Try with IntStream:
List<JSONObject> jsonObject = IntStream
.range(0, jsonArray.length())
.mapToObj(i -> jsonArray.getJSONObject(i))
.collect(Collectors.toList());
Top answer 1 of 4
26
Try with IntStream:
List<JSONObject> jsonObject = IntStream
.range(0, jsonArray.length())
.mapToObj(i -> jsonArray.getJSONObject(i))
.collect(Collectors.toList());
2 of 4
4
JSONArray is a sub-class of java.util.ArrayList and JSONObject is a sub-class of java.util.HashMap.
Therefore, new JSONObject().put("name", "John") returns the previous value associated with the key (null), not the JSONObject instance. As a result, null is added to the JSONArray.
This, on the other hand, works:
JSONArray jsonArray = new JSONArray();
JSONObject j1 = new JSONObject();
j1.put ("name", "John");
JSONObject j2 = new JSONObject();
j2.put ("name", "David");
jsonArray.add(j1);
jsonArray.add(j2);
Stream<String> ss = jsonArray.stream().map (json->json.toString ());
List<String> list = ss.collect (Collectors.toList ());
System.out.println(list);
For some reason I had to split the stream pipeline into two steps, because otherwise the compiler doesn't recognize that .collect (Collectors.toList()) returns a List.
The output is:
[{"name":"John"}, {"name":"David"}]
Top answer 1 of 16
204
ArrayList<String> listdata = new ArrayList<String>();
JSONArray jArray = (JSONArray)jsonObject;
if (jArray != null) {
for (int i=0;i<jArray.length();i++){
listdata.add(jArray.getString(i));
}
}
2 of 16
85
I've done it using Gson (by Google).
Add the following line to your module's build.gradle:
dependencies {
// ...
// Note that `compile` will be deprecated. Use `implementation` instead.
// See https://stackoverflow.com/a/44409111 for more info
implementation 'com.google.code.gson:gson:2.8.2'
}
JSON string:
private String jsonString = "[\n" +
" {\n" +
" \"id\": \"c200\",\n" +
" \"name\": \"Ravi Tamada\",\n" +
" \"email\": \"[email protected]\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"male\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c201\",\n" +
" \"name\": \"Johnny Depp\",\n" +
" \"email\": \"[email protected]\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"male\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c202\",\n" +
" \"name\": \"Leonardo Dicaprio\",\n" +
" \"email\": \"[email protected]\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"male\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c203\",\n" +
" \"name\": \"John Wayne\",\n" +
" \"email\": \"[email protected]\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"male\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c204\",\n" +
" \"name\": \"Angelina Jolie\",\n" +
" \"email\": \"[email protected]\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"female\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c205\",\n" +
" \"name\": \"Dido\",\n" +
" \"email\": \"[email protected]\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"female\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c206\",\n" +
" \"name\": \"Adele\",\n" +
" \"email\": \"[email protected]\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"female\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c207\",\n" +
" \"name\": \"Hugh Jackman\",\n" +
" \"email\": \"[email protected]\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"male\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c208\",\n" +
" \"name\": \"Will Smith\",\n" +
" \"email\": \"[email protected]\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"male\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c209\",\n" +
" \"name\": \"Clint Eastwood\",\n" +
" \"email\": \"[email protected]\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"male\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c2010\",\n" +
" \"name\": \"Barack Obama\",\n" +
" \"email\": \"[email protected]\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"male\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c2011\",\n" +
" \"name\": \"Kate Winslet\",\n" +
" \"email\": \"[email protected]\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"female\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" },\n" +
" {\n" +
" \"id\": \"c2012\",\n" +
" \"name\": \"Eminem\",\n" +
" \"email\": \"[email protected]\",\n" +
" \"address\": \"xx-xx-xxxx,x - street, x - country\",\n" +
" \"gender\" : \"male\",\n" +
" \"phone\": {\n" +
" \"mobile\": \"+91 0000000000\",\n" +
" \"home\": \"00 000000\",\n" +
" \"office\": \"00 000000\"\n" +
" }\n" +
" }\n" +
" ]";
ContactModel.java:
public class ContactModel {
public String id;
public String name;
public String email;
}
Code for converting a JSON string to ArrayList<Model>:
Note: You have to import java.lang.reflect.Type;:
// Top of file
import java.lang.reflect.Type;
// ...
private void parseJSON() {
Gson gson = new Gson();
Type type = new TypeToken<List<ContactModel>>(){}.getType();
List<ContactModel> contactList = gson.fromJson(jsonString, type);
for (ContactModel contact : contactList){
Log.i("Contact Details", contact.id + "-" + contact.name + "-" + contact.email);
}
}
Hope this will help you.
