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How to Get Range of Floating Numbers in Python | Delft Stack
February 2, 2024 - The below example code demonstrates how to use the numpy.linspace() to generate the range of floats from 0 to 1 with the step equal to 0.1. The num value for the required sequence will be (0 - 1)/0.1 = 10. seq = np.linspace(0, 1, 10, endpoint=0) ...
Finxter
blog.finxter.com βΊ 5-best-ways-to-generate-list-of-floats-in-python
5 Best Ways to Generate List of Floats in Python β Be on the Right Side of Change
One of the most concise methods for generating floats is to use list comprehension alongside range() to create a list of integers and then map those to floats. ... start = 0 end = 10 step = 1 float_list = [float(i)/2 for i in range(start*2, (end*2) + 1, step)] print(float_list) ...
TutorialKart
tutorialkart.com βΊ python βΊ python-range βΊ python-range-float
Python Range with Floating Point Numbers
January 17, 2021 - During iteration, if we divide each element with the same scaling factor, we get sequence of floating point numbers. ... start = 0 stop = 0.9 step = 0.1 scale = 10 for i in range(int(scale*start), int(scale*stop), int(scale*step)) : print(i/scale) ...
Iditect
iditect.com βΊ faq βΊ python βΊ python-range-for-floats.html
Python range() for floats
... start = 0.0 stop = 1.0 step = 0.2 float_range = [start + i * step for i in range(int((stop - start) / step))] print("Float range with list comprehension:", float_range) ... Description: This query explains how to generate a range of floats in reverse order.
PyTutorial
pytutorial.com βΊ python-range-float-how-to-generate-sequences
PyTutorial | Python Range Float: How to Generate Sequences
March 30, 2026 - For a deep dive into its exclusive stop behavior, see our guide on Is Python Range Inclusive? Stop Value Explained. This integer-only rule is non-negotiable. It is a core part of the function's contract. This ensures predictable and fast performance in loops. The simplest alternative is a list comprehension. You can use the integer range() to control iterations. Then, calculate the float value inside the loop. This gives you full control over the step size. # Generate a sequence from 0.0 to 2.0 in steps of 0.2 step = 0.2 num_steps = int((2.0 - 0.0) / step) + 1 # Calculate number of items float_sequence = [0.0 + i * step for i in range(num_steps)] print(float_sequence)
Finxter
blog.finxter.com βΊ 5-best-ways-to-create-a-python-list-of-floats-with-step
5 Best Ways to Create a Python List of Floats with Step β Be on the Right Side of Change
February 24, 2024 - This approach is Pythonic and concise, ... function that returns an iterator which generates consecutive numbers. By utilizing islice, we can generate a sequence of floats with the specified step size....
Top answer 1 of 16
187
You can either use:
[x / 10.0 for x in range(5, 50, 15)]
or use lambda / map:
map(lambda x: x/10.0, range(5, 50, 15))
2 of 16
119
I used to use numpy.arange but had some complications controlling the number of elements it returns, due to floating point errors. So now I use linspace, e.g.:
>>> import numpy
>>> numpy.linspace(0, 10, num=4)
array([ 0. , 3.33333333, 6.66666667, 10. ])
Finxter
blog.finxter.com βΊ 5-best-ways-to-create-a-set-of-floats-from-1-to-n-in-python
5 Best Ways to Create a Set of Floats from 1 to n in Python β Be on the Right Side of Change
February 25, 2024 - This code snippet demonstrates the creation of a set called float_set. It uses a set comprehension that iterates over the range of numbers from 1 up to, but not including, 5. Each integer i is cast to a float and then added to the set.
Its Linux FOSS
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Python Range of Float Numbers β Its Linux FOSS
February 19, 2023 - The range or sequence of numbers ... function is used in Python to generate the sequence of numbers. But the simple βrange()β function will return an error when the float value is passed to it, so we explained several other methods to create the range of float ...
TechBeamers
techbeamers.com βΊ python-float-range
Generate Floating Point Range in Python - TechBeamers
November 30, 2025 - However, all arguments are of integer type. If you pass a float, it results in a TypeError. start = 1 stop = 6.7 step = 0.1 for value in range(start, stop, step): print (value) When you run the above code, it throws the following error: TypeError: 'float' object cannot be interpreted as an integer Β· The above example suggests that Python doesnβt give any built-in way to generate a floating point range.
