The tolist() method should do what you want. If you have a numpy array, just call tolist():
In [17]: a
Out[17]:
array([ 0. , 0.14285714, 0.28571429, 0.42857143, 0.57142857,
0.71428571, 0.85714286, 1. , 1.14285714, 1.28571429,
1.42857143, 1.57142857, 1.71428571, 1.85714286, 2. ])
In [18]: a.dtype
Out[18]: dtype('float64')
In [19]: b = a.tolist()
In [20]: b
Out[20]:
[0.0,
0.14285714285714285,
0.2857142857142857,
0.42857142857142855,
0.5714285714285714,
0.7142857142857142,
0.8571428571428571,
1.0,
1.1428571428571428,
1.2857142857142856,
1.4285714285714284,
1.5714285714285714,
1.7142857142857142,
1.857142857142857,
2.0]
In [21]: type(b)
Out[21]: list
In [22]: type(b[0])
Out[22]: float
If, in fact, you really have python list of numpy.float64 objects, then @Alexander's answer is great, or you could convert the list to an array and then use the tolist() method. E.g.
In [46]: c
Out[46]:
[0.0,
0.33333333333333331,
0.66666666666666663,
1.0,
1.3333333333333333,
1.6666666666666665,
2.0]
In [47]: type(c)
Out[47]: list
In [48]: type(c[0])
Out[48]: numpy.float64
@Alexander's suggestion, a list comprehension:
In [49]: [float(v) for v in c]
Out[49]:
[0.0,
0.3333333333333333,
0.6666666666666666,
1.0,
1.3333333333333333,
1.6666666666666665,
2.0]
Or, convert to an array and then use the tolist() method.
In [50]: np.array(c).tolist()
Out[50]:
[0.0,
0.3333333333333333,
0.6666666666666666,
1.0,
1.3333333333333333,
1.6666666666666665,
2.0]
If you are concerned with the speed, here's a comparison. The input, x, is a python list of numpy.float64 objects:
In [8]: type(x)
Out[8]: list
In [9]: len(x)
Out[9]: 1000
In [10]: type(x[0])
Out[10]: numpy.float64
Timing for the list comprehension:
In [11]: %timeit list1 = [float(v) for v in x]
10000 loops, best of 3: 109 µs per loop
Timing for conversion to numpy array and then tolist():
In [12]: %timeit list2 = np.array(x).tolist()
10000 loops, best of 3: 70.5 µs per loop
So it is faster to convert the list to an array and then call tolist().
The tolist() method should do what you want. If you have a numpy array, just call tolist():
In [17]: a
Out[17]:
array([ 0. , 0.14285714, 0.28571429, 0.42857143, 0.57142857,
0.71428571, 0.85714286, 1. , 1.14285714, 1.28571429,
1.42857143, 1.57142857, 1.71428571, 1.85714286, 2. ])
In [18]: a.dtype
Out[18]: dtype('float64')
In [19]: b = a.tolist()
In [20]: b
Out[20]:
[0.0,
0.14285714285714285,
0.2857142857142857,
0.42857142857142855,
0.5714285714285714,
0.7142857142857142,
0.8571428571428571,
1.0,
1.1428571428571428,
1.2857142857142856,
1.4285714285714284,
1.5714285714285714,
1.7142857142857142,
1.857142857142857,
2.0]
In [21]: type(b)
Out[21]: list
In [22]: type(b[0])
Out[22]: float
If, in fact, you really have python list of numpy.float64 objects, then @Alexander's answer is great, or you could convert the list to an array and then use the tolist() method. E.g.
In [46]: c
Out[46]:
[0.0,
0.33333333333333331,
0.66666666666666663,
1.0,
1.3333333333333333,
1.6666666666666665,
2.0]
In [47]: type(c)
Out[47]: list
In [48]: type(c[0])
Out[48]: numpy.float64
@Alexander's suggestion, a list comprehension:
In [49]: [float(v) for v in c]
Out[49]:
[0.0,
0.3333333333333333,
0.6666666666666666,
1.0,
1.3333333333333333,
1.6666666666666665,
2.0]
Or, convert to an array and then use the tolist() method.
