The simplest and most pythonic way, I believe, is to break the strings down into individual words and scan for a match:

string = "My Name Is Josh"
substring = "Name"

for word in string.split():
    if substring == word:
        print("Match Found")

For a bonus, here's a oneliner:

any(substring == word for word in string.split())

Use the beg argument for the .find method.

counter = 0
search_pos = 0
while True:
    found = my_string.find(word, search_pos)
    if found != -1: # find returns -1 when it's not found
        #update counter and move search_pos to look for the next word
        search_pos = found + len(word)
        counter += 1
    else:
        #the word wasn't found
        break

This is kinda a general purpose solution. Specifically for counting in a string you can just use my_string.count(word)

if 'seek' in 'those who seek shall find':
    print('Success!')

but keep in mind that this matches a sequence of characters, not necessarily a whole word - for example, 'word' in 'swordsmith' is True. If you only want to match whole words, you ought to use regular expressions:

import re

def findWholeWord(w):
    return re.compile(r'\b({0})\b'.format(w), flags=re.IGNORECASE).search

findWholeWord('seek')('those who seek shall find')    # -> <match object>
findWholeWord('word')('swordsmith')                   # -> None

You could do this but there are like... 400 edge cases that will make this a problem.

text = "This is my text"
keywords = ["Lo"]
if len(set(text.split()).intersection(set(keywords))) > 0:
    print("Yes")

You can traverse the string and see if the word you want is present. In python, while handling with strings, you can use the find() function. This will give the index of the first occurance of the word.

str="Vet approved home made dog food. If I'm searching for dog food"
print(str.find("food"))

This will return the first occurance.

A way more better way to approach would be using regular expressions. You would have to import re module. THe syntax is re.search(pattern, string, flags=0)

You can later use the group() function and then find out the occurances. import re

# Target String
target_string = "et approved home made dog food"

# find substring 'dog food'
result = re.search(r"dog food", target_string)

# Print matching substring
print(result.group())

If you want to do a plain match of just one word, use ==:

'abc' == 'abc123' # false

If you're doing 'abc' in ['cde','fdabc','abc123'], that returns False anyway:

'abc' in ['cde','fdabc','abc123'] # False

The reason 'abc' in 'abc123' returns true, from the docs:

For the Unicode and string types, x in y is true if and only if x is a substring of y. An equivalent test is y.find(x) != -1.

So for comparing against a single string, use '==', and if comparing in a collection of strings, in can be used (you could also do 'abc' in ['abc123'] - since the behaviour of in works as your intuition imagines when y is a list or collection of sorts.