The problem is that you try to parse "x.x\n", e.g: 1.8\n. And this returns an error: strconv.ParseFloat: parsing "1.8\n": invalid syntax. You can do a strings.TrimSpace function or to convert feet[:len(feet)-1] to delete \n character

With strings.TrimSpace() (you need to import strings package):

CopyfeetFloat, _ := strconv.ParseFloat(strings.TrimSpace(feet), 64)

Wtih feet[:len(feet)-1]:

CopyfeetFloat, _ := strconv.ParseFloat(feet[:len(feet)-1], 64)

Output in both cases:

Copy10.8 feet converted to meters give you 3.2918400000000005 meters

Go uses IEEE-754 binary floating-point numbers. Floating-point numbers are imprecise. Don't use them for financial transactions. Use integers.

For example,

package main

import (
    "fmt"
    "strconv"
    "strings"
)

func parseCents(s string) (int64, error) {
    n := strings.SplitN(s, ".", 3)
    if len(n) != 2 || len(n[1]) != 2 {
        err := fmt.Errorf("format error: %s", s)
        return 0, err
    }
    d, err := strconv.ParseInt(n[0], 10, 56)
    if err != nil {
        return 0, err
    }
    c, err := strconv.ParseUint(n[1], 10, 8)
    if err != nil {
        return 0, err
    }
    if d < 0 {
        c = -c
    }
    return d*100 + int64(c), nil
}

func main() {
    s := "79.35"
    fmt.Println(parseCents(s))
    s = "149.20"
    fmt.Println(parseCents(s))
    s = "-149.20"
    fmt.Println(parseCents(s))
    s = "149.2"
    fmt.Println(parseCents(s))
}

Playground: https://play.golang.org/p/mGuO51QWyIv

Output:

7935 <nil>
14920 <nil>
-14920 <nil>
0 format error: 149.2