You can use to_numeric which will give you a float32

or np.float32(x)

then x.item() will give you python float

The tolist() method should do what you want. If you have a numpy array, just call tolist():

In [17]: a
Out[17]: 
array([ 0.        ,  0.14285714,  0.28571429,  0.42857143,  0.57142857,
        0.71428571,  0.85714286,  1.        ,  1.14285714,  1.28571429,
        1.42857143,  1.57142857,  1.71428571,  1.85714286,  2.        ])

In [18]: a.dtype
Out[18]: dtype('float64')

In [19]: b = a.tolist()

In [20]: b
Out[20]: 
[0.0,
 0.14285714285714285,
 0.2857142857142857,
 0.42857142857142855,
 0.5714285714285714,
 0.7142857142857142,
 0.8571428571428571,
 1.0,
 1.1428571428571428,
 1.2857142857142856,
 1.4285714285714284,
 1.5714285714285714,
 1.7142857142857142,
 1.857142857142857,
 2.0]

In [21]: type(b)
Out[21]: list

In [22]: type(b[0])
Out[22]: float

If, in fact, you really have python list of numpy.float64 objects, then @Alexander's answer is great, or you could convert the list to an array and then use the tolist() method. E.g.

In [46]: c
Out[46]: 
[0.0,
 0.33333333333333331,
 0.66666666666666663,
 1.0,
 1.3333333333333333,
 1.6666666666666665,
 2.0]

In [47]: type(c)
Out[47]: list

In [48]: type(c[0])
Out[48]: numpy.float64

@Alexander's suggestion, a list comprehension:

In [49]: [float(v) for v in c]
Out[49]: 
[0.0,
 0.3333333333333333,
 0.6666666666666666,
 1.0,
 1.3333333333333333,
 1.6666666666666665,
 2.0]

Or, convert to an array and then use the tolist() method.

In [50]: np.array(c).tolist()
Out[50]: 
[0.0,
 0.3333333333333333,
 0.6666666666666666,
 1.0,
 1.3333333333333333,
 1.6666666666666665,
 2.0]

If you are concerned with the speed, here's a comparison. The input, x, is a python list of numpy.float64 objects:

In [8]: type(x)
Out[8]: list

In [9]: len(x)
Out[9]: 1000

In [10]: type(x[0])
Out[10]: numpy.float64

Timing for the list comprehension:

In [11]: %timeit list1 = [float(v) for v in x]
10000 loops, best of 3: 109 µs per loop

Timing for conversion to numpy array and then tolist():

In [12]: %timeit list2 = np.array(x).tolist()
10000 loops, best of 3: 70.5 µs per loop

So it is faster to convert the list to an array and then call tolist().

This seems to be from the way that pandas is handling nans. When I set skipna=False in the sum method I get the numpy datatype

import pandas as pd
import numpy as np

type(pd.DataFrame({'col1':[.1,.2,.3,.4]}).col1.sum(skipna=True))
#float

type(pd.DataFrame({'col1':[.1,.2,.3,.4]}).col1.sum(skipna=False))
#numpy.float64

The sum method is calling nansum from pandas/core/nanops.py, which produces the same behaviours.

from pandas.core.nanops import nansum

type(sum(np.arange(10.0)))
# numpy.float64

type(nansum(np.arange(10.0)))
# float

Why nansum is converting from numpy.float64 to float, I couldn't tell you. I've looked at the nansum source code, but none of the functions it itself calls seem to be producing that change.

Can you try toarray

pd.DataFrame(A.toarray())

Use val.item() to convert most NumPy values to a native Python type:

import numpy as np

# for example, numpy.float32 -> python float
val = np.float32(0)
pyval = val.item()
print(type(pyval))         # <class 'float'>

# and similar...
type(np.float64(0).item()) # <class 'float'>
type(np.uint32(0).item())  # <class 'int'>
type(np.int16(0).item())   # <class 'int'>
type(np.cfloat(0).item())  # <class 'complex'>
type(np.datetime64(0, 'D').item())  # <class 'datetime.date'>
type(np.datetime64('2001-01-01 00:00:00').item())  # <class 'datetime.datetime'>
type(np.timedelta64(0, 'D').item()) # <class 'datetime.timedelta'>
...

