Use Math.round() :

Math.round(num * 100) / 100

Or to be more specific and to ensure things like 1.005 round correctly, use Number.EPSILON :

Math.round((num + Number.EPSILON) * 100) / 100

NOTE - See Edit 4 if 3 digit precision is important

var discount = (price / listprice).toFixed(2);

toFixed will round up or down for you depending on the values beyond 2 decimals.

Example: http://jsfiddle.net/calder12/tv9HY/

Documentation: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Number/toFixed

Edit - As mentioned by others this converts the result to a string. To avoid this:

var discount = +((price / listprice).toFixed(2));

Edit 2- As also mentioned in the comments this function fails in some precision, in the case of 1.005 for example it will return 1.00 instead of 1.01. If accuracy to this degree is important I've found this answer: https://stackoverflow.com/a/32605063/1726511 Which seems to work well with all the tests I've tried.

There is one minor modification required though, the function in the answer linked above returns whole numbers when it rounds to one, so for example 99.004 will return 99 instead of 99.00 which isn't ideal for displaying prices.

Edit 3 - Seems having the toFixed on the actual return was STILL screwing up some numbers, this final edit appears to work. Geez so many reworks!

var discount = roundTo((price / listprice), 2);

function roundTo(n, digits) {
  if (digits === undefined) {
    digits = 0;
  }

  var multiplicator = Math.pow(10, digits);
  n = parseFloat((n * multiplicator).toFixed(11));
  var test =(Math.round(n) / multiplicator);
  return +(test.toFixed(digits));
}

See Fiddle example here: https://jsfiddle.net/calder12/3Lbhfy5s/

Edit 4 - You guys are killing me. Edit 3 fails on negative numbers, without digging into why it's just easier to deal with turning a negative number positive before doing the rounding, then turning it back before returning the result.

function roundTo(n, digits) {
    var negative = false;
    if (digits === undefined) {
        digits = 0;
    }
    if (n < 0) {
        negative = true;
        n = n * -1;
    }
    var multiplicator = Math.pow(10, digits);
    n = parseFloat((n * multiplicator).toFixed(11));
    n = (Math.round(n) / multiplicator).toFixed(digits);
    if (negative) {
        n = (n * -1).toFixed(digits);
    }
    return n;
}

Fiddle: https://jsfiddle.net/3Lbhfy5s/79/

Well, they are two different functions, with two different uses. Math.floor() always rounds down to the nearest integer, while Math.round() will round up or down depending on what side of .5 the number falls on. So, the basic answer is that you use which one gets the result you expect.

When it comes to generating random numbers though, Math.floor() has a more even distribution than Math.round(). If you want to generate a random number between 0 and 2, take the following examples:

Math.floor(Math.random() * 3). Here, 0-0.999999 will give you 0, 1.0 to 1.999999 will give you 1, and 2.0 to 2.999999 will give you 2. Every number has a 33% chance of being the result.

Math.round(Math.random() * 2). Here, 0-0.499999 will give you 0, 0.5 to 1.499999 will give you 1, and 1.5 to 1.999999 will give you 2. Note that the range of numbers that lead to a 1 is twice as big as those that lead to 0 or 1. That is 25% chance of 0, 50% chance of 1, and 25% chance of 2.