How to do in Java
howtodoinjava.com › home › convert json array to list: gson, jackson and org.json
Convert JSON Array to List: Gson, Jackson and Org.json
September 25, 2023 - List<Person> readPersonListFromJsonArray(String jsonArray) { //Use autowired bean in Spring / Spring Boot Gson gson = new Gson(); Type listType = new TypeToken<List<Person>>() {}.getType(); List<Person> personList = gson.fromJson(jsonArray, listType); return personList; } Org.json or JSON-Java is a simple and lightweight Java-based library that we can use to encode or decode between JSON and XML, HTTP headers, Cookies, and CDL.
Oracle
docs.oracle.com › javame › 8.0 › api › json › api › com › oracle › json › JsonArray.html
JsonArray (JSON Documentation)
The values in a JsonArray can be of the following types: JsonObject, JsonArray, JsonString, JsonNumber, JsonValue.TRUE, JsonValue.FALSE, and JsonValue.NULL.
Top answer 1 of 16
196
ArrayList<String> list = new ArrayList<String>();
JSONArray jsonArray = (JSONArray)jsonObject;
if (jsonArray != null) {
int len = jsonArray.length();
for (int i=0;i<len;i++){
list.add(jsonArray.get(i).toString());
}
}
2 of 16
63
If you don't already have a JSONArray object, call
JSONArray jsonArray = new JSONArray(jsonArrayString);
Then simply loop through that, building your own array. This code assumes it's an array of strings, it shouldn't be hard to modify to suit your particular array structure.
List<String> list = new ArrayList<String>();
for (int i=0; i<jsonArray.length(); i++) {
list.add( jsonArray.getString(i) );
}
Tabnine
tabnine.com › home page › code › java › org.json.jsonarray
org.json.JSONArray.toList java code examples | Tabnine
* * @return a java.util.Map containing the entries of this object */ public Map<String, Object> toMap() { Map<String, Object> results = new HashMap<String, Object>(); for (Entry<String, Object> entry : this.map.entrySet()) { Object value; if (entry.getValue() == null || NULL.equals(entry.getValue())) { value = null; } else if (entry.getValue() instanceof JSONObject) { value = ((JSONObject) entry.getValue()).toMap(); } else if (entry.getValue() instanceof JSONArray) { value = ((JSONArray) entry.getValue()).toList(); } else { value = entry.getValue(); } results.put(entry.getKey(), value); } return results; } } ... /** * Returns a java.util.List containing all of the elements in this array.
Mkyong
mkyong.com › home › java › how to parse json array with jackson
How to parse JSON Array with Jackson - Mkyong.com
April 23, 2024 - convert JSON array to Array objects ... System.out.println(p); } // 2. convert JSON array to List List<Person> person2 = mapper.readValue(jsonArray, new TypeReference<>() { }); person2.forEach(System.out::println); } } ... ...
Baeldung
baeldung.com › home › json › jackson › convert json array to java list
Convert JSON Array to Java List | Baeldung
August 13, 2025 - Learn how to convert a JSON array to a Java List using the popular Gson and Jackson libraries.
Stleary
stleary.github.io › JSON-java › org › json › JSONArray.html
JSONArray
The internal form is an object ... values. The values can be any of these types: Boolean, JSONArray, JSONObject, Number, String, or the JSONObject.NULL object. The constructor can convert a JSON text into a Java object....
Top answer 1 of 6
245
Have you tried using JSONArray.getJSONObject(int), and JSONArray.length() to create your for-loop:
for (int i = 0; i < recs.length(); ++i) {
JSONObject rec = recs.getJSONObject(i);
int id = rec.getInt("id");
String loc = rec.getString("loc");
// ...
}
2 of 6
5
An org.json.JSONArray is not iterable.
Here's how I process elements in a net.sf.json.JSONArray:
JSONArray lineItems = jsonObject.getJSONArray("lineItems");
for (Object o : lineItems) {
JSONObject jsonLineItem = (JSONObject) o;
String key = jsonLineItem.getString("key");
String value = jsonLineItem.getString("value");
...
}
Works great... :)
Tabnine
tabnine.com › home page › code › java › org.json.jsonarray
org.json.JSONArray java code examples | Tabnine
List<Photo> parse(String response) throws JSONException { JSONObject searchResults = new JSONObject(response.substring(FLICKR_API_PREFIX_LENGTH, response.length() - 1)); JSONArray photos = searchResults.getJSONObject("photos").getJSONArray("photo"); List<Photo> results = new ArrayList<>(photos.length()); for (int i = 0, size = photos.length(); i < size; i++) { results.add(new Photo(photos.getJSONObject(i))); } return results; } } ... public static JSONArray readJsonFromUrl(String url) throws IOException, JSONException { InputStream is = new URL(url).openStream(); try { BufferedReader rd = new BufferedReader(new InputStreamReader(is, Charset.forName("UTF-8"))); String jsonText = readAll(rd); JSONArray json = new JSONArray(jsonText); return json; } finally { is.close(); } }
Top answer 1 of 2
7
Well basically org.json.JSONArray is not array as such. It's just a class that represents JSON array (yep, sounds weird) which is [].
