Hi Carolyn, All you need do is change the colormap line to colormap(sort(Color, 'descend')); but make sure that you have cleared your variables first. With your previous command, Matlab creates a variable named 'colormap' and you do not want that. The forgoing method works, but you get a pretty ugly colorbar with four sections of constant color. For a nicer colorbar you can make a more continuous version of the colormap, such as x=[1,2,3,4]; y=[5,6,7,8]; sz = 100; N = 64; % or whatever Color1 = [ones(N,1),(N-1:-1:0)'/(N-1),zeros(N,1)]; colormap(Color1) s=scatter(x,y,sz,y,'filled'); colorbar This also gives you the opportunity to put not a matrix of rgb values into the scatter 'C' input as you did, but but rather to make C a vector of the same length as x and y. Then the collection of C vector values is mapped into the entire colormap from bottom to top. As you see, the y values were mapped to colors in the code above. That idea may not apply directly in your case with the circular plot, but you can make a C vector with appropriate values that map into the colormap. Answer from David Goodmanson on mathworks.com