How do i get the length of the column in a nD array? example, i have a nD array called a. when i print a.shape, it returns (1,21). I want to do a for loop, in the range of the column size of the... More on stackoverflow.com

Copydef size(a, axis=None): """ Return the number of elements along a given axis. Parameters ---------- a : array_like Input data. axis : int, optional Axis along which the elements are counted. By default, give the total number of elements. Returns ------- element_count : int Number of elements ... More on stackoverflow.com

A numpy array of shape (100,) has one dimension, while an array of shape (100, 1) has two dimensions. The difference is also immediately observable: >>> import numpy as np >>> arr_1 = np.random.randint(1, 10, size=(5,)) >>> print(arr_1.ndim) 1 >>> print(arr_1) [7 9 2 3 3] >>> arr_2 = np.random.randint(1, 10, size=(5,1)) >>> print(arr_2.ndim) 2 >>> print(arr_2) [[5] [4] [4] [2] [4]] More on reddit.com

This is wrong because each row references the same array. If you change one value in the array, it will be changed for all rows. You should put the new double[3] statement directly inside the loop. Alternatively, if you're dealing with matrices, you should use n-dimensional arrays instead: - var bigDaddy = new double[1001, 3] this will create a 1001x3 matrix filled with zeroes by default - var bigDaddy = new double[3003] this will create a 3003 sized array filled with zeroes which you can then navigate with the % operator and use Span for operations for a performance boost More on reddit.com