Would something like this do what you need?
class Test(object):
def _decorator(foo):
def magic( self ) :
print "start magic"
foo( self )
print "end magic"
return magic
@_decorator
def bar( self ) :
print "normal call"
test = Test()
test.bar()
This avoids the call to self to access the decorator and leaves it hidden in the class namespace as a regular method.
>>> import stackoverflow
>>> test = stackoverflow.Test()
>>> test.bar()
start magic
normal call
end magic
>>>
edited to answer question in comments:
How to use the hidden decorator in another class
class Test(object):
def _decorator(foo):
def magic( self ) :
print "start magic"
foo( self )
print "end magic"
return magic
@_decorator
def bar( self ) :
print "normal call"
_decorator = staticmethod( _decorator )
class TestB( Test ):
@Test._decorator
def bar( self ):
print "override bar in"
super( TestB, self ).bar()
print "override bar out"
print "Normal:"
test = Test()
test.bar()
print
print "Inherited:"
b = TestB()
b.bar()
print
Output:
Normal:
start magic
normal call
end magic
Inherited:
start magic
override bar in
start magic
normal call
end magic
override bar out
end magic
Answer from Michael Speer on Stack OverflowHi r/learnpython, I'm currently working through djangoforbeginners and encountered the usage of classmethod() as a decorator for testing using setUpTestData().
I'm really trying to get comfortable reading the docs, but I feel like the explanations are using other terms I don't really understand to explain it, and feel like it's just looping into each other without a dumbed down explanation.
From what I could gather reading the docs, decorators make the code look neater in a similar(?) sense that list comprehension make it easier to read? I also don't quite understand what classmethod and staticmethod does that's different to just defining your own function. What do they mean by staticmethod not receiving an "implicit argument" vs. classmethod which does?
Please help an absolute clean slate beginner here! TIA.
python - Class method decorator with self arguments? - Stack Overflow
Decorators and class methods
The best explanation of Python decorators I’ve ever seen. (An archived answer from StackOverflow.) · GitHub
Can you explain what decorator is like I’m 5?
From a few years ago, an explanation people seemed to like.
More on reddit.comWould something like this do what you need?
class Test(object):
def _decorator(foo):
def magic( self ) :
print "start magic"
foo( self )
print "end magic"
return magic
@_decorator
def bar( self ) :
print "normal call"
test = Test()
test.bar()
This avoids the call to self to access the decorator and leaves it hidden in the class namespace as a regular method.
>>> import stackoverflow
>>> test = stackoverflow.Test()
>>> test.bar()
start magic
normal call
end magic
>>>
edited to answer question in comments:
How to use the hidden decorator in another class
class Test(object):
def _decorator(foo):
def magic( self ) :
print "start magic"
foo( self )
print "end magic"
return magic
@_decorator
def bar( self ) :
print "normal call"
_decorator = staticmethod( _decorator )
class TestB( Test ):
@Test._decorator
def bar( self ):
print "override bar in"
super( TestB, self ).bar()
print "override bar out"
print "Normal:"
test = Test()
test.bar()
print
print "Inherited:"
b = TestB()
b.bar()
print
Output:
Normal:
start magic
normal call
end magic
Inherited:
start magic
override bar in
start magic
normal call
end magic
override bar out
end magic
What you're wanting to do isn't possible. Take, for instance, whether or not the code below looks valid:
class Test(object):
def _decorator(self, foo):
foo()
def bar(self):
pass
bar = self._decorator(bar)
It, of course, isn't valid since self isn't defined at that point. The same goes for Test as it won't be defined until the class itself is defined (which its in the process of). I'm showing you this code snippet because this is what your decorator snippet transforms into.
So, as you can see, accessing the instance in a decorator like that isn't really possible since decorators are applied during the definition of whatever function/method they are attached to and not during instantiation.
If you need class-level access, try this:
class Test(object):
@classmethod
def _decorator(cls, foo):
foo()
def bar(self):
pass
Test.bar = Test._decorator(Test.bar)
Yes. Instead of passing in the instance attribute at class definition time, check it at runtime:
def check_authorization(f):
def wrapper(*args):
print args[0].url
return f(*args)
return wrapper
class Client(object):
def __init__(self, url):
self.url = url
@check_authorization
def get(self):
print 'get'
>>> Client('http://www.google.com').get()
http://www.google.com
get
The decorator intercepts the method arguments; the first argument is the instance, so it reads the attribute off of that. You can pass in the attribute name as a string to the decorator and use getattr if you don't want to hardcode the attribute name:
def check_authorization(attribute):
def _check_authorization(f):
def wrapper(self, *args):
print getattr(self, attribute)
return f(self, *args)
return wrapper
return _check_authorization
A more concise example might be as follows:
#/usr/bin/env python3
from functools import wraps
def wrapper(method):
@wraps(method)
def _impl(self, *method_args, **method_kwargs):
method_output = method(self, *method_args, **method_kwargs)
return method_output + "!"
return _impl
class Foo:
@wrapper
def bar(self, word):
return word
f = Foo()
result = f.bar("kitty")
print(result)
Which will print:
kitty!
I could write my class like this:
class Fnord():
def __init__(self, bar:str):
self._bar = bar
@property
def bar(self) -> str:
return self._bar
@property
def BAR(self) -> str:
return self.barBut this feels a little verbose. This feels (to me, anyway) that it ought to be possible to achieve the same end with another decorator:
class Fnord():
# init method as above
@property_alias("BAR")
@property
def bar(self) -> str:
return self._barI've spent a lot of time reading about decorators and am thoroughly confused. Any help is appreciated.