ts = squeeze(YourArray(SomeRowNumber, SomeColumnNumber, :)); swappedArray = permute(YourArray, [2 1 3]);

I can think of two answers:

use the surface function on a 3D line like this:

color=1:length(Data(:,1));

surface([Data(:,1);Data(:,1)],[Data(:,2);Data(:,2)][Data(:,3);Data(:,3)],[color ;color],...
    'facecol','no','edgecol','interp');

this is a very nice trick, but it plots a line.

If you want to plot points, you can define an RGB color and plot single points with hold on like this:

hold on

for i=1:length(Data(:,1)) 

    plot3(Data(i,1),Data(i,2),Data(i,3),'Color',[(i/100*255)/255 0/255 (255-(i/100*255))/255],'LineWidth',2)

end    

shg

In order to plot 2D timeseries in a detached style in a 3D plot you can plot in the x-z-plane setting y as a vector containing constant values. So the resulting x-z curves will be detached in y-direction: n=5; % matrix containing the time information 1:5 for each column x=repmat((1:n)',1,n) % matrix containing the constant y offset per column y=x' % data matrix containing the data series as columns z=magic(n) % plot the data plot3(x,y,z,'linewidth',2,'marker','o') grid on xlabel('time') ylabel('data series')

Aradhya - everytime you call plot3 you are creating a new plot (graphics) object and the previous one is deleted. Perhaps that is why you are not seeing all of the data being plotted (if I understand your question correctly). Rather than using a loop to plot the data, just do it all at once plot3( x_accel(1:999), y_accel(1:999), z_accel(1:999)) Else if you want to plot each point (with perhaps a pause between each one), then you will want to create one plot object and update that on each iteration of your loop hPlot = plot3(x_accel(1), y_accel(1), z_accel(1)); for k = 2:1000-1 pause(0.5); xdata = [get(hPlot, 'XData') ; x_accel(k)]; ydata = [get(hPlot, 'YData') ; y_accel(k)]; zdata = [get(hPlot, 'ZData') ; z_accel(k)]; set(hPlot, 'XData', xdata, 'YData', ydata, 'ZData', zdata); end I haven't tested the above, but it should work something like that.

So your matrix is of size 11X14X60 (60 being the number of time steps); You may use for i = 1:60 surf(yourmatrix(:,:,i)) drawnow end

The type of plot you are trying to make may be difficult to visualize well. I can give you two suggestions: one is what you want, and one is what you should probably do instead...

Plotting 4-D data:

In order to do this, you will have to plot a series of x,y,t points and somehow represent the error value e at each point. You could do this by changing the color or size of the point. In this example, I'll plot a sphere at each point with a diameter that varies based on the error (a diameter of 1 equates to the maximum expected error). The color represents the time. I'll be using the sample data you added to the question (formatted as a 5-by-4 matrix with the columns containing the x, y, t, and e data):

data = [4 5 2 45; 4 5 6 54; 7 8 2 32; 7 8 9 98; 7 8 1 121];
[x, y, z] = sphere;  % Coordinate data for sphere
MAX_ERROR = 121;     % Maximum expected error
for i = 1:size(data, 1)
  c = 0.5*data(i, 4)/MAX_ERROR;  % Scale factor for sphere
  X = x.*c+data(i, 1);           % New X coordinates for sphere
  Y = y.*c+data(i, 2);           % New Y coordinates for sphere
  Z = z.*c+data(i, 3);           % New Z coordinates for sphere
  surface(X, Y, Z, 'EdgeColor', 'none');  % Plot sphere
  hold on
end
grid on
axis equal
view(-27, 16);
xlabel('x');
ylabel('y');
zlabel('t');

And here's what it would look like:

The problem: Although the plot looks kind of interesting, it's not very intuitive. Also, plotting lots of points in this way will get cluttered and it will be hard to see them all well.

More intuitive 3-D plot:

It may be better to instead make a 3-D plot of the data, since it may be easier to interpret. Here, the x-axis represents the iteration number and the y-axis represents each individual network:

plot3(1:2, [1 1], [2 45; 6 54]);           % Plot data for network 4-5
hold on
plot3(1:3, [2 2 2], [2 32; 9 98; 1 121]);  % Plot data for network 7-8
xlabel('iteration number');
set(gca, 'YTick', [1 2], 'YTickLabel', {'network 4-5', 'network 7-8'})
grid on
legend('time', 'error')
view(-18, 30)

This produces a much clearer plot: