You can do something like this:

var cubes = [
 [1, 2, 3],
 [4, 5, 6],    
 [7, 8, 9],
];

for(var i = 0; i < cubes.length; i++) {
    var cube = cubes[i];
    for(var j = 0; j < cube.length; j++) {
        display("cube[" + i + "][" + j + "] = " + cube[j]);
    }
}

Working jsFiddle:

• http://jsfiddle.net/TRR4n/

The output of the above:

cube[0][0] = 1
cube[0][1] = 2
cube[0][2] = 3
cube[1][0] = 4
cube[1][1] = 5
cube[1][2] = 6
cube[2][0] = 7
cube[2][1] = 8
cube[2][2] = 9

To return a value in a multidimensional array: array[n][m] is the mth element of the nth row. To do this for every element, use embedded for-loops:

for (var i = 0; i < array.length; i++){
    for (var j = 0; j < array[i].length; j++){
        console.log(array[i][j]);

First, you should not add elements to arrays by key, but to objects. Which means your global object should be build as :

var _cQueue = [];
var valueToPush = {}; // this isn't an array but a js object used as map
valueToPush['[email protected]'] = '1234567';
_cQueue.push(valueToPush);

Then, you iterate using two kinds of loops :

for (var i=0; i<_cQueue.length; i++) { // iterate on the array
   var obj = _cQueue[i];
   for (var key in obj) { // iterate on object properties
      var value = obj[key];
      console.log(value);
   }
}

See MDN's excellent Working with objects.

If you want to find the email associated to an id, you can do two things :

1) loop until you find it :

function find(id) {
    for (var i=0; i<_cQueue.length; i++) { // iterate on the array
       var obj = _cQueue[i];
       for (var key in obj) { // iterate on object properties
          var value = obj[key];
          if (value==id) return key;
       }
    }
}

2) put all the ids in a map so that it can be found faster :

   var bigMap = {};
   for (var i=0; i<_cQueue.length; i++) { // iterate on the array
       var obj = _cQueue[i];
       for (var key in obj) { // iterate on object properties
          bigMap[obj[key]] = key; // maps the id to the email
       }
    }
    function find(id) {
        return bigMap[id];
    }

With due credit to @Matt who's comment points it out.

The commonest format for looping through an array is:

 for(var i=0; i<array.length; i++) {
     doSomethingWith(array[i];
 }

Note that's a "less than" operator, not a "less than or equal to" operator.

This loop counts from 0 to array.length - 1, because the second part of the for statement: i < array.length, means "keep repeating for as long as i is less than array.length.

... and that's what you want, because arrays are numbered from 0 to length-1. That is, an array of length 4 is numbered 0,1,2,3.

If you loop while i <= 4, then the loop will execute for 0,1,2,3,4 -- and in Javascript, it will get undefined when it references array[4].

Sometimes you do need "<=" in a for loop, but it's very much the exception. Any time you do use "<=", think about adding a comment to say why.

You can filter with this:

var filteredProducts = {},
    dim = $("select[name=dim]").val(),
    acc = $("select[name=acc]").val(),
    option = $("select[name=options]").val();

function valueInObject(object, value){
   for(var key in object){
      if(object[key] == value) return true;
   }
   return false;      
}

$.each(obj, function(key, product){
    if(
      (option == "" || $.inArray(option, product.options)) >= 0 && 
      (acc == "" || valueInObject(product.acc, acc)) &&
      (dim == "" || valueInObject(product.dim, dim))   
    ){
       filteredProducts[key] = product;
    }
});

console.log(filteredProducts);
alert(JSON.stringify(filteredProducts));

Then, you have the filtered products in the filteredProducts object, that has same structure as the original obj object. Then you can traverse it and show it in a table or something.

Assuming you want to show them on a list, let's say you have:

<div id="filteredProducts"></div>

you would do:

$('#filteredProducts').empty();  //Clears previous results
$.each(filteredProducts, function(productKey, product){
    $('<div class="title">'+productKey+'<br/>'+
          '<a href="'+ product.url+'">'+ product.url + '</a>'+
      '</div>').appendTo('#filteredProducts');
});     

It would add each product to the list.

Cheers, from La Paz, Bolivia

This code should work:

var cubes = [[1, 2, 3],[4, 5, 6],[7, 8, 9]];

for(var i=0; i<cubes[0].length; ++i)
for(var j=0; j<cubes[1].length; ++j)
for(var k=0; k<cubes[2].length; ++k) {
    alert([cubes[0][i],cubes[1][j],cubes[2][k]]);
}