You should try this code:

n = int(input("number of boats:"))
mylist = []
for _ in range(n):            # Taking n lines as input and add into mylist
    mylist.extend(list(map(int, input().rstrip().split())))
print("mylist is:", mylist)

Output as:

number of boats:3
23 56
36 48
46 97
mylist is: [23, 56, 36, 48, 46, 97]

(a) When the input value is 5, the output of the program is 2. This is because the program sums up all even numbers from 1 to 4 (inclusive), which are 2 and 4, and ignores all odd numbers.(b) When the input value is 0, the program does not execute the for loop because the range (1, N) will be an empty sequence. Therefore, the output will be 0, which is the initial value of the "sum" variable before the loop starts.Python program in more detail.The program takes an input from the user using the "input" function, which prompts the user to enter a value for N. This value is then stored in the variable "N" as an integer after being converted from a string using the "int" function.The program then initializes two variables: "i" and "sum". The variable "i" is set to 1, and the variable "sum" is set to 0.The program then enters a for loop that will iterate from 1 up to (but not including) the value of "N". During each iteration, the program first checks if the current value of "i" is even, by using the modulo operator (%), which returns the remainder of a division operation. If the remainder is 0, that means the number is even, so the program adds the value of "i" to the "sum" variable. If the remainder is not 0, then the number is odd, and the program moves on to the next iteration of the loop without modifying the "sum" variable.Finally, after the loop has finished executing, the program prints out the value of the "sum" variable, which should contain the sum of all even numbers between 1 and N-1 (inclusive), as the range function used in the loop has an upper limit of N exclusive.In case of input value being 5, the program iterates through the loop with the values of i as 1, 2, 3, and 4. The only even numbers in this range are 2 and 4, so the program adds these numbers to the "sum" variable. Therefore, the output is 2 + 4 = 6.In case of input value being 0, the range function in the loop will not include any numbers, so the loop will not execute at all. As a result, the value of "sum" will remain 0, and the program will print out this value as the output.To know more: -https://brainly.in/question/40155872?referrer=searchResults https://brainly.in/question/21067977?referrer=searchResults #SPJ1

It seems there are a couple of syntax errors in your code. Let me correct them:pythonCopy codeN = int(input("Enter the number:"))for i in range(1, N + 1):    for j in range(1, i + 1):        print(j, end=" ")    print("")Now, let's understand what this code does. It takes an input from the user and then prints a pattern of numbers in the following format:pythonCopy code1 1 2 1 2 3 1 2 3 4 ...For instance, if the user enters 5, the output will be:Copy code1 1 2 1 2 3 1 2 3 4 1 2 3 4 5 Each line contains numbers from 1 to the respective line number.Explanation: pls mark me as the brainliest, i just need one to go to genius

This is a Python program that computes the sum of a series of numbers. Here is a line-by-line explanation of what the program does:N=int(input("Enter a value of n:"))This line prompts the user to enter a value of n, and then stores that value as an integer in the variable N.s=0.0This line initializes a variable s to 0.0, which will be used to store the sum of the series.for i in range(1, n+1):This line sets up a for loop that iterates over the values of i from 1 to n. The range() function generates a sequence of numbers from the first argument (1) up to but not including the second argument (n+1).a = float(i**i)/iThis line calculates the value of the current term of the series, which is i raised to the power of i, divided by i. The float() function is used to convert the result to a floating-point number.s=s+aThis line adds the current term to the running total of the sum, which is stored in the variable s.print("The sum of the series is", s)This line prints out the final result, which is the sum of the series, to the console. The print() function is used to display a message along with the value of the variable s.

Hi, Try this code and it will help pass both answers import java.util.Scanner; public class Program { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int days = scanner.nextInt(); int daysToSeconds = days * 24 * 60 *60; System.out.println(daysToSeconds); } } It works for me, let me know if it works also with you?

Since Python 3, input returns a string which you have to explicitly convert to int, like this

x = int(input("Enter a number: "))
y = int(input("Enter a number: "))

You can accept numbers of any base like this

>>> data = int(input("Enter a number: "), 8)
Enter a number: 777
>>> data
511
>>> data = int(input("Enter a number: "), 16)
Enter a number: FFFF
>>> data
65535
>>> data = int(input("Enter a number: "), 2)
Enter a number: 10101010101
>>> data
1365

The second parameter tells it the base of the number and then internally it understands and converts it. If the entered data is wrong it will throw a ValueError.

>>> data = int(input("Enter a number: "), 2)
Enter a number: 1234
Traceback (most recent call last):
  File "<input>", line 1, in <module>
ValueError: invalid literal for int() with base 2: '1234'

For values that can have a fractional component, the type would be float rather than int:

x = float(input("Enter a number:"))

Differences between Python 2 and 3

Summary

• Python 2's input function evaluated the received data, converting it to an integer implicitly (read the next section to understand the implication), but Python 3's input function does not do that anymore.
• Python 2's equivalent of Python 3's input is the raw_input function.

Python 2.x

There were two functions to get user input, called input and raw_input. The difference between them is, raw_input doesn't evaluate the data and returns as it is, in string form. But, input will evaluate whatever you entered and the result of evaluation will be returned. For example,

>>> import sys
>>> sys.version
'2.7.6 (default, Mar 22 2014, 22:59:56) \n[GCC 4.8.2]'
>>> data = input("Enter a number: ")
Enter a number: 5 + 17
>>> data, type(data)
(22, <type 'int'>)

The data 5 + 17 is evaluated and the result is 22. When it evaluates the expression 5 + 17, it detects that you are adding two numbers and so the result will also be of the same int type. So, the type conversion is done for free, and 22 is returned as the result of the input and stored in the data variable. You can think of input as the raw_input composed with an eval call.

>>> data = eval(raw_input("Enter a number: "))
Enter a number: 5 + 17
>>> data, type(data)
(22, <type 'int'>)

Note: You should be careful when you are using input in Python 2.x. I explained why one should be careful when using it, in this answer.

But, raw_input doesn't evaluate the input and returns as it is, as a string.

>>> import sys
>>> sys.version
'2.7.6 (default, Mar 22 2014, 22:59:56) \n[GCC 4.8.2]'
>>> data = raw_input("Enter a number: ")
Enter a number: 5 + 17
>>> data, type(data)
('5 + 17', <type 'str'>)

Python 3.x

Python 3.x's input and Python 2.x's raw_input are similar and raw_input is not available in Python 3.x.

>>> import sys
>>> sys.version
'3.4.0 (default, Apr 11 2014, 13:05:11) \n[GCC 4.8.2]'
>>> data = input("Enter a number: ")
Enter a number: 5 + 17
>>> data, type(data)
('5 + 17', <class 'str'>)

Output:- 2 6