0 and 1 are the exit codes.
exit(0) means a clean exit without any errors / problems
exit(1) means there was some issue / error / problem and that is why the program is exiting.
This is not Python specific and is pretty common. A non-zero exit code is treated as an abnormal exit, and at times, the error code indicates what the problem was. A zero error code means a successful exit.
This is useful for other programs, shell, caller etc. to know what happened with your program and proceed accordingly.
Answer from manojlds on Stack Overflow0 and 1 are the exit codes.
exit(0) means a clean exit without any errors / problems
exit(1) means there was some issue / error / problem and that is why the program is exiting.
This is not Python specific and is pretty common. A non-zero exit code is treated as an abnormal exit, and at times, the error code indicates what the problem was. A zero error code means a successful exit.
This is useful for other programs, shell, caller etc. to know what happened with your program and proceed accordingly.
This determines the exit status of the program when it finishes running (generally, 0 for success and 1 for error).
It is not unique to Python, and the exact effect depends on your operating system and how the program is called (though 99% of the time, if you're just running Python scripts, it doesn't matter).
I have dealt with the same problem, and the answer is twofold:
- The reason it's crashing could be any number of things. It's probably a programming bug, calling a function that doesn't exist, passing a widget instead of a layout, etc. But since you're not getting useful output you don't know where to look for the culprit. This is caused by:
- PyQT raises and catches exceptions, but doesn't pass them along. Instead it just exits with a status of 1 to show an exception was caught.
To catch the exceptions, you need to overwrite the sys exception handler:
# Back up the reference to the exceptionhook
sys._excepthook = sys.excepthook
def my_exception_hook(exctype, value, traceback):
# Print the error and traceback
print(exctype, value, traceback)
# Call the normal Exception hook after
sys._excepthook(exctype, value, traceback)
sys.exit(1)
# Set the exception hook to our wrapping function
sys.excepthook = my_exception_hook
Then in your execution code, wrap it in a try/catch.
try:
sys.exit(app.exec_())
except:
print("Exiting")
I had the same problem in pycharm, python 3.8, qt5. The stacktrace was never shown for qt errors inside pycharm; running the file from cmd the error was shown correctly instead.
I solved by doing the following: open Edit Configurations of the file you want to run, scroll down and check the box Emulate terminal in output console.
error code 1
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Is it better to quit a script due to a user input error using sys.exit(1) or raise Error()?
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So im pretty new to python and im trying to make a chat bot so I try installing chatter bot and I get error code 1 Running setup.py install for preshed did not run successfully. what does this mean and how do I fix it? I tried looking it up but people use lingo I dont know yet. Can anyone tell me how to fix this? that would be great thanks!
0 and 1 are exit codes, and they are not necessarily python specific, in fact they are very common.
exit code (0) means an exit without errors or issues.
exit code (1) means there was some issue / problem which caused the program to exit.
The effect of each of these codes can vary between operating systems, but with Python should be fairly consistent.
0 and 1 are exit codes.
exit code (0) means an exit without an errors or any issues, can be a compile time error or any dependency issue.
exit code (1) means there was some issue which caused the program to exit. For example if your program is running on port :8080 and that port is currently in used or not closed, then you code ends up with exit code 1
Let's say you have a script that is a simple csv parser but the user enters an invalid filepath for the csv.
Is it better to exit the script with a print("wrong filepath") and then sys.exit(1) or by using raise SomeError("wrong filepath")?
From what I read sys.exit(1) raises an exception also, but it doesn't seem to print a traceback like using raise SomeError("wrong filepath") does. So you can just print the message you want the user to see and exit quietly.
If I were to distribute a script like this to public users. What's the better practice?
In my python script I have
if failed: write_failed(failed, args) sys.exit(1)
In the bash script
#!/bin/bash niche=$1 set e python2 script.py -n $niche -ma && echo --------------------- python2 script.py -n $niche -rt -rto
I want it to exit if the first line, above the echo, fails but it is still carrying on regardless of if the first one fails.
So how to make it exit if first script call fails?
The if failed condition should be met because it prints the failed accounts as well, above in the code if failed, and that the failed account is printed.
EDIT: Also just tried putting sys.exit(1) outside that condition and run the script and still ignored by bash.
Calling sys.exit with a string will work. The docs mention this use explicitly:
In particular, sys.exit("some error message") is a quick way to exit a program when an error occurs.
To be more specific this will also result in an exit code of 1:
any other object is printed to stderr and results in an exit code of 1
There are 3 approaches, the first as lvc mentioned is using sys.exit
sys.exit('My error message')
The second way is using print, print can write almost anything including an error message
print >>sys.stderr, "fatal error" # Python 2.x
print("fatal error", file=sys.stderr) # Python 3.x
The third way is to rise an exception which I don't like because it can be try-catch
raise SystemExit('error in code want to exit')
it can be ignored like this
try:
raise SystemExit('error in code want to exit')
except:
print("program is still open")