NumPy
numpy.org › doc › stable › reference › generated › numpy.bincount.html
numpy.bincount — NumPy v2.5 Manual
>>> import numpy as np >>> np.bincount(np.arange(5)) array([1, 1, 1, 1, 1]) >>> np.bincount(np.array([0, 1, 1, 3, 2, 1, 7])) array([1, 3, 1, 1, 0, 0, 0, 1])
NumPy
numpy.org › doc › 2.1 › reference › generated › numpy.bincount.html
numpy.bincount — NumPy v2.1 Manual
>>> import numpy as np >>> np.bincount(np.arange(5)) array([1, 1, 1, 1, 1]) >>> np.bincount(np.array([0, 1, 1, 3, 2, 1, 7])) array([1, 3, 1, 1, 0, 0, 0, 1])
NumPy
numpy.org › doc › 2.3 › reference › generated › numpy.bincount.html
numpy.bincount — NumPy v2.3 Manual
>>> import numpy as np >>> np.bincount(np.arange(5)) array([1, 1, 1, 1, 1]) >>> np.bincount(np.array([0, 1, 1, 3, 2, 1, 7])) array([1, 3, 1, 1, 0, 0, 0, 1])
Educative
educative.io › answers › what-is-numpybincount-in-python
What is numpy.bincount() in Python?
The bincount() method of the NumPy module is used to find the frequency of each element in a NumPy array of positive integers. The element’s index in the frequency array or bin is stored as the element’s count.
NumPy
numpy.org › devdocs › reference › generated › numpy.bincount.html
numpy.bincount — NumPy v2.6.dev0 Manual
>>> import numpy as np >>> np.bincount(np.arange(5)) array([1, 1, 1, 1, 1]) >>> np.bincount(np.array([0, 1, 1, 3, 2, 1, 7])) array([1, 3, 1, 1, 0, 0, 0, 1])
MindSpore
mindspore.cn › mindspore.numpy.bincount
mindspore.numpy.bincount | MindSpore 2.0.0-alpha documentation | MindSpore
mindspore.numpy.bincount · View page source · mindspore.numpy.bincount(x, weights=None, minlength=0, length=None)[source] · Count number of occurrences of each value in array of non-negative ints. The number of bins (of size 1) is one larger than the largest value in x.
University of Texas at Austin
het.as.utexas.edu › HET › Software › Numpy › reference › generated › numpy.bincount.html
numpy.bincount — NumPy v1.9 Manual
>>> x = np.array([0, 1, 1, 3, 2, 1, 7, 23]) >>> np.bincount(x).size == np.amax(x)+1 True
Intelpython
intelpython.github.io › dpnp › reference › generated › dpnp.bincount.html
dpnp.bincount - Data Parallel Extension for NumPy (dpnp) 0.21.0dev8 documentation
>>> x = np.array([0, 1, 1, 3, 2, 1, 7, 23]) >>> np.bincount(x).size == np.max(x) + 1 array(True)
NumPy
numpy.org › doc › 2.0 › reference › generated › numpy.bincount.html
numpy.bincount — NumPy v2.0 Manual
>>> x = np.array([0, 1, 1, 3, 2, 1, 7, 23]) >>> np.bincount(x).size == np.amax(x)+1 True
SciPy
docs.scipy.org › doc › numpy-1.15.0 › reference › generated › numpy.bincount.html
numpy.bincount — NumPy v1.15 Manual
>>> x = np.array([0, 1, 1, 3, 2, 1, 7, 23]) >>> np.bincount(x).size == np.amax(x)+1 True
NumPy
numpy.org › doc › 2.4 › reference › generated › numpy.bincount.html
numpy.bincount — NumPy v2.4 Manual
>>> import numpy as np >>> np.bincount(np.arange(5)) array([1, 1, 1, 1, 1]) >>> np.bincount(np.array([0, 1, 1, 3, 2, 1, 7])) array([1, 3, 1, 1, 0, 0, 0, 1])
SciPy
docs.scipy.org › doc › numpy-1.5.x › reference › generated › numpy.bincount.html
numpy.bincount — NumPy v1.5 Manual (DRAFT)
November 18, 2010 - >>> x = np.array([0, 1, 1, 3, 2, 1, 7, 23]) >>> np.bincount(x).size == np.amax(x)+1 True
Skytowner
skytowner.com › explore › numpy_bincount_method
NumPy | bincount method with Examples
Numpy's bincount(~) method computes the bin count (i.e. the number of values that fall in an interval) given an array of values. By default, the interval size of each bin is one, and so the number of bins is dependent on the range of the input values.
Top answer 1 of 3
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bincount returns the count of values in each bin from 0 to the largest value in the array i.e.
np.bincount(my_list) == [count(i) for i in range(0, max(my_list))]
== [count(0), count(1), ..., count(max(my_list))]
e.g.
np.bincount([0, 1, 2, 3, 4, 4, 6])
>>> array([1, 1, 1, 1, 2, 0, 1])
Note:
- absent numbers (e.g.
5above) return a count of0 - a
ValueErroris raised if the list contains negative numbers orNaN
2 of 3
21
Here's a graphic explanation of bincount() with and without weights:
