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Quickest way to convert XML to JSON in Java [closed]

stackoverflow.com › questions › 1823264 › quickest-way-to-convert-xml-to-json-in-java

JSON in Java has some great resources.

Maven dependency:

<dependency>
  <groupId>org.json</groupId>
  <artifactId>json</artifactId>
  <version>20180813</version>
</dependency>

XML.java is the class you're looking for:

import org.json.JSONObject;
import org.json.XML;
import org.json.JSONException;

public class Main {

    public static int PRETTY_PRINT_INDENT_FACTOR = 4;
    public static String TEST_XML_STRING =
        "<?xml version=\"1.0\" ?><test attrib=\"moretest\">Turn this to JSON</test>";

    public static void main(String[] args) {
        try {
            JSONObject xmlJSONObj = XML.toJSONObject(TEST_XML_STRING);
            String jsonPrettyPrintString = xmlJSONObj.toString(PRETTY_PRINT_INDENT_FACTOR);
            System.out.println(jsonPrettyPrintString);
        } catch (JSONException je) {
            System.out.println(je.toString());
        }
    }
}

Output is:

{"test": {
    "attrib": "moretest",
    "content": "Turn this to JSON"
}}

Answer from danieltalsky on Stack Overflow

Stack Overflow

stackoverflow.com › questions › 1823264 › quickest-way-to-convert-xml-to-json-in-java

Quickest way to convert XML to JSON in Java - Stack Overflow

Top answer

1 of 6

217

JSON in Java has some great resources.

Maven dependency:

<dependency>
  <groupId>org.json</groupId>
  <artifactId>json</artifactId>
  <version>20180813</version>
</dependency>

XML.java is the class you're looking for:

import org.json.JSONObject;
import org.json.XML;
import org.json.JSONException;

public class Main {

    public static int PRETTY_PRINT_INDENT_FACTOR = 4;
    public static String TEST_XML_STRING =
        "<?xml version=\"1.0\" ?><test attrib=\"moretest\">Turn this to JSON</test>";

    public static void main(String[] args) {
        try {
            JSONObject xmlJSONObj = XML.toJSONObject(TEST_XML_STRING);
            String jsonPrettyPrintString = xmlJSONObj.toString(PRETTY_PRINT_INDENT_FACTOR);
            System.out.println(jsonPrettyPrintString);
        } catch (JSONException je) {
            System.out.println(je.toString());
        }
    }
}

Output is:

{"test": {
    "attrib": "moretest",
    "content": "Turn this to JSON"
}}

2 of 6

To convert XML File in to JSON include the following dependency

<dependency>
    <groupId>org.json</groupId>
    <artifactId>json</artifactId>
    <version>20140107</version>
</dependency>

and you can Download Jar from Maven Repository here. Then implement as:

String soapmessageString = "<xml>yourStringURLorFILE</xml>";
JSONObject soapDatainJsonObject = XML.toJSONObject(soapmessageString);
System.out.println(soapDatainJsonObject);

Baeldung

baeldung.com › home › json › jackson › convert xml to json using jackson

Convert XML to JSON Using Jackson | Baeldung

January 8, 2024 - Data binding, simply put, is when we want to map serialized data directly to a Java object. To explore this, let’s define our XML with Flower and Color properties: <Flower> <name>Poppy</name> <color>RED</color> <petals>9</petals> </Flower> ... public class Flower { private String name; private Color color; private Integer petals; // getters and setters } public enum Color { PINK, BLUE, YELLOW, RED; } Our first step will be to parse the XML into a Flower instance.

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Convert xml to json with Java - Stack Overflow

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