You can do
orig.update(extra)
or, if you don't want orig to be modified, make a copy first:
dest = dict(orig) # or orig.copy()
dest.update(extra)
Note that if extra and orig have overlapping keys, the final value will be taken from extra. For example,
>>> d1 = {1: 1, 2: 2}
>>> d2 = {2: 'ha!', 3: 3}
>>> d1.update(d2)
>>> d1
{1: 1, 2: 'ha!', 3: 3}
Answer from mipadi on Stack OverflowYou can do
orig.update(extra)
or, if you don't want orig to be modified, make a copy first:
dest = dict(orig) # or orig.copy()
dest.update(extra)
Note that if extra and orig have overlapping keys, the final value will be taken from extra. For example,
>>> d1 = {1: 1, 2: 2}
>>> d2 = {2: 'ha!', 3: 3}
>>> d1.update(d2)
>>> d1
{1: 1, 2: 'ha!', 3: 3}
There are two ways to add one dictionary to another:
Update (modifies orig in place)
orig.update(extra) # Python 2.7+
orig |= extra # Python 3.9+
Merge (creates a new dictionary)
# Python 2.7+
dest = collections.ChainMap(orig, extra)
dest = {k: v for d in (orig, extra) for (k, v) in d.items()}
# Python 3
dest = {**orig, **extra}
dest = {**orig, 'D': 4, 'E': 5}
# Python 3.9+
dest = orig | extra
Caveats
Note that these operations are noncommutative. In all cases, the latter is the winner. E.g.
orig = {'A': 1, 'B': 2} extra = {'A': 3, 'C': 3} dest = orig | extra # dest = {'A': 3, 'B': 2, 'C': 3} dest = extra | orig # dest = {'A': 1, 'B': 2, 'C': 3}
It is also important to note that only from Python 3.7 (and CPython 3.6)
dicts are ordered. So, in previous versions, the order of the items in the dictionary may vary.
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I have a script that continuosly generates dictionaries with the same keys but different values. I want to write the results out in a json file but to do that i need to do load & dump into the file.
with open('sample.json') as f:
data = json.load(f)
data.update(results)
with open('sample.json', 'w') as f:
json.dump(data, f)The above code only overwrites the existing data it doesn't append it. I figured it is beacuse the dictionaries have the same keys because if i try it with a different dictionary template, the append does happen.
Is there a way to append similar dictionaries without overwriting?