Use with AIfor i in range(15):
print i #will print out 0..14
for i in range(1, 15):
print i # will print out 1..14
for i in range (a, b, s):
print i # will print a..b-1 counting by s. interestingly if while counting by the step 's' you exceed b, it will stop at the last 'reachable' number, example
for i in range(1, 10, 3):
print i
> 1
> 4
> 7
List Splicing:
Use with AIa = "hello" # there are 5 characters, so the characters are accessible on indexes 0..4
a[1] = 'e'
a[1:2] = 'e' # because the number after the colon is not reached.
a[x:y] = all characters starting from the character AT index 'x' and ending at the character which is before 'y'
a[x:] = all characters starting from x and to the end of the string
In the future, if you ever wonder what the behavior of python is like, you can try it out in the python shell. just type python in the terminal and you can enter any lines you want (though this is mostly convenient for one-liners rather than scripts).
Answer from Jeremy Fisher on Stack OverflowUse with AIfor i in range(15):
print i #will print out 0..14
for i in range(1, 15):
print i # will print out 1..14
for i in range (a, b, s):
print i # will print a..b-1 counting by s. interestingly if while counting by the step 's' you exceed b, it will stop at the last 'reachable' number, example
for i in range(1, 10, 3):
print i
> 1
> 4
> 7
List Splicing:
Use with AIa = "hello" # there are 5 characters, so the characters are accessible on indexes 0..4
a[1] = 'e'
a[1:2] = 'e' # because the number after the colon is not reached.
a[x:y] = all characters starting from the character AT index 'x' and ending at the character which is before 'y'
a[x:] = all characters starting from x and to the end of the string
In the future, if you ever wonder what the behavior of python is like, you can try it out in the python shell. just type python in the terminal and you can enter any lines you want (though this is mostly convenient for one-liners rather than scripts).
The best way to clarify such doubts is to play with the REPL:
Use with AI>>> range(10)
range(0, 10)
>>> list(range(10))
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> x = list(range(10))
>>> x[:3]
[0, 1, 2]
>>> x[:1]
[0]
>>> x[1:10]
[1, 2, 3, 4, 5, 6, 7, 8, 9]
Is range(len(list)) ever Pythonic?
python - how to extract a range of index from a list - Stack Overflow
Droping data with range of negitive indexes
python - Why can't a range object be used to index a list? - Stack Overflow
What is the "list index out of range" error?
The "list index out of range" error occurs when you try to access an index that is outside the range of valid indices for a list. For example, if a list has 5 elements, the valid indices are 0 to 4. If you try to access an index greater than or equal to 5, you will get this error.
To avoid the "list index out of range" error, you should make sure that the index you are trying to access is within the range of valid indices for the list. You can use the len() function to get the length of a list and check if an index is within the range of valid indices.
What is the "list indices must be integers" error?
The "list indices must be integers" error occurs when you try to use a non-integer value as a list index. For example, if you try to use a floating-point number or a string as a list index, you will get this error.
To avoid the "list indices must be integers" error, you should make sure that you are using an integer value as a list index. If you need to use a non-integer value as an index, you can convert it to an integer using the int() function.
How is index() different from find()?
The find() method is used with strings and returns -1 instead of raising an error when the value is not found. Lists do not have a find() method.
text = "hello"
print(text.find('e')) # Output: 1
print(text.find('z')) # Output: -1
Are there circumstances where for i in range(len(my_list)): is to be preferred over for i, _ in enumerate(my_list):? If so, what are they, generally speaking?
Edited to fix syntax.
One alternative is to do:
mylist1 = [11, 4, 5, 6, 8, 6, 3]
for i in mylist1:
a = list(range(i))
print(a[-2:] + a[:2])
Output
[9, 10, 0, 1]
[2, 3, 0, 1]
[3, 4, 0, 1]
[4, 5, 0, 1]
[6, 7, 0, 1]
[4, 5, 0, 1]
[1, 2, 0, 1]
You could try something like this:
list1 = [0, 1, 2, 3, 4, 5]
for ln in range(1, len(list1)):
list2 = [list1[n] for n in range(-ln, ln)] #magic line
print(list2)
or you could also try this instead of the magic line:
list2 = list1[ln:] + list1[:ln]
Where ln is the number of elements you want from the end and the beginning of the list.