Spark 2.2 onwards

df.filter(df.location.contains('google.com'))

Spark 2.2 documentation link

Spark 2.1 and before

You can use plain SQL in filter

df.filter("location like '%google.com%'")

or with DataFrame column methods

df.filter(df.location.like('%google.com%'))

Spark 2.1 documentation link

You can use the contains function.

from pyspark.sql.functions import *
df1 = spark.createDataFrame([("hahaha the 3 is good",3),("i dont know about 3",2),("what is 5 doing?",5),\
("ajajaj 123",2),("7 dwarfs",1)], ["long_text","number"]) 
df1.filter(col("long_text").contains(col("number"))).show()

The long_text column should contain the number in the number column.

Output:

+--------------------+------+
|           long_text|number|
+--------------------+------+
|hahaha the 3 is good|     3|
|    what is 5 doing?|     5|
|          ajajaj 123|     2|
+--------------------+------+