Given your data structure:

>>> [item for item in accounts if item.get('id')==2]
[{'title': 'Gow to get this one?', 'id': 2}]

If item does not exist:

>>> [item for item in accounts if item.get('id')==10]
[]

That being said, if you have opportunity to do so, you might rethink your datastucture:

accounts = {
    1: {
        'title': 'Example Account 1'
    },
    2: {
        'title': 'Gow to get this one?'
    },
    3: {
        'title': 'Example Account 3'
    }
}

You might then be able to access you data directly by indexing their id or using get() depending how you want to deal with non-existent keys.

>>> accounts[2]
{'title': 'Gow to get this one?'}

>>> accounts[10]
Traceback (most recent call last):
  File "<input>", line 1, in <module>
KeyError: 10

>>> accounts.get(2)
{'title': 'Gow to get this one?'}
>>> accounts.get(10)
# None

You need to traverse the list and look at each of the objects.

If you expect one match, you can use next with a generator expression:

res = next((i.value for i in mylist if i.url == 'http://2'), None)

print(res)
# 2

If you expect multiple matches, you can use a list comprehension:

res = [i.value for i in mylist if i.url == 'http://2']

print(res)
# [2]

According to documentation db.get may accept list of keys and fetch them in a single batch, which will be much faster.

list_of_objects = db.get(list_of_keys)

next((x for x in test_list if x.value == value), None)

This gets the first item from the list that matches the condition, and returns None if no item matches. It's my preferred single-expression form.

However,

for x in test_list:
    if x.value == value:
        print("i found it!")
        break

The naive loop-break version, is perfectly Pythonic -- it's concise, clear, and efficient. To make it match the behavior of the one-liner:

for x in test_list:
    if x.value == value:
        print("i found it!")
        break
else:
    x = None

This will assign None to x if you don't break out of the loop.

This is a simple for loop to check each item in list if the id of its details is equal to the value which you mentioned: 101841_2004497

for item in list:
    if item["details"]["id"] == "101841_2004497":
        print(item["details"])

JSON response:

{'text': 'Old', 'type': 'SPT_0006', 'id': '101841_2004497'}

Hope it helps!

my_item = next((item for item in my_list if item['id'] == my_unique_id), None)

This iterates through the list until it finds the first item matching my_unique_id, then stops. It doesn't store any intermediate lists in memory (by using a generator expression) or require an explicit loop. It sets my_item to None of no object is found. It's approximately the same as

for item in my_list:
    if item['id'] == my_unique_id:
        my_item = item
        break
else:
    my_item = None

else clauses on for loops are used when the loop is not ended by a break statement.

Assuming your dictionaries always have a single key,value pair that you are extracting, you could use two list comprehensions:

l1 = [d.values()[0] for d in dividends]
# ['2005', '2006', '2007', '2008', '2009', '2010', '2011', '2012', '2013', '2014', '2015']

l2 = [d.keys()[0] for d in dividends]
# [0.18, 0.21, 0.26, 0.31, 0.34, 0.38, 0.38, 0.38, 0.38, 0.415, 0.427]