You are first adding R0Cx and then R1Cxy. You need to add RxCy. So try:

newlist = []
row = A
col = B
for x in range (0, row): 
  newlist.append([])

  for y in range(0, col):
    newlist[x].append('R' + str(x) + 'C' + str(y))

print(newlist)
Answer from Sefe on Stack Overflow
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Stack Overflow
stackoverflow.com › questions › 47422148 › create-a-list-with-certain-number-of-rows-and-columns-in-python
Create a list with certain number of rows and columns in Python - Stack Overflow
Top answer
1 of 3
5

You are first adding R0Cx and then R1Cxy. You need to add RxCy. So try:

newlist = []
row = A
col = B
for x in range (0, row): 
  newlist.append([])

  for y in range(0, col):
    newlist[x].append('R' + str(x) + 'C' + str(y))

print(newlist)
2 of 3
0

You have to fill columns in a row while still in that row:

rows = []
row = 2
col = 3

for x in range(0, row):
    columns = []
    for y in range(0, col):
        columns.append('R' + str(x) + 'C' + str(y))

    rows.append(columns)


print(rows)

will print:

[['R0C0', 'R0C1', 'R0C2'], ['R1C0', 'R1C1', 'R1C2']]

python - using a specific row to create a new list
Adding columns to list in python
python - How to create a table using a list of lists
python - Creating a list based on column conditions
python - Loop for creating multiple list
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Profound Academy
profound.academy › python-introduction › multi-line-lists-BLTEtz0sDYdm0zAjIB7S
multi-line lists • Introduction to Python
November 2, 2024 - Both of these list declarations are valid. It’s not mandatory to have all elements on the same line. As long as there is an opening and closing brackets [], everything in between separated by commas is considered part of the list.
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Look up a list of different values and return all rows in dataset that has one of these values in a given column?
You can use isin(). df[df['Number'].isin(my_list)] More on reddit.com
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geeksforgeeks.org › python › python-rows-with-all-list-elements
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Stack Overflow
stackoverflow.com › questions › 58170112 › how-to-insert-multiple-rows-from-list-with-python
pyodbc - how to insert multiple rows from list with Python - Stack Overflow
Top answer
1 of 1
3

Don't append a string, just append a tuple:

valuesToInsert.append((fileName,tree.find('PNumber').text,tree.find('PNumber2').text))
Find elsewhere
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Stack Overflow
stackoverflow.com › questions › 50324565 › python-write-multiple-lists-to-multiple-rows-in-csv
Python: write multiple lists to multiple rows in csv - Stack Overflow
Top answer
1 of 2
1

You may want to add linebreak to every ending of row. You can do so by typing for example:

file.write('\n')
2 of 2
0

The csv module from standard library provides objects to read and write CSV files. In your case, you could do:

import csv
for i in range(10):
    final = [i*1, i*2, i*3]
    with open("0514test.csv", "a", newline="") as file:
        writer = csv.writer(file)
        writer.writerow(final)

Using this module is often safer in real life situations because it takes care of all the CSV machinery (adding delimiters like " or ', managing the cases in which your separator is also present in your data etc.)

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Stack Overflow
stackoverflow.com › questions › 51051381 › assign-multiple-values-from-a-list-by-oder-for-multiple-rows-in-dataframe
python - Assign multiple values from a list, by oder ,for multiple rows in dataframe - Stack Overflow
Top answer
1 of 1
1

Without modifying too much of your code, I was able to use the enumerate() function instead of your i loop. I am using Python 3. 

import pandas as pd 
import numpy as np 
# create sample dataframe
abc = ['a','b','c','d','e', 'f']
data = {'Text':['foo', 'bar', 'spