oop - How can I create a copy of an object in Python? - Stack Overflow
Python copy.copy() appears to make a deep copy
[Beginner] Understanding shallow vs deep copy
copy vs deepcopy
To get a fully independent copy of an object you can use the copy.deepcopy() function.
For more details about shallow and deep copying please refer to the other answers to this question and the nice explanation in this answer to a related question.
How can I create a copy of an object in Python?
So, if I change values of the fields of the new object, the old object should not be affected by that.
You mean a mutable object then.
In Python 3, lists get a copy method (in 2, you'd use a slice to make a copy):
>>> a_list = list('abc')
>>> a_copy_of_a_list = a_list.copy()
>>> a_copy_of_a_list is a_list
False
>>> a_copy_of_a_list == a_list
True
Shallow Copies
Shallow copies are just copies of the outermost container.
list.copy is a shallow copy:
>>> list_of_dict_of_set = [{'foo': set('abc')}]
>>> lodos_copy = list_of_dict_of_set.copy()
>>> lodos_copy[0]['foo'].pop()
'c'
>>> lodos_copy
[{'foo': {'b', 'a'}}]
>>> list_of_dict_of_set
[{'foo': {'b', 'a'}}]
You don't get a copy of the interior objects. They're the same object - so when they're mutated, the change shows up in both containers.
Deep copies
Deep copies are recursive copies of each interior object.
>>> lodos_deep_copy = copy.deepcopy(list_of_dict_of_set)
>>> lodos_deep_copy[0]['foo'].add('c')
>>> lodos_deep_copy
[{'foo': {'c', 'b', 'a'}}]
>>> list_of_dict_of_set
[{'foo': {'b', 'a'}}]
Changes are not reflected in the original, only in the copy.
Immutable objects
Immutable objects do not usually need to be copied. In fact, if you try to, Python will just give you the original object:
>>> a_tuple = tuple('abc')
>>> tuple_copy_attempt = a_tuple.copy()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: 'tuple' object has no attribute 'copy'
Tuples don't even have a copy method, so let's try it with a slice:
>>> tuple_copy_attempt = a_tuple[:]
But we see it's the same object:
>>> tuple_copy_attempt is a_tuple
True
Similarly for strings:
>>> s = 'abc'
>>> s0 = s[:]
>>> s == s0
True
>>> s is s0
True
and for frozensets, even though they have a copy method:
>>> a_frozenset = frozenset('abc')
>>> frozenset_copy_attempt = a_frozenset.copy()
>>> frozenset_copy_attempt is a_frozenset
True
When to copy immutable objects
Immutable objects should be copied if you need a mutable interior object copied.
>>> tuple_of_list = [],
>>> copy_of_tuple_of_list = tuple_of_list[:]
>>> copy_of_tuple_of_list[0].append('a')
>>> copy_of_tuple_of_list
(['a'],)
>>> tuple_of_list
(['a'],)
>>> deepcopy_of_tuple_of_list = copy.deepcopy(tuple_of_list)
>>> deepcopy_of_tuple_of_list[0].append('b')
>>> deepcopy_of_tuple_of_list
(['a', 'b'],)
>>> tuple_of_list
(['a'],)
As we can see, when the interior object of the copy is mutated, the original does not change.
Custom Objects
Custom objects usually store data in a __dict__ attribute or in __slots__ (a tuple-like memory structure.)
To make a copyable object, define __copy__ (for shallow copies) and/or __deepcopy__ (for deep copies).
from copy import copy, deepcopy
class Copyable:
__slots__ = 'a', '__dict__'
def __init__(self, a, b):
self.a, self.b = a, b
def __copy__(self):
return type(self)(self.a, self.b)
def __deepcopy__(self, memo): # memo is a dict of id's to copies
id_self = id(self) # memoization avoids unnecesary recursion
_copy = memo.get(id_self)
if _copy is None:
_copy = type(self)(
deepcopy(self.a, memo),
deepcopy(self.b, memo))
memo[id_self] = _copy
return _copy
Note that deepcopy keeps a memoization dictionary of id(original) (or identity numbers) to copies. To enjoy good behavior with recursive data structures, make sure you haven't already made a copy, and if you have, return that.
So let's make an object:
>>> c1 = Copyable(1, [2])
And copy makes a shallow copy:
>>> c2 = copy(c1)
>>> c1 is c2
False
>>> c2.b.append(3)
>>> c1.b
[2, 3]
And deepcopy now makes a deep copy:
>>> c3 = deepcopy(c1)
>>> c3.b.append(4)
>>> c1.b
[2, 3]
I am following the python docs for copy functions to learn how to make a deep copy of a list or dictionary. (https://docs.python.org/3/library/copy.html) However, when I use copy.copy(list) and change one of the values it doesn't modify the original list like I thought.
Example
import copy
myL = ['first', 'second', 'third']
myLReg = copy.copy(myL)
myLReg[1] = 'new value'
console.log(myL)
What I expect the output to be is ['first', 'new value', 'third'] but I get ['first', 'second', 'third']
Am I understanding the docs wrong, is there a bug, or something else?
This is the behavior I expected from copy.deepcopy(myL)