Good news is that it implements Iterable. So you can get a stream like that:
String x="{\"count\":25,\"rows\":[{\"id\":10,\"name\":\"xxx\"},
{\"id\":11,\"name\":\"xyx\"}]}";
JSONObject obj = new JSONObject(x);
JSONArray arr= obj.getJSONArray("rows");
StreamSupport.stream(arr.spliterator(), false)
.forEach(System.out::println);
Out:
{"name":"xxx","id":10}
{"name":"xyx","id":11}
Edit 1 - answer to comments
Code that you provided works perfectly fine for me. It does filter all objects in array except those which have id==11:
List<JSONObject> list = StreamSupport.stream(arr.spliterator(), false)
.map(val -> (JSONObject) val)
.filter(val -> val.getInt("id") == 11)
.collect(Collectors.toList());
System.out.println(list);
Out:
[{"name":"xyx","id":11}]
2 of 2
0
You can use the iterator to stream conversion:
Stream<String> stream= StreamSupport.stream(
arr.spliteratorUnknownSize(list.iterator(), Spliterator.ORDERED),
false);
Another solution would be to use the standard for java implementation - javax.json.JsonArray which is basically a collection and gives you a stream() method
Oracle
docs.oracle.com › javaee › 7 › api › javax › json › JsonArray.html
JsonArray (Java(TM) EE 7 Specification APIs)
JsonObject home = array.getJsonObject(0); String number = home.getString("number"); JsonArray instances are list objects that provide read-only access to the values in the JSON array.
BeginnersBook -
beginnersbook.com › home › java › convert json array to arraylist in java
Convert JSON Array to ArrayList in Java
June 13, 2024 - import org.json.JSONArray; import ... \"age\":37}, {\"name\":\"Rahul\", \"age\":34}]"; // Convert JSON array to JSONArray JSONArray jsonArray = new JSONArray(jsonArrayString); // Convert JSONArray to ArrayList ArrayList<JSONObject> arrayList = new ArrayList<>(); for (int ...
Stack Overflow
stackoverflow.com › questions › 13171540 › easiest-and-most-efficient-way-to-convert-jsonarray-to-list
java - Easiest and most efficient way to convert JSONArray to List - Stack Overflow
What is the easiest and most efficient way to convert org.json.JSONArray to List? ... FYI, net.sf.JSONArray implements java.util.List.
TutorialsPoint
tutorialspoint.com › org_json › org_json_jsonarray.htm
Org.Json - HTTP Class
package com.tutorialspoint; import org.json.JSONArray; import org.json.JSONObject; public class JsonDemo { public static void main(String[] args) { JSONArray list = new JSONArray(); list.put("foo"); list.put(Integer.valueOf(100)); list.put(Double.valueOf(1000.21)); list.put(Boolean.TRUE); list.put(JSONObject.NULL); System.out.println("JSONArray: "); System.out.println(list); } }
Top answer 1 of 4
74
Seems like you can't iterate through JSONArray with a for each. You can loop through your JSONArray like this:
for (int i=0; i < arr.length(); i++) {
arr.getJSONObject(i);
}
Source
2 of 4
52
Apparently, org.json.simple.JSONArray implements a raw Iterator. This means that each element is considered to be an Object. You can try to cast:
for(Object o: arr){
if ( o instanceof JSONObject ) {
parse((JSONObject)o);
}
}
This is how things were done back in Java 1.4 and earlier.
Stack Abuse
stackabuse.com › converting-json-array-to-a-java-array-or-list
Convert JSON Array to a Java Array or List with Jackson
September 8, 2020 - In this article, we'll convert a JSON array into a Java Array and Java List using Jackson.
GitHub
github.com › stleary › JSON-java › issues › 491
Casting list of JSONObject to JSONObject throws ClassCastException · Issue #491 · stleary/JSON-java
October 22, 2019 - @Test public void shouldCastArrayOfJSONObjectsToList() { String a = "{\"a\": 1}"; String b = "{\"b\":2}"; String jsonString = "{\"list\":[" + a + "," + b + "]}"; JSONObject jsonObject = new JSONObject(jsonString); JSONArray jsonArray = jsonObject.getJSONArray("list"); List<JSONObject> jsonObjects = jsonArray.toList().stream().map(JSONObject.class::cast).collect(Collectors.toList()); assertEquals(jsonObjects.size(), 2); } No exception should be thrown and the test should pass · ClassCastException is thrown. java.lang.ClassCastException: Cannot cast java.util.HashMap to org.json.JSONObject at j
Author ggavriilidis