You can achieve this using only 2 more parameters in px.line:
markers=Truecolor_discrete_sequence=my_plotly_continuous_sequence
The complete code would look something like this (Note the list slicing [::4] so that the colors are well spaced):
import plotly.express as px
import pandas as pd
import numpy as np
x = [1, 2, 3, 4, 5, 6]
df = pd.DataFrame(
{
'x': x * 3,
'y': list(np.array(x)) + list(np.array(x) ** 2) + list(np.array(x) ** .5),
'color': list(np.array(x) * 0) + list(np.array(x) * 0 + 1) + list(np.array(x) * 0 + 2),
}
)
fig = px.line(
df,
x='x',
y='y',
color='color',
color_discrete_sequence=px.colors.sequential.Plasma[::4],
markers=True,
template='plotly'
)
fig.show()
This produces the following output.

In case you have more lines than the colors present in the colormap, you can construct a custom colorscale so that you get one complete sequence instead of a cycling sequence:
rgb = px.colors.convert_colors_to_same_type(px.colors.sequential.RdBu)[0]
colorscale = []
n_steps = 4 # Control the number of colors in the final colorscale
for i in range(len(rgb) - 1):
for step in np.linspace(0, 1, n_steps):
colorscale.append(px.colors.find_intermediate_color(rgb[i], rgb[i + 1], step, colortype='rgb'))
fig = px.line(df_e, x='temperature', y='probability', color='year', color_discrete_sequence=colorscale, height=900)
fig.show()

You can achieve this using only 2 more parameters in px.line:
markers=Truecolor_discrete_sequence=my_plotly_continuous_sequence
The complete code would look something like this (Note the list slicing [::4] so that the colors are well spaced):
import plotly.express as px
import pandas as pd
import numpy as np
x = [1, 2, 3, 4, 5, 6]
df = pd.DataFrame(
{
'x': x * 3,
'y': list(np.array(x)) + list(np.array(x) ** 2) + list(np.array(x) ** .5),
'color': list(np.array(x) * 0) + list(np.array(x) * 0 + 1) + list(np.array(x) * 0 + 2),
}
)
fig = px.line(
df,
x='x',
y='y',
color='color',
color_discrete_sequence=px.colors.sequential.Plasma[::4],
markers=True,
template='plotly'
)
fig.show()
This produces the following output.

In case you have more lines than the colors present in the colormap, you can construct a custom colorscale so that you get one complete sequence instead of a cycling sequence:
rgb = px.colors.convert_colors_to_same_type(px.colors.sequential.RdBu)[0]
colorscale = []
n_steps = 4 # Control the number of colors in the final colorscale
for i in range(len(rgb) - 1):
for step in np.linspace(0, 1, n_steps):
colorscale.append(px.colors.find_intermediate_color(rgb[i], rgb[i + 1], step, colortype='rgb'))
fig = px.line(df_e, x='temperature', y='probability', color='year', color_discrete_sequence=colorscale, height=900)
fig.show()

I am not sure this is possible using only plotly.express. If you use px.line, then you can pass the argument markers=True as described in this answer, but from the px.line documentation it doesn't look like continuous color scales are supported.
UPDATED ANSWER: in order to have both a legend that groups both the lines and markers together, it's probably simpest to use go.Scatter with the argument mode='lines+markers'. You'll need to add the traces one at a time (by plotting each unique color portion of the data one at a time) in order to be able to control each line+marker group from the legend.
When plotting these traces, you will need some functions to retrieve the colors of the lines from the continuous color scale because go.Scatter won't know what color your lines are supposed to be unless you specify them - thankfully that has been answered here.
Also you won't be able to generate a colorbar adding the markers one color at a time, so to add a colorbar, you can plot all of the markers at once using go.Scatter, but use the argument marker=dict(size=0, color="rgba(0,0,0,0)", colorscale='Plasma', colorbar=dict(thickness=20)) to display a colorbar, but ensure that these duplicate markers are not visible.
Putting all of this together:
# import plotly.express as px
import plotly.graph_objects as go
import pandas as pd
import numpy as np
x = [1,2,3,4,5,6]
df = pd.DataFrame(
{
'x': x*3,
'y': list(np.array(x)) + list(np.array(x)**2) + list(np.array(x)**.5),
'color': list(np.array(x)*0) + list(np.array(x)*0+1) + list(np.array(x)*0+2),
}
)
# This function allows you to retrieve colors from a continuous color scale
# by providing the name of the color scale, and the normalized location between 0 and 1
# Reference: https://stackoverflow.com/questions/62710057/access-color-from-plotly-color-scale
def get_color(colorscale_name, loc):
from _plotly_utils.basevalidators import ColorscaleValidator
# first parameter: Name of the property being validated
# second parameter: a string, doesn't really matter in our use case
cv = ColorscaleValidator("colorscale", "")
# colorscale will be a list of lists: [[loc1, "rgb1"], [loc2, "rgb2"], ...]
colorscale = cv.validate_coerce(colorscale_name)
if hasattr(loc, "__iter__"):
return [get_continuous_color(colorscale, x) for x in loc]
return get_continuous_color(colorscale, loc)
# Identical to Adam's answer
import plotly.colors
from PIL import ImageColor
def get_continuous_color(colorscale, intermed):
"""
Plotly continuous colorscales assign colors to the range [0, 1]. This function computes the intermediate
color for any value in that range.
Plotly doesn't make the colorscales directly accessible in a common format.
Some are ready to use:
colorscale = plotly.colors.PLOTLY_SCALES["Greens"]
Others are just swatches that need to be constructed into a colorscale:
viridis_colors, scale = plotly.colors.convert_colors_to_same_type(plotly.colors.sequential.Viridis)
colorscale = plotly.colors.make_colorscale(viridis_colors, scale=scale)
:param colorscale: A plotly continuous colorscale defined with RGB string colors.
:param intermed: value in the range [0, 1]
:return: color in rgb string format
:rtype: str
"""
if len(colorscale) < 1:
raise ValueError("colorscale must have at least one color")
hex_to_rgb = lambda c: "rgb" + str(ImageColor.getcolor(c, "RGB"))
if intermed <= 0 or len(colorscale) == 1:
c = colorscale[0][1]
return c if c[0] != "#" else hex_to_rgb(c)
if intermed >= 1:
c = colorscale[-1][1]
return c if c[0] != "#" else hex_to_rgb(c)
for cutoff, color in colorscale:
if intermed > cutoff:
low_cutoff, low_color = cutoff, color
else:
high_cutoff, high_color = cutoff, color
break
if (low_color[0] == "#") or (high_color[0] == "#"):
# some color scale names (such as cividis) returns:
# [[loc1, "hex1"], [loc2, "hex2"], ...]
low_color = hex_to_rgb(low_color)
high_color = hex_to_rgb(high_color)
return plotly.colors.find_intermediate_color(
lowcolor=low_color,
highcolor=high_color,
intermed=((intermed - low_cutoff) / (high_cutoff - low_cutoff)),
colortype="rgb",
)
fig = go.Figure()
## add the lines+markers
for color_val in df.color.unique():
color_val_normalized = (color_val - min(df.color)) / (max(df.color) - min(df.color))
# print(f"color_val={color_val}, color_val_normalized={color_val_normalized}")
df_subset = df[df['color'] == color_val]
fig.add_trace(go.Scatter(
x=df_subset['x'],
y=df_subset['y'],
mode='lines+markers',
marker=dict(color=get_color('Plasma', color_val_normalized)),
name=f"line+marker {color_val}",
legendgroup=f"line+marker {color_val}"
))
## add invisible markers to display the colorbar without displaying the markers
fig.add_trace(go.Scatter(
x=df['x'],
y=df['y'],
mode='markers',
marker=dict(
size=0,
color="rgba(0,0,0,0)",
colorscale='Plasma',
cmin=min(df.color),
cmax=max(df.color),
colorbar=dict(thickness=40)
),
showlegend=False
))
fig.update_layout(
legend=dict(
yanchor="top",
y=0.99,
xanchor="left",
x=0.01),
yaxis_range=[min(df.y)-2,max(df.y)+2]
)
fig.show()

