Looks like ' is Hermitian while .' is just transpose.

A = A'; or A = A.';

The quote ' is not the transpose operator, but the complex transposition. To be exact the tranpose operator is .' including the dot.

They produce the same result only for _real_ values. The ‘regular’ transpose operator *|(')|* produces a _complex-conjugate_ transpose for complex numbers. With the dot operator *|(.')|* it produces the transpose without performing the complex-conjugate operation. *_Note_:* This is the only operation (that I am aware of) where the dot-operator does not signify element-wise operations, as it does with multiplication, division, and exponentiation.

The ability to transpose a dataset or table using the transpose operator (') is not available in MATLAB R2013b, however this is possible using a combination of other commands. For datasets, you can use a combination of 'dataset2cell' and 'cell2dataset' to convert the dataset into a cell array, transpose the cell array, then translate back into a dataset: >> Xc = dataset2cell(X) Xc = 'ObsNames' 'a' 'b' 'c' [1] [100] 'd' [2] [200] >> Xt = cell2dataset(Xc','ReadObsNames',true) Xt = c d a 1 2 b 100 200 For tables, you can use a combination of 'table2cell' and 'cell2table': >> Xc = table2cell(X) Xc = [1] [100] [2] [200] >> Xt = cell2table(Xc','RowNames',X.Properties.VariableNames,'VariableNames',X.Properties.RowNames) Xt = c d ___ ___ a 1 2 b 100 200 As of MATLAB R2018a, you can also use the ROW2VARS function:

Take the first column of the original matrix.

This is an ill-posed problem or something is missing from the problem statement. There are various ways to accomplish a transpose via indexing or permute etc as has already been pointed out. None of these involve the reshape function and as Walter points out reshape never alters the internal memory order (which is required for a general matrix transpose) so how the heck is reshape supposed to be involved in this in the first place?