", list);
In case the list is not of type String, a joining collector can be used:
String listString = list.stream().map(Object::toString)
.collect(Collectors.joining(", "));
If you happen to be doing this on Android, there is a nice utility for this called TextUtils which has a .join(String delimiter, Iterable) method.
List<String> list = new ArrayList<String>();
list.add("Item 1");
list.add("Item 2");
String joined = TextUtils.join(", ", list);
Obviously not much use outside of Android, but figured I'd add it to this thread...
Use Stream.concat inside the flatMap operation:
references.stream()
.flatMap(user -> Stream.concat(
Stream.of(user.getId()),
user.getExternalIds().stream()
))
.collect(Collectors.toList())
Try this:
references.stream()
.flatMap(u -> Stream.of(List.of(u.getId()), u.getExternalIds()))
.flatMap(List::stream)
.collect(Collectors.toList());
You want
String[] strarray = strlist.toArray(new String[0]);
See here for the documentation and note that you can also call this method in such a way that it populates the passed array, rather than just using it to work out what type to return. Also note that maybe when you print your array you'd prefer
System.out.println(Arrays.toString(strarray));
since that will print the actual elements.
public static void main(String[] args) {
List<String> strlist = new ArrayList<String>();
strlist.add("sdfs1");
strlist.add("sdfs2");
String[] strarray = new String[strlist.size()]
strlist.toArray(strarray );
System.out.println(strarray);
}