(A related method np.asscalar(val) was deprecated with 1.16, and removed with 1.23).

For the curious, to build a table of conversions of NumPy array scalars for your system:

for name in dir(np):
    obj = getattr(np, name)
    if hasattr(obj, 'dtype'):
        try:
            if 'time' in name:
                npn = obj(0, 'D')
            else:
                npn = obj(0)
            nat = npn.item()
            print('{0} ({1!r}) -> {2}'.format(name, npn.dtype.char, type(nat)))
        except:
            pass

There are a few NumPy types that have no native Python equivalent on some systems, including: clongdouble, clongfloat, complex192, complex256, float128, longcomplex, longdouble and longfloat. These need to be converted to their nearest NumPy equivalent before using .item().

Solution for pandas 0.24+ for converting numeric with missing values:

df = pd.DataFrame({'column name':[7500000.0,7500000.0, np.nan]})
print (df['column name'])
0    7500000.0
1    7500000.0
2          NaN
Name: column name, dtype: float64

df['column name'] = df['column name'].astype(np.int64)

ValueError: Cannot convert non-finite values (NA or inf) to integer

#http://pandas.pydata.org/pandas-docs/stable/user_guide/integer_na.html
df['column name'] = df['column name'].astype('Int64')
print (df['column name'])
0    7500000
1    7500000
2        NaN
Name: column name, dtype: Int64

I think you need cast to numpy.int64:

df['column name'].astype(np.int64)

Sample:

df = pd.DataFrame({'column name':[7500000.0,7500000.0]})
print (df['column name'])
0    7500000.0
1    7500000.0
Name: column name, dtype: float64

df['column name'] = df['column name'].astype(np.int64)
#same as
#df['column name'] = df['column name'].astype(pd.np.int64)
print (df['column name'])
0    7500000
1    7500000
Name: column name, dtype: int64

If some NaNs in columns need replace them to some int (e.g. 0) by fillna, because type of NaN is float:

df = pd.DataFrame({'column name':[7500000.0,np.nan]})

df['column name'] = df['column name'].fillna(0).astype(np.int64)
print (df['column name'])
0    7500000
1          0
Name: column name, dtype: int64

Also check documentation - missing data casting rules

EDIT:

Convert values with NaNs is buggy:

df = pd.DataFrame({'column name':[7500000.0,np.nan]})

df['column name'] = df['column name'].values.astype(np.int64)
print (df['column name'])
0                7500000
1   -9223372036854775808
Name: column name, dtype: int64

Yes, actually when you use Python's native float to specify the dtype for an array , numpy converts it to float64. As given in documentation -

Note that, above, we use the Python float object as a dtype. NumPy knows that int refers to np.int_, bool means np.bool_ , that float is np.float_ and complex is np.complex_. The other data-types do not have Python equivalents.

And -

float_ - Shorthand for float64.

This is why even though you use float to convert the whole array to float , it still uses np.float64.

According to the requirement from the other question , the best solution would be converting to normal float object after taking each scalar value as -

float(new_array[0])

A solution that I could think of is to create a subclass for float and use that for casting (though to me it looks bad). But I would prefer the previous solution over this if possible. Example -

In [20]: import numpy as np

In [21]: na = np.array([1., 2., 3.])

In [22]: na = np.array([1., 2., 3., np.inf, np.inf])

In [23]: type(na[-1])
Out[23]: numpy.float64

In [24]: na[-1] - na[-2]
C:\Anaconda3\Scripts\ipython-script.py:1: RuntimeWarning: invalid value encountered in double_scalars
  if __name__ == '__main__':
Out[24]: nan

In [25]: class x(float):
   ....:     pass
   ....:

In [26]: na_new = na.astype(x)


In [28]: type(na_new[-1])
Out[28]: float                           #No idea why its showing float, I would have thought it would show '__main__.x' .

In [29]: na_new[-1] - na_new[-2]
Out[29]: nan

In [30]: na_new
Out[30]: array([1.0, 2.0, 3.0, inf, inf], dtype=object)

If you don't see the point (no data loss) you can manually downcast the column to a standard numpy type by passing the column values through a numpy array and changing its type, here: to numpy.float64 (which reconstructs also the index):

df[col_name] = df[col_name].values.astype(float)