list1=[1,3] list2=list1 list1[0]=4 print(list2) On your 2nd line, you have "list2 = list1" - this does not copy list1 to list2, instead, both list1 and list2 are pointing at the same list object. This is true for lists, dicts, and all objects in python. So if you wanted list2 to be a copy of list1, you'd need to do something to explicitly copy it, such as list2 = list(list1) This creates a new list which is a shallow copy of list1 - note that if list1's elements are also objects or lists or dicts, then THOSE don't get copied - if you have nested data structures and want a true copy then you need to use the deepcopy library More on reddit.com

if you would want the last 3 items without knowing the length of the list. [-3:] More on reddit.com

Python only has a limited amount of built-in functions, which you can find here https://docs.python.org/3/library/functions.html More on reddit.com

std::vector is very popular and is more like a Python list than std::array. However, all elements in a std::vector must have the same type whereas a Python list can have a variety of types. I also find it helpful to remember that std::unordered_map is similar to a Python dictionary. More on reddit.com