Your input appears to be a sequence of Python objects; it certainly is not valid a JSON document.

If you have a list of Python dictionaries, then all you have to do is dump each entry into a file separately, followed by a newline:

import json

with open('output.jsonl', 'w') as outfile:
    for entry in JSON_file:
        json.dump(entry, outfile)
        outfile.write('\n')

The default configuration for the json module is to output JSON without newlines embedded.

Assuming your A, B and C names are really strings, that would produce:

{"index": 1, "met": "1043205", "no": "A"}
{"index": 2, "met": "000031043206", "no": "B"}
{"index": 3, "met": "0031043207", "no": "C"}

If you started with a JSON document containing a list of entries, just parse that document first with json.load()/json.loads().

Your question is a little unclear. If you're generating hostDict in a loop:

with open('data.txt', 'a') as outfile:
    for hostDict in ....:
        json.dump(hostDict, outfile)
        outfile.write('\n')

If you mean you want each variable within hostDict to be on a new line:

with open('data.txt', 'a') as outfile:
    json.dump(hostDict, outfile, indent=2)

When the indent keyword argument is set it automatically adds newlines.