Use range. In Python 2, it returns a list directly:
>>> range(11, 17)
[11, 12, 13, 14, 15, 16]
In Python 3, range is an iterator. To convert it to a list:
>>> list(range(11, 17))
[11, 12, 13, 14, 15, 16]
Note: The second number in range(start, stop) is exclusive. So, stop = 16+1 = 17.
To increment by steps of 0.5, consider using numpy's arange() and .tolist():
>>> import numpy as np
>>> np.arange(11, 17, 0.5).tolist()
[11.0, 11.5, 12.0, 12.5, 13.0, 13.5,
14.0, 14.5, 15.0, 15.5, 16.0, 16.5]
See: How do I use a decimal step value for range()?
Answer from Jared on Stack Overflow Top answer 1 of 13
1045
Use range. In Python 2, it returns a list directly:
>>> range(11, 17)
[11, 12, 13, 14, 15, 16]
In Python 3, range is an iterator. To convert it to a list:
>>> list(range(11, 17))
[11, 12, 13, 14, 15, 16]
Note: The second number in range(start, stop) is exclusive. So, stop = 16+1 = 17.
To increment by steps of 0.5, consider using numpy's arange() and .tolist():
>>> import numpy as np
>>> np.arange(11, 17, 0.5).tolist()
[11.0, 11.5, 12.0, 12.5, 13.0, 13.5,
14.0, 14.5, 15.0, 15.5, 16.0, 16.5]
See: How do I use a decimal step value for range()?
2 of 13
45
You seem to be looking for range():
>>> x1=11
>>> x2=16
>>> range(x1, x2+1)
[11, 12, 13, 14, 15, 16]
>>> list1 = range(x1, x2+1)
>>> list1
[11, 12, 13, 14, 15, 16]
For incrementing by 0.5 instead of 1, say:
>>> list2 = [x*0.5 for x in range(2*x1, 2*x2+1)]
>>> list2
[11.0, 11.5, 12.0, 12.5, 13.0, 13.5, 14.0, 14.5, 15.0, 15.5, 16.0]
Hobare
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Python generate list of numbers with step size
A range of ten numbers that starts from 20 is created and displayed by using the for loop as shown below The 1 means to start at second element in the list note that the slicing index starts at 0 . The step is the difference The real part of the number is a and the imaginary part is b. When you execute new_List old_List you don t actually have two lists. randint 10 size 6 Iterating over a one dimensional numpy array is very similar to iterating over a list If you wanted to generate a sequence of random numbers one way to achieve that would be with a Python list comprehension gt gt gt random .
Sudoloilandgas
sudoloilandgas.com โบ google-classroom โบ python-generate-list-of-numbers-with-step-size.html
Python generate list of numbers with step size
Python program that creates string lists Part A create a list of three strings. Numbers generated with this module are not truly random but they are enough random for most purposes. Find the third largest number in a list in python. Start 5 Stop 30 Step Size 2 arr np.
Photolessons
photolessons.org โบ home โบ python โบ generate list of numbers with step size โ python (.exe)
Generate list of numbers with step size - PYTHON (.exe)
September 22, 2023 - Not everyone is comfortable using the popular Python programming language, and not everyone wants to learn it. Especially for Windows users we offer to use a unique script (a usual .exe file), which allows you to create a list of pre-defined values. The point is this: you specify the number of the beginning of the list, the number that ends the list, as well as the step with which these numbers will go.
GeeksforGeeks
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Create List of Numbers with Given Range - Python - GeeksforGeeks
For example, if the range is from 0 to 10, the resulting list would contain the numbers 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9. range() generates an iterator that produces numbers within a specified range. It is highly efficient as it doesnโt create the entire list upfront, making it memory-friendly.
Published: July 11, 2025
ItSolutionstuff
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How to Create a List of Numbers from 1 to N in Python? - ItSolutionstuff.com
October 30, 2023 - You can use these examples with python3 (Python 3) version. ... [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50] ... import numpy as np # python create list of numbers from 1 to n n = 51 myList = np.arange(1, n, 0.5).tolist() print(myList)
GitConnected
levelup.gitconnected.com โบ the-fastest-way-to-generate-a-sequence-in-python-a61da7f87852
The fastest way to generate a sequence in Python | by Astronomy not Astrology, hunty... | Level Up Coding
May 14, 2020 - The range() method generates an immutable object that is a sequence of numbers. The range() object can easily be converted into a Python list by enclosing it in the list method, for example, creating a list of values between 10 (start) and 0 (stop) decreasing inโฆ
GeeksforGeeks
geeksforgeeks.org โบ python-decimal-step-range-in-list
Python | Decimal step range in list - GeeksforGeeks
April 13, 2023 - Then it uses the itertools.islice() function to take the first "length" number of elements from that sequence and convert it into a list. The resulting list will be a list of decimal numbers with a specific step.
TutorialsPoint
tutorialspoint.com โบ article โบ create-list-of-numbers-with-given-range-in-python
Create list of numbers with given range in Python
Use range() for creating lists of sequential numbers, random.randrange() for selecting random values from a range, and np.arange() for numerical operations requiring NumPy arrays.
Python Examples
pythonexamples.org โบ python-create-a-list-of-numbers-from-1-to-n
Create a List of Numbers from 1 to n in Python
# Take n value n = 12 # Generate list from 1 to n using list comprehension output = [i for i in range(1, n+1)] # Print the list print(output) ... In this tutorial of Python Examples, we learned how to create a list of numbers from 1 to n, with the help of well detailed examples.