Had the same problem

Let me show you what I did

PHP :

base64_encode(json_encode($bodyData))

then

json_decode(shell_exec('python ' . base64_encode(json_encode($bodyData)) );

and in Python I have

import base64

and

content = json.loads(base64.b64decode(sys.argv[1]))

as Em L already mentioned :)

It works for me Cheers!

Copy    $jsonArr = array();
    foreach($periodi as $key => $val){
        $jsonArr[$key]['name'] = $val;
        $jsonArr[$key]['data'] = $key; //there is no source for priority 
          //in your array so i just put $key as priority variable
    }

    json_encode($jsonArr);

If your array isn't too exotic, your JSON idea should actually work just fine. I built a little python script (test.py) to feed the php script (test.php):

test.py:

import json
print json.dumps([['a','b','c'], ['d','e','f']]);

test.php:

<?php
$command = escapeshellcmd('python test.py');
$output = shell_exec($command);
echo $output;
$arr = json_decode($output);
var_dump($arr);
?>

Thank you all for comments! According to that, I kind figure out solution.

Python script

data = {}
for result in results:
    if 'stackoverflow.com' in result['serp_url']:
        data['url'] = result['serp_url']
        data['rank'] = result['serp_rank']
        data['query'] = result['query']
        print(json.dumps(data))
        exit

PHP script

exec("python3 py.py", $output);

$test = [];

foreach($output as $key => $out) {
    $test[$key] = json_decode($out, true);
    print_r("Rank: " . $test[$key]['rank'] ." - ". $test[$key]['url']."<br>");
}

Output

Rank: 1 - https://stackoverflow.com/
Rank: 36 - https://www.quantcast.com/stackoverflow.com

If you pass the JSON in your post to json_decode, it will fail. Valid JSON strings have quoted keys:

json_decode('{foo:"bar"}');         // this fails
json_decode('{"foo":"bar"}', true); // returns array("foo" => "bar")
json_decode('{"foo":"bar"}');       // returns an object, not an array.

You creating invalid json by adding apiBlockTicketRequest to output

 $json='apiBlockTicketRequest'.$data;

instead you can do

$json = json_encode(['apiBlockTicketRequest' => $prebook]);

You want to json_encode($json, JSON_FORCE_OBJECT).

The JSON_FORCE_OBJECT flag, as the name implies, forces the json output to be an object, even when it otherwise would normally be represented as an array.

You can also eliminate the use of array_push for some slightly cleaner code:

$json[] = ['ip' => $ip, 'port' => $port];