You haven't called the function!
def test(foundN):
if foundN%2 == 0:
print "The number ", foundN, "is ok."
else:
print "Try another number. "
foundN = input("Enter number: ")
test(foundN)
Answer from Ry- on Stack Overflowprint(-6 % 8) returns 2, not 6. What's the reason for this? Apparently, the operator doesn't produce the remainder. Can someone explain?
python - Find the division remainder of a number - Stack Overflow
Please help me with this code.
How does 'if (number % 2 == 0)' work in this example?
How to divide without remainders on Python - Stack Overflow
you are looking for the modulo operator:
a % b
for example:
>>> 26 % 7
5
Of course, maybe they wanted you to implement it yourself, which wouldn't be too difficult either.
The remainder of a division can be discovered using the operator %:
>>> 26%7
5
In case you need both the quotient and the modulo, there's the builtin divmod function:
>>> seconds= 137
>>> minutes, seconds= divmod(seconds, 60)
I have been trying to make a code for divisions that outputs if your 2 numbers are divisible or if they have a remainder. I need to add an error system to make it output "ERROR" if the user inputs 0 but whenever i input zero for the 1 number the code malfunctions, this is the code: i use python in visual studio code.
def division (num_1, num_2):
num_1 = int(input("Please enter the number to divide by: "))
num_2 = int(input("Please enter the number to divide: "))
division = num_2 / num_1
remainder = num_2 % num_1
if num_2 == (0):
print("ERROR!")
elif num_1 == (0):
print("ERROR!")
elif remainder:
print(f"{num_2} is not divisable by {num_1}, there is a remainder of {remainder}.")
else:
print(f"{num_2} is divisable by {num_1}")You can do 5//2 and get 2 instead of the 2.5 you'd get with 5/2.
As long as you're in Python 3
, you can also use floor(5/2).
Both ways of doing it give you the floor-rounded answer.
In python 3, the standard division operator / will do "real" division, while the // operator will do integer division.