In [50]: np.array(c).tolist()
Out[50]:
[0.0,
0.3333333333333333,
0.6666666666666666,
1.0,
1.3333333333333333,
1.6666666666666665,
2.0]
If you are concerned with the speed, here's a comparison. The input, x, is a python list of numpy.float64 objects:
In [8]: type(x)
Out[8]: list
In [9]: len(x)
Out[9]: 1000
In [10]: type(x[0])
Out[10]: numpy.float64
Timing for the list comprehension:
In [11]: %timeit list1 = [float(v) for v in x]
10000 loops, best of 3: 109 µs per loop
Timing for conversion to numpy array and then tolist():
In [12]: %timeit list2 = np.array(x).tolist()
10000 loops, best of 3: 70.5 µs per loop
So it is faster to convert the list to an array and then call tolist().
You could use a list comprehension:
floats = [float(np_float) for np_float in np_float_list]
numpy.float64 is not converted to float
Preventing numpy from converting float type to numpy.int64 type
`np.float64` is not accepted as `float` under static type checks
python - Convert numpy array type and values from Float64 to Float32 - Stack Overflow
Videos
Yes, actually when you use Python's native float to specify the dtype for an array , numpy converts it to float64. As given in documentation -
Note that, above, we use the Python float object as a dtype. NumPy knows that
intrefers tonp.int_,boolmeansnp.bool_, thatfloatisnp.float_andcomplexisnp.complex_. The other data-types do not have Python equivalents.
And -
float_ - Shorthand for float64.
This is why even though you use float to convert the whole array to float , it still uses np.float64.
According to the requirement from the other question , the best solution would be converting to normal float object after taking each scalar value as -
float(new_array[0])
A solution that I could think of is to create a subclass for float and use that for casting (though to me it looks bad). But I would prefer the previous solution over this if possible. Example -
In [20]: import numpy as np
In [21]: na = np.array([1., 2., 3.])
In [22]: na = np.array([1., 2., 3., np.inf, np.inf])
In [23]: type(na[-1])
Out[23]: numpy.float64
In [24]: na[-1] - na[-2]
C:\Anaconda3\Scripts\ipython-script.py:1: RuntimeWarning: invalid value encountered in double_scalars
if __name__ == '__main__':
Out[24]: nan
In [25]: class x(float):
....: pass
....:
In [26]: na_new = na.astype(x)
In [28]: type(na_new[-1])
Out[28]: float #No idea why its showing float, I would have thought it would show '__main__.x' .
In [29]: na_new[-1] - na_new[-2]
Out[29]: nan
In [30]: na_new
Out[30]: array([1.0, 2.0, 3.0, inf, inf], dtype=object)
You can create an anonymous type float like this
>>> new_array = my_array.astype(type('float', (float,), {}))
>>> type(new_array[0])
<type 'float'>
So I have 3-tuple of only float types, let's call it eta.
I also have a class attribute eta_hat which is initialized as numpy.array( [ [0], [0], [0] ] ), the idea it being a column vector.
My goal is to make the values of eta_hat the values of eta. However, the piece of code
self.eta_hat[0][0], self.eta_hat[1][0], self.eta_hat[2][0] = eta[0], eta[1], eta[2]
converts eta[x] from float to numpy.int64 in self.eta_hat[x][0]. I do not understand how numpy handles these, and would love an explenation on how I could fix this problem. Thanks!
The problem is that you do not do any type conversion of the numpy array. You calculate a float32 variable and put it as an entry into a float64 numpy array. numpy then converts it properly back to float64
Try someting like this:
a = np.zeros(4,dtype="float64")
print a.dtype
print type(a[0])
a = np.float32(a)
print a.dtype
print type(a[0])
The output (tested with python 2.7)
float64
<type 'numpy.float64'>
float32
<type 'numpy.float32'>
a is in your case the array tree.tree_.threshold
Actually i tried hard but not able to do as the 'sklearn.tree._tree.Tree' objects is not writable.
It is causing a precision issue while generating a PMML file, so i raised a bug over there and they gave an updated solution for it by not converting it in to the Float64 internally.
For more info, you can follow this link: Precision Issue