test.php:

<?php
print_r($argv);
?>

Shell:

$ php -q test.php foo bar
Array
(
    [0] => test.php
    [1] => foo
    [2] => bar
)

You're starting your command with . - that will be interpreted as shell-source command, which is not what you want, obviously. Instead specify full path and do like:

$result = shell_exec('/bin/bash /full/path/to/script.sh param1 param2');
//var_dump($result);

-also, make sure your php user have permission to execute your sh-script and that PHP can use functions like exec() (they could be disabled by configuration)

Passing parameters to a shell script from PHP.

Its all about the "strings", and when to "double quote" for expansion.

<?php

/* exec("/csvexport.sh $table"); */

/* double quote here because you want PHP to expand $table */
/* Escape double quotes so they are passed to the shell because you do not wnat the shell to choke on spaces */
$command_with_parameters = "/path/csvexport.sh \"${table}\"";
$output_from_command = "";
$command_success = "";

/* double quote here because you want PHP to expand $command_with_parameters, a string */
exec("${command_with_parameters}", $output_from_command, $command_success);

/* or to keep it simple */
exec("/path/csvexport.sh \"${table}\"");


/* show me what you got */
echo"${command_success}\n${output_from_command}\n";

?>

BTW: I did not test this snippet.

The problem here is that you are quoting the entiore command you are trying to run as a single variable. As a result, you're not running php with foo.php as an argument but instead are attempting to execute a file called php foo.php. Here's a simpler example to show you what I mean:

$ var1="echo "
$ var2="foo"
$ set -x ## debugging info
var1$var2"
+ 'echo foo'      ### The shell tries to execute both vars as a single command
bash: echo foo: command not found

var1" "$var2"
+ 'echo ' foo     ### The shell tries to execute 'echo ' (echo with a space)
bash: echo foo: command not found  

So, the right way is to remove the space and quote each variable separately:

$ var1="echo"
$ var2="foo"
var1" "$var2"

If you do that though, you'll hit the next error. The . is the source command. That tries to read a shell script and execute it in the current session. You are giving it a php script instead. That won't work, you need to execute it, not source it.

Finally, always avoid using CAPITAL variable names. The shell's reserved variables are capitalized so it's a good idea to always use lower case variable names for your scripts.

Putting all this together (with a few other minor improvements), what you want is something like:

#!/bin/sh

list="/path/to/my/site/dir"
config="/usr/bin/php"

for i in "$list"
do
    "$config" "$i"/test.php
done

Several possibilities:

• You have safe mode enabled. That way, only exec() is working, and then only on executables in safe_mode_exec_dir
• exec and shell_exec are disabled in php.ini
• The path to the executable is wrong. If the script is in the same directory as the php file, try exec(dirname(__FILE__) . '/myscript.sh');

You can use that code:

start_date="2014-10-05"
days=2
for i in $(seq 0 $days);
do
  php update_cron.php $(date "+%Y-%m-%d" --date="$start_date +$i days")
done

Explanation:

• start_date="2014-10-05": Sets the date where you start
• days=2: sets the number of days you want (note: 2 means 3 days in total, day 0 also counts)
• for i in $(seq 0 $days);: loops trough $days times
• php update_cron.php $(...): executes php update_cron.php with the argument
• $(date "+%Y-%m-%d" --date="$start_date +$i days"): formats the date and estimates the date from $start_date plus $i days

You aren't using passed argument in your command. You need to use the argument in whois command:

<?php    
$argument1 = escapeshellarg($argv[1]);  
$output = shell_exec('whois '. $argument1);    
echo "<pre>$output</pre>";    
?>

PS: whois can tun without sudo also.

Note: I didn't do all the settings, just enough I hope you get the idea.

Option 1: Passing parameters

PHP:

$file = escapeshellarg($file);
$filename = escapeshellarg($filename);
// escape the others
$output = exec("./bashscript $file $filename $tags $private $password");

Bash:

#!/bin/bash
filename=$1
file=$2
description="Test of the api with a simple model"
token_api="ff00ff"
title="Uber Glasses"
tags=$3
private=$4
password=$5

...

Option 2: Using environment variables

PHP:

putenv("FILENAME=$filename");
putenv("FILE=$file");
putenv("TAGS=$tags");
putenv("PRIVATE=$private");
putenv("PASSWORD=$PASSWORD");

$output = exec('./bash_script');

Bash:

filename=$FILENAME
file=$FILE
description="Test of the api with a simple model"
token_api="ff00ff"
title="Uber Glasses"
tags=$TAGS
private=$PRIVATE
password=$PASSWORD

...