You can get a list of all matching elements with a list comprehension:
[x for x in myList if x.n == 30] # list of all elements with .n==30
If you simply want to determine if the list contains any element that matches and do it (relatively) efficiently, you can do
def contains(list, filter):
for x in list:
if filter(x):
return True
return False
if contains(myList, lambda x: x.n == 3) # True if any element has .n==3
# do stuff
Answer from Adam Rosenfield on Stack OverflowYou can get a list of all matching elements with a list comprehension:
[x for x in myList if x.n == 30] # list of all elements with .n==30
If you simply want to determine if the list contains any element that matches and do it (relatively) efficiently, you can do
def contains(list, filter):
for x in list:
if filter(x):
return True
return False
if contains(myList, lambda x: x.n == 3) # True if any element has .n==3
# do stuff
Simple, Elegant, and Powerful:
A generator expression in conjuction with a builtinโฆ (python 2.5+)
any(x for x in mylist if x.n == 10)
Uses the Python any() builtin, which is defined as follows:
any(iterable)
->Return True if any element of the iterable is true. Equivalent to:
def any(iterable):
for element in iterable:
if element:
return True
return False
Like ok... the title said it all. For example : I have a list filled by class name Food. The class uniqueness are defined by name and price attribute. And I create a method to check if the Food is free. the question is how do I use the method to filter the list of Food class using the free checking method of food class?
@dataclass
class Food:
name : str
price : int
def isfree(self):
return self.price == 0
food_list = [Food(name = "curry", price = 5), Food(name = "sushi", price = 0)]
filtered_list = filter(Food.isfree, food_list) # got error TypeError: isfree() takes 0 positional arguments but 2 were given