Empty strings are "falsy" (python 2 or python 3 reference), which means they are considered false in a Boolean context, so you can just do this:
if not myString:
This is the preferred way if you know that your variable is a string. If your variable could also be some other type then you should use:
if myString == "":
See the documentation on Truth Value Testing for other values that are false in Boolean contexts.
Answer from Andrew Clark on Stack OverflowHow to check if the string is empty in Python? - Stack Overflow
What's the most pythonic way of checking if variable is None or empty string ""?
empty string returns True upon checking if its contained in a non empty string
In Java, should I use (String ) isEmpty() or isBlank() when checking an XML object for an empty value?
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Empty strings are "falsy" (python 2 or python 3 reference), which means they are considered false in a Boolean context, so you can just do this:
if not myString:
This is the preferred way if you know that your variable is a string. If your variable could also be some other type then you should use:
if myString == "":
See the documentation on Truth Value Testing for other values that are false in Boolean contexts.
From PEP 8, in the “Programming Recommendations” section:
For sequences, (strings, lists, tuples), use the fact that empty sequences are false.
So you should use:
if not some_string:
or:
if some_string:
Just to clarify, sequences are evaluated to False or True in a Boolean context if they are empty or not. They are not equal to False or True.
I'm trying to constantly check against any of those values but I don't want to keep repeating myself in code.
if variable is None or variable == "": do stuff
What are my options? Can I create somehow a class and check against that class?
if variable is MyNewClass: do stuff
How would I write such a class?
Thanks!
This code is meant to count all the words that have the expression "di" but with the text "imagina." the final answer is 1.
texto = 'imagina.'
cl = 0
flag_di = False
answer = 0
previous = ''
for car in texto:
if car != ' ' and car != '.':
cl += 1
if car in 'iI' and previous in 'dD':
flag_di = True
previous = car
else:
if car == ' ' or car == '.':
if flag_di:
answer += 1
cl = 0
flag_di = False
previous = ''
print(answer)