Top answer 1 of 2
3
It's relatively simple by creating an inclusive integer range from 2*min to 2*max and dividing it by 2:
df.with_columns(b = pl.col.a.list.eval(
pl.arange(2*pl.element().min(), 2*pl.element().max() + 1) / 2
))
2 of 2
0
pl.int_ranges()to create lists of integers.pl.Expr.repeat_by()to create a list of2with the same length, so we can divide the first list by it.
df.with_columns(
b = pl.int_ranges(2*pl.col.a.list.min(), 2*pl.col.a.list.max() + 1)
).with_columns(
pl.col.b / pl.lit(2).repeat_by(pl.col.b.list.len())
)
shape: (5, 2)
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β list[f64] β list[f64] β
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β [4.0, 5.0, 3.0, 7.0, 0.0, 1.0, 6.0, 2.0] β [0.0, 0.5, 1.0, 1.5, 2.0, 2.5, 3.0, 3.5, 4.0, 4.5, 5.0, 5.5, 6.0, 6.5, 7.0] β
β [2.0, 4.0, 3.0, 0.0, 1.0] β [0.0, 0.5, 1.0, 1.5, 2.0, 2.5, 3.0, 3.5, 4.0] β
β [1.0, 2.0, 3.0, 0.0, 4.0] β [0.0, 0.5, 1.0, 1.5, 2.0, 2.5, 3.0, 3.5, 4.0] β
β [1.0, 3.0, 2.0, 0.0] β [0.0, 0.5, 1.0, 1.5, 2.0, 2.5, 3.0] β
β [1.0, 0.0] β [0.0, 0.5, 1.0] β
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GeeksforGeeks
geeksforgeeks.org βΊ python βΊ python-create-a-list-of-floats
Python - Create a List of Floats - GeeksforGeeks
July 23, 2025 - If you want to create a list of floats based on a mathematical operation, map() combined with lambda can be efficient. ... If you're dealing with a large number of floats or need specialized functionality like linspace, numpy is a highly optimized ...
Top answer 1 of 3
2
In [1]: import numpy as np
In [2]: np.repeat(1 / 10**np.arange(1, 5), 2)[1:] * np.array([1., 5.]*4)[:-1]
Out[2]: array([0.1 , 0.05 , 0.01 , 0.005 , 0.001 , 0.0005, 0.0001])
Generalizing for any "pattern":
def rates(smallest_magnitude, pattern):
n = len(pattern)
pows = np.repeat(1 / 10**np.arange(1, smallest_magnitude), n)[(n-1):]
mults = np.array(pattern * (smallest_magnitude - 1))[:-(n-1)]
return np.round(pows * mults, smallest_magnitude)
Demo:
In [4]: print(*rates(5, [1, 5])) # Your original 'pattern'
0.1 0.05 0.01 0.005 0.001 0.0005 0.0001
In [5]: print(*rates(5, [2, 4, 8]))
0.2 0.04 0.08 0.02 0.004 0.008 0.002 0.0004 0.0008 0.0002
In [6]: print(*rates(5, [3, 5, 7, 9]))
0.3 0.05 0.07 0.09 0.03 0.005 0.007 0.009 0.003 0.0005 0.0007 0.0009 0.0003
2 of 3
2
This works, but I'm not sure it's any better than your method.
import numpy as np
# Create the powers of ten:
a = 0.1 ** np.arange(1,6)
# Interleave the halves in between:
a = np.concatenate((a,a/2))
# Sort and reverse:
a.sort()
a = a[-1::-1]
print(a)
Finxter
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5 Best Ways to Generate a Python List of Random Floats in Range - Be on the Right Side of Change
February 24, 2024 - The random.uniform(a, b) function from Pythonβs standard library module random generates a random float N such that a <= N <= b. Utilizing a list comprehension combines this function call with the ability to create a list of any size. ... This snippet imports the random module and generates a list of 10 random floats. The list comprehension iterates 10 times, each time calling random.uniform() with the desired range to produce a varied sequence of numbers.
w3resource
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Python Math: Create a range for floating numbers - w3resource
August 11, 2025 - #https://gist.github.com/axelpale/3e780ebdde4d99cbb69ffe8b1eada92c def frange(x, y, jump=1.0): i = 0.0 x = float(x) # Prevent yielding integers. y = float(y) # Comparison converts y to float every time otherwise. x0 = x epsilon = jump / 2.0 yield x # yield always first value while x + epsilon < y: i += 1.0 x = x0 + i * jump yield x print(list(frange(0.0, 1.0, 0.1))) ... [0.0, 0.1, 0.2, 0.30000000000000004, 0.4, 0.5, 0.6000000000000001, 0.7000000000000001, 0.8, 0.9, 1.0] ... Write a Python program to create a list of floating-point numbers from 0.0 to 1.0 with a step of 0.1 using a while loop.
ItSolutionstuff
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Python Generate List of Random Float Numbers Example - ItSolutionstuff.com
October 30, 2023 - import random import numpy as np low = 0.2 high = 2.9 # Python Generate List of Random Float Numbers Example floatList = [random.uniform(low, high) for _ in range(5)] print(floatList) ... [1.2810449626587266, 1.5206898226328796, 1.9837497458591744, 0.8076086725933713, 0.6949857530454222] ... import random import numpy as np low = 0.2 high = 2.9 # Python Generate List of Random Float Numbers Example floatList = [round(random.uniform(low, high), 2) for _ in range(5)] print(floatList)