Here is the Math.max code in Chrome V8 engine.
function MathMax(arg1, arg2) { // length == 2
var length = %_ArgumentsLength();
if (length == 2) {
arg1 = TO_NUMBER(arg1);
arg2 = TO_NUMBER(arg2);
if (arg2 > arg1) return arg2;
if (arg1 > arg2) return arg1;
if (arg1 == arg2) {
// Make sure -0 is considered less than +0.
return (arg1 === 0 && %_IsMinusZero(arg1)) ? arg2 : arg1;
}
// All comparisons failed, one of the arguments must be NaN.
return NaN;
}
var r = -INFINITY;
for (var i = 0; i < length; i++) {
var n = %_Arguments(i);
n = TO_NUMBER(n);
// Make sure +0 is considered greater than -0.
if (NUMBER_IS_NAN(n) || n > r || (r === 0 && n === 0 && %_IsMinusZero(r))) {
r = n;
}
}
return r;
}
Here is the repository.
Answer from Charlie on Stack OverflowVideos
Here is the Math.max code in Chrome V8 engine.
function MathMax(arg1, arg2) { // length == 2
var length = %_ArgumentsLength();
if (length == 2) {
arg1 = TO_NUMBER(arg1);
arg2 = TO_NUMBER(arg2);
if (arg2 > arg1) return arg2;
if (arg1 > arg2) return arg1;
if (arg1 == arg2) {
// Make sure -0 is considered less than +0.
return (arg1 === 0 && %_IsMinusZero(arg1)) ? arg2 : arg1;
}
// All comparisons failed, one of the arguments must be NaN.
return NaN;
}
var r = -INFINITY;
for (var i = 0; i < length; i++) {
var n = %_Arguments(i);
n = TO_NUMBER(n);
// Make sure +0 is considered greater than -0.
if (NUMBER_IS_NAN(n) || n > r || (r === 0 && n === 0 && %_IsMinusZero(r))) {
r = n;
}
}
return r;
}
Here is the repository.
Below is how to implement the functions if Math.min() and Math.max() did not exist.
Functions have an arguments object, which you can iterate through to get its values.
It's important to note that Math.min() with no arguments returns Infinity, and Math.max() with no arguments returns -Infinity.
function min() {
var result= Infinity;
for(var i in arguments) {
if(arguments[i] < result) {
result = arguments[i];
}
}
return result;
}
function max() {
var result= -Infinity;
for(var i in arguments) {
if(arguments[i] > result) {
result = arguments[i];
}
}
return result;
}
//Tests
console.log(min(5,3,-2,4,14)); //-2
console.log(Math.min(5,3,-2,4,14)); //-2
console.log(max(5,3,-2,4,14)); //14
console.log(Math.max(5,3,-2,4,14)); //14
console.log(min()); //Infinity
console.log(Math.min()); //Infinity
console.log(max()); //-Infinity
console.log(Math.max()); //-Infinity
I'm trying to get the maximum value in an array. What's the correct syntax to do this?
Alternative, is there a way to compare different variables and get the name of the variable with the highest value? Like
var memory = 10 var cores = 20 var level = 200 var node = 5 -> return "level"
Taking the maximal number amongst the parameters.
$\max\{x_1,x_2\} = \cases{x_1, \text{if }x_1 > x_2\\x_2, \text{otherwise}}$
You can define like that the maximum of any finitely many elements.
When the parameters are an infinite set of values, then it is implied that one of them is maximal (namely that there is a greatest one, unlike the set where there is no greatest element)
In this case, I can also think of as a function in
:
The result is essentially "cut off" at
.