You can check the execution time to get clear picture of it
In [2]: import numpy as np
In [3]: A = np.array([[2, 2],[2, 2]])
In [7]: %timeit np.square(A)
1000000 loops, best of 3: 923 ns per loop
In [8]: %timeit A ** 2
1000000 loops, best of 3: 668 ns per loop
Answer from saimadhu.polamuri on Stack OverflowYou can check the execution time to get clear picture of it
In [2]: import numpy as np
In [3]: A = np.array([[2, 2],[2, 2]])
In [7]: %timeit np.square(A)
1000000 loops, best of 3: 923 ns per loop
In [8]: %timeit A ** 2
1000000 loops, best of 3: 668 ns per loop
For most appliances, both will give you the same results.
Generally the standard pythonic a*a or a**2 is faster than the numpy.square() or numpy.pow(), but the numpy functions are often more flexible and precise.
If you do calculations that need to be very accurate, stick to numpy and probably even use other datatypes float96.
For normal usage a**2 will do a good job and way faster job than numpy.
The guys in this thread gave some good examples to a similar questions.
The fastest way is to do a*a or a**2 or np.square(a) whereas np.power(a, 2) showed to be considerably slower.
np.power() allows you to use different exponents for each element if instead of 2 you pass another array of exponents. From the comments of @GarethRees I just learned that this function will give you different results than a**2 or a*a, which become important in cases where you have small tolerances.
I've timed some examples using NumPy 1.9.0 MKL 64 bit, and the results are shown below:
In [29]: a = np.random.random((1000, 1000))
In [30]: timeit a*a
100 loops, best of 3: 2.78 ms per loop
In [31]: timeit a**2
100 loops, best of 3: 2.77 ms per loop
In [32]: timeit np.power(a, 2)
10 loops, best of 3: 71.3 ms per loop
>>> import numpy
>>> print numpy.power.__doc__
power(x1, x2[, out])
First array elements raised to powers from second array, element-wise.
Raise each base in `x1` to the positionally-corresponding power in
`x2`. `x1` and `x2` must be broadcastable to the same shape.
Parameters
----------
x1 : array_like
The bases.
x2 : array_like
The exponents.
Returns
-------
y : ndarray
The bases in `x1` raised to the exponents in `x2`.
Examples
--------
Cube each element in a list.
>>> x1 = range(6)
>>> x1
[0, 1, 2, 3, 4, 5]
>>> np.power(x1, 3)
array([ 0, 1, 8, 27, 64, 125])
Raise the bases to different exponents.
>>> x2 = [1.0, 2.0, 3.0, 3.0, 2.0, 1.0]
>>> np.power(x1, x2)
array([ 0., 1., 8., 27., 16., 5.])
The effect of broadcasting.
>>> x2 = np.array([[1, 2, 3, 3, 2, 1], [1, 2, 3, 3, 2, 1]])
>>> x2
array([[1, 2, 3, 3, 2, 1],
[1, 2, 3, 3, 2, 1]])
>>> np.power(x1, x2)
array([[ 0, 1, 8, 27, 16, 5],
[ 0, 1, 8, 27, 16, 5]])
>>>
Precision
As per the discussed observation on numerical precision as per @GarethRees objection in comments:
>>> a = numpy.ones( (3,3), dtype = numpy.float96 ) # yields exact output
>>> a[0,0] = 0.46002700024131926
>>> a
array([[ 0.460027, 1.0, 1.0],
[ 1.0, 1.0, 1.0],
[ 1.0, 1.0, 1.0]], dtype=float96)
>>> b = numpy.power( a, 2 )
>>> b
array([[ 0.21162484, 1.0, 1.0],
[ 1.0, 1.0, 1.0],
[ 1.0, 1.0, 1.0]], dtype=float96)
>>> a.dtype
dtype('float96')
>>> a[0,0]
0.46002700024131926
>>> b[0,0]
0.21162484095102677
>>> print b[0,0]
0.211624840951
>>> print a[0,0]
0.460027000241
Performance
>>> c = numpy.random.random( ( 1000, 1000 ) ).astype( numpy.float96 )
>>> import zmq
>>> aClk = zmq.Stopwatch()
>>> aClk.start(), c**2, aClk.stop()
(None, array([[ ...]], dtype=float96), 5663L) # 5 663 [usec]
>>> aClk.start(), c*c, aClk.stop()
(None, array([[ ...]], dtype=float96), 6395L) # 6 395 [usec]
>>> aClk.start(), c[:,:]*c[:,:], aClk.stop()
(None, array([[ ...]], dtype=float96), 6930L) # 6 930 [usec]
>>> aClk.start(), c[:,:]**2, aClk.stop()
(None, array([[ ...]], dtype=float96), 6285L) # 6 285 [usec]
>>> aClk.start(), numpy.power( c, 2 ), aClk.stop()
(None, array([[ ... ]], dtype=float96), 384515L) # 384 515 [usec]