Generally your idea of trying to apply astype to each column is fine.
In [590]: X[:,0].astype(int)
Out[590]: array([1, 2, 3, 4, 5])
But you have to collect the results in a separate list. You can't just put them back in X. That list can then be concatenated.
In [601]: numlist=[]; obj_ind=[]
In [602]: for ind in range(X.shape[1]):
.....: try:
.....: x = X[:,ind].astype(np.float32)
.....: numlist.append(x)
.....: except:
.....: obj_ind.append(ind)
In [603]: numlist
Out[603]: [array([ 3., 4., 5., 6., 7.], dtype=float32)]
In [604]: np.column_stack(numlist)
Out[604]:
array([[ 3.],
[ 4.],
[ 5.],
[ 6.],
[ 7.]], dtype=float32)
In [606]: obj_ind
Out[606]: [1]
X is a numpy array with dtype object:
In [582]: X
Out[582]:
array([[1, 'A'],
[2, 'A'],
[3, 'C'],
[4, 'D'],
[5, 'B']], dtype=object)
You could use the same conversion logic to create a structured array with a mix of int and object fields.
In [616]: ytype=[]
In [617]: for ind in range(X.shape[1]):
try:
x = X[:,ind].astype(np.float32)
ytype.append('i4')
except:
ytype.append('O')
In [618]: ytype
Out[618]: ['i4', 'O']
In [620]: Y=np.zeros(X.shape[0],dtype=','.join(ytype))
In [621]: for i in range(X.shape[1]):
Y[Y.dtype.names[i]] = X[:,i]
In [622]: Y
Out[622]:
array([(3, 'A'), (4, 'A'), (5, 'C'), (6, 'D'), (7, 'B')],
dtype=[('f0', '<i4'), ('f1', 'O')])
Y['f0'] gives the the numeric field.
python - changing numpy array to float - Stack Overflow
python - numpy astype from float32 to float16 - Stack Overflow
print(np.array([np.nan]).astype(int).astype(float)).
ENH: Numpy arrays of floats converted to string using astype(str) have unexpected behaviour
Generally your idea of trying to apply astype to each column is fine.
In [590]: X[:,0].astype(int)
Out[590]: array([1, 2, 3, 4, 5])
But you have to collect the results in a separate list. You can't just put them back in X. That list can then be concatenated.
In [601]: numlist=[]; obj_ind=[]
In [602]: for ind in range(X.shape[1]):
.....: try:
.....: x = X[:,ind].astype(np.float32)
.....: numlist.append(x)
.....: except:
.....: obj_ind.append(ind)
In [603]: numlist
Out[603]: [array([ 3., 4., 5., 6., 7.], dtype=float32)]
In [604]: np.column_stack(numlist)
Out[604]:
array([[ 3.],
[ 4.],
[ 5.],
[ 6.],
[ 7.]], dtype=float32)
In [606]: obj_ind
Out[606]: [1]
X is a numpy array with dtype object:
In [582]: X
Out[582]:
array([[1, 'A'],
[2, 'A'],
[3, 'C'],
[4, 'D'],
[5, 'B']], dtype=object)
You could use the same conversion logic to create a structured array with a mix of int and object fields.
In [616]: ytype=[]
In [617]: for ind in range(X.shape[1]):
try:
x = X[:,ind].astype(np.float32)
ytype.append('i4')
except:
ytype.append('O')
In [618]: ytype
Out[618]: ['i4', 'O']
In [620]: Y=np.zeros(X.shape[0],dtype=','.join(ytype))
In [621]: for i in range(X.shape[1]):
Y[Y.dtype.names[i]] = X[:,i]
In [622]: Y
Out[622]:
array([(3, 'A'), (4, 'A'), (5, 'C'), (6, 'D'), (7, 'B')],
dtype=[('f0', '<i4'), ('f1', 'O')])
Y['f0'] gives the the numeric field.
I think this might help
def func(x):
a = None
try:
a = x.astype(float)
except:
# x.name represents the current index value
# which is column name in this case
obj.append(x.name)
a = x
return a
obj = []
new_df = df.apply(func, axis=0)
This will keep the object columns as such which you can use later.
Note: While using pandas.DataFrame avoid using iteration using loop as this much slower than performing the same operation using apply.
The IEEE 754-2008 16-bit base 2 format, aka binary16, doesn't give you a lot of precision. What do you expect from 16 bits? :) 1 bit is the sign bit, 5 bits are used for the exponent, and that leaves 10 bits to store the normalised 11 bit mantissa, so anything > 2**11 == 2048 has to be quantized.
According to Wikipedia, integers between 4097 and 8192 round to a multiple of 4, and integers between 8193 and 16384 round to a multiple of 8.
Tensorflow requires float16 and produces an error for float32. You can use what was suggested by Reti43:
np.float16(a)
Out[102]: array([8192.], dtype=float16)
I'm surprised that a useless reply has been upvoted so high. I know that moderators request to mark as the best answer the one which was upvoted the highest, but an question author is not obliged to do this. There are a number of people who just gather points here, and do not care about actually replying to a request. They might upvote themselves under different names.
Can someone explain what does it mean.