df.groupby('Category').agg({'Item':'size','shop1':['sum','mean','std'],'shop2':['sum','mean','std'],'shop3':['sum','mean','std']})
Or if you want it across all shops then:
df1 = df.set_index(['Item','Category']).stack().reset_index().rename(columns={'level_2':'Shops',0:'costs'})
df1.groupby('Category').agg({'Item':'size','costs':['sum','mean','std']})
Answer from Scott Boston on Stack Overflowdf.groupby('Category').agg({'Item':'size','shop1':['sum','mean','std'],'shop2':['sum','mean','std'],'shop3':['sum','mean','std']})
Or if you want it across all shops then:
df1 = df.set_index(['Item','Category']).stack().reset_index().rename(columns={'level_2':'Shops',0:'costs'})
df1.groupby('Category').agg({'Item':'size','costs':['sum','mean','std']})
Edited for Pandas 0.22+ considering the deprecation of the use of dictionaries in a group by aggregation.
We set up a very similar dictionary where we use the keys of the dictionary to specify our functions and the dictionary itself to rename the columns.
rnm_cols = dict(size='Size', sum='Sum', mean='Mean', std='Std')
df.set_index(['Category', 'Item']).stack().groupby('Category') \
.agg(rnm_cols.keys()).rename(columns=rnm_cols)
Size Sum Mean Std
Category
Books 3 58 19.333333 2.081666
Clothes 3 148 49.333333 4.041452
Technology 6 1800 300.000000 70.710678
option 1
use agg ← link to docs
agg_funcs = dict(Size='size', Sum='sum', Mean='mean', Std='std')
df.set_index(['Category', 'Item']).stack().groupby(level=0).agg(agg_funcs)
Std Sum Mean Size
Category
Books 2.081666 58 19.333333 3
Clothes 4.041452 148 49.333333 3
Technology 70.710678 1800 300.000000 6
option 2
more for less
use describe ← link to docs
df.set_index(['Category', 'Item']).stack().groupby(level=0).describe().unstack()
count mean std min 25% 50% 75% max
Category
Books 3.0 19.333333 2.081666 17.0 18.5 20.0 20.5 21.0
Clothes 3.0 49.333333 4.041452 45.0 47.5 50.0 51.5 53.0
Technology 6.0 300.000000 70.710678 200.0 262.5 300.0 337.5 400.0
Videos
df.groupby("category", as_index=False).mean()
Your first three lines correctly print out the result
category score priority
0 A 2 1
1 A 4 2
2 B 5 3
3 B 2 3
Now add this line:
df.groupby("category").mean(numeric_only=True)
and you will see:
score priority
category
A 3.0 1.5
B 3.5 3.0
which is probably what you're looking for. Running mean(numeric_only=True) on a DataFrame calculates means for all numeric columns. (You can leave it out right now, but you'll get a deprecated-feature message.)
If you call .reset_index() on the series that you have, it will get you a dataframe like you want (each level of the index will be converted into a column):
df.groupby(['name', 'id', 'dept'])['total_sale'].mean().reset_index()
EDIT: to respond to the OP's comment, adding this column back to your original dataframe is a little trickier. You don't have the same number of rows as in the original dataframe, so you can't assign it as a new column yet. However, if you set the index the same, pandas is smart and will fill in the values properly for you. Try this:
cols = ['date','name','id','dept','sale1','sale2','sale3','total_sale']
data = [
['1/1/17', 'John', 50, 'Sales', 50.0, 60.0, 70.0, 180.0],
['1/1/17', 'Mike', 21, 'Engg', 43.0, 55.0, 2.0, 100.0],
['1/1/17', 'Jane', 99, 'Tech', 90.0, 80.0, 70.0, 240.0],
['1/2/17', 'John', 50, 'Sales', 60.0, 70.0, 80.0, 210.0],
['1/2/17', 'Mike', 21, 'Engg', 53.0, 65.0, 12.0, 130.0],
['1/2/17', 'Jane', 99, 'Tech', 100.0, 90.0, 80.0, 270.0],
['1/3/17', 'John', 50, 'Sales', 40.0, 50.0, 60.0, 150.0],
['1/3/17', 'Mike', 21, 'Engg', 53.0, 55.0, 12.0, 120.0],
['1/3/17', 'Jane', 99, 'Tech', 80.0, 70.0, 60.0, 210.0]
]
df = pd.DataFrame(data, columns=cols)
mean_col = df.groupby(['name', 'id', 'dept'])['total_sale'].mean() # don't reset the index!
df = df.set_index(['name', 'id', 'dept']) # make the same index here
df['mean_col'] = mean_col
df = df.reset_index() # to take the hierarchical index off again
You are very close. You simply need to add a set of brackets around [['total_sale']] to tell python to select as a dataframe and not a series:
df.groupby(['name', 'id', 'dept'])[['total_sale']].mean()
If you want all columns:
df.groupby(['name', 'id', 'dept'], as_index=False).mean()[['name', 'id', 'dept', 'total_sale']]