A few choices, in descending order of Pythonicity:

for index, item in enumerate(lst): # note: don't use list
    if not index: # or if index == 0:
        # first item
    else:
        # other items

Or:

first = True
for item in lst:
    if first:
        first = False
        # first item 
    else:
        # other items 

Or:

for index in range(len(lst)):
    item = lst[i]
    if not index:
        # first item
    else:
        # other items

Something like this should work.

for i, member in enumerate(something.get()):
    if i == 0:
         # Do thing
    # Code for everything

However, I would strongly recommend thinking about your code to see if you really have to do it this way, because it's sort of "dirty". Better would be to fetch the element that needs special handling up front, then do regular handling for all the others in the loop.

The only reason I could see for not doing it this way is for a big list you'd be getting from a generator expression (which you wouldn't want to fetch up front because it wouldn't fit in memory), or similar situations.

To display only the first element, you can use index 0

data = [['Day','Date','Week'], ['Day','Date','Week'], ['Day','Date','Week']]
print data[0]

Output

['Day','Date','Week']

You can display that in for loop like this

for x in range(10):
    print data[0]

Output

['Day', 'Date', 'Week']
['Day', 'Date', 'Week']
['Day', 'Date', 'Week']
['Day', 'Date', 'Week']
['Day', 'Date', 'Week']
['Day', 'Date', 'Week']
['Day', 'Date', 'Week']
['Day', 'Date', 'Week']
['Day', 'Date', 'Week']
['Day', 'Date', 'Week']

To get all the first elements in the inner lists

data = [['Day','Date','Week'], ['Day','Date','Week'], ['Day','Date','Week']]
print [item[0] for item in data]

Output

['Day', 'Day', 'Day']

you're looping over all the tables, but not looping over all the items in each table.

def pull_active(url):
    for i in key_data2:
        for td in i.findall('td', class_='colText'):
            label = td.find('a', class_='truncateMeTo1')
            value = td.find('td', class_='colPrimary')
            if a and col:
                stock_list.append((label.get_text(), value.get_text()))
    print(stock_list)

A simple break statement would do:

for i in range(10): 
    print(i) 
    break 

From what i understood, you want to only print the first five elements of each row?

In that case, you can iterate over the list to get the rows, and then slice the rows. An implementation of this could look something like this:

for row in allUserDetails:
for element in row[0:5]: # the rows have been sliced to only show element 0 - 5
    print(element)
print("-" * 25)

You can use slicing:

for i in x[:5]:
    print i

This will get the first five elements of a list, which you then iterate through and print each item.

It's also not recommended to do for x in x:, as you have just overwritten the list itself.

Finally, semi-colons aren't needed in python :).

Functions end as soon as a return is reached. You'll need to return once at the end instead of inside the loop:

def func1(x):
  # The string to work on
  new_str = ""

  for (a,b) in enumerate (x):
    # Add to the new string instead of returning immediately
    if a%2 == 0:
      new_str += b.upper()
    else:
      new_str += b.lower()

  # Then return the complete string
  return new_str

To skip the first element in Python you can simply write

for car in cars[1:]:
    # Do What Ever you want

or to skip the last elem

for car in cars[:-1]:
    # Do What Ever you want

You can use this concept for any sequence (not for any iterable though).