To convert an integer to a binary string in Python, use the built-in bin() function. It returns a string prefixed with '0b' to indicate binary format.
num = 10
binary = bin(num)
print(binary) # Output: '0b1010'To remove the '0b' prefix, use string slicing:
binary_no_prefix = bin(num)[2:]
print(binary_no_prefix) # Output: '1010'For more control over formatting (like padding with leading zeros), use format() or f-strings:
# Using format()
binary_padded = format(num, '08b') # 8-bit binary with leading zeros
print(binary_padded) # Output: '00001010'
# Using f-strings
binary_padded = f'{num:08b}'
print(binary_padded) # Output: '00001010'Note: bin() works only with integers. For negative numbers, Python uses two's complement notation, so the output includes a negative sign (e.g., -0b1010 for -10).
Python's string format method can take a format spec.
>>> "{0:b}".format(37)
'100101'
Format spec docs for Python 2
Format spec docs for Python 3
Answer from Tung Nguyen on Stack OverflowHow to convert an integer into a binary number without the specific function?
python - Convert base-2 binary number string to int - Stack Overflow
Converting integer to binary in Python - Stack Overflow
I have a byte, I want to extract the bits (from MSB to LSB). What is the 'Python' way to do this (use a bytearray)?
I would use something like the following, but I'm not sure python is the best language for doing this sort of bit manipulation in. There are some C-based libraries that implement this you could look at.
output = [input & 1<<x > 0 for x in range(input.bit_length())]More on reddit.com
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Hello,
I'm fairly new and I wanted to challenge myself by trying to convert an integer into a binary number (up until 256). I'd use the functions like if, elif else and while. I'd also use some math and some string operations. I've tried, but it feels like I'm stuck.
Here's what I have so far:
def convert_number_into_binary(number):
assert number <= 256
binary = ""
for i in range(8,-1):
while number != 0:
if number - 2 ** i == 0:
binary = "0" * (8 - i) + str(10 ** i)
return binary
elif number - 2 ** i != 0:
if 2**i > number: binary += "0"
elif 2**i < number: number -= 2**i binary += "1"
sorry for the lack of indents, I don't know how to transfer the code properly from Python to Reddit.
Thanks in advance
>>> '{0:08b}'.format(6)
'00000110'
Just to explain the parts of the formatting string:
{}places a variable into a string0takes the variable at argument position 0:adds formatting options for this variable (otherwise it would represent decimal6)08formats the number to eight digits zero-padded on the leftbconverts the number to its binary representation
If you're using a version of Python 3.6 or above, you can also use f-strings:
>>> f'{6:08b}'
'00000110'
Just another idea:
>>> bin(6)[2:].zfill(8)
'00000110'
Shorter way via string interpolation (Python 3.6+):
>>> f'{6:08b}'
'00000110'