You need a jitter. I applied a pseudo-jitter function to the y-axis to create a scatter plot. The jitter function was inspired by the contents of this page. It may differ from the original graphing logic. At first, I wrote the graph by extracting the days of the week in a loop process, but since the color scale duplicates, I described all the days of the week and added the color scale only for Saturday since Saturday contains the largest value.
import plotly.graph_objects as go
import plotly.express as px
import numpy as np
df = px.data.tips()
N = len(df)
fig = go.Figure()
dfs = df.query('day == "Sun"')
fig.add_trace(go.Scatter(
x=dfs['total_bill'],
y=0 + np.random.rand(N) * 0.2,
mode='markers',
marker=dict(
size=9,
color=dfs['total_bill'],
),
name='Sun',
))
dfst = df.query('day == "Sat"')
fig.add_trace(go.Scatter(
x=dfst['total_bill'],
y=1 + np.random.rand(N) * 0.2,
mode='markers',
marker=dict(
size=9,
color=dfst['total_bill'],
colorbar=dict(
title='total_bill',
),
colorscale='Plasma'
),
name='Sat',
))
dfth = df.query('day == "Thur"')
fig.add_trace(go.Scatter(
x=dfth['total_bill'],
y=2 + np.random.rand(N) * 0.2,
mode='markers',
marker=dict(
size=9,
color=dfth['total_bill'],
),
name='Thur',
))
dff = df.query('day == "Fri"')
fig.add_trace(go.Scatter(
x=dff['total_bill'],
y=3 + np.random.rand(N) * 0.2,
mode='markers',
marker=dict(
size=9,
color=dff['total_bill'],
),
name='Fri',
))
fig.update_layout(showlegend=False, coloraxis_showscale=True)
fig.update_yaxes(tickvals=[0,1,2,3], ticktext=['Sun','Sat','Thur','Fri'])
fig.show()

You can use Plotly or Seaborn
Plotly
I am using grays here (white to black), but you can choose what makes sense. Check the RGB values... n_colors will break up the colors into groups. Used 4 as there are 4 unique days here
Code:
import plotly.express as px
from plotly.colors import n_colors
df = px.data.tips()
fig = px.strip(df, x="total_bill", y="day", color="day", color_discrete_sequence = n_colors('rgb(0, 0, 0)', 'rgb(255, 255, 255)', 4, colortype = 'rgb'))
Output

Seaborn
It is actually easier in seaborn as you can use palette and using jitter=True, you should be good to go
Code:
import seaborn as sns
sns.stripplot(data = df, x='total_bill', y = 'day', palette = 'gray', jitter=True)
Output

Option 3 - continuous X-axis
If you need the gradient on the X-axis, you need add hue='total_bill' to the sns plot. Code below... I have removed the legend as it will show all colors, which you probably don't need
import seaborn as sns
sns.stripplot(data = df, x='total_bill', y = 'day', hue = 'total_bill', palette = 'gray', jitter=True)
plt.legend([],[], frameon=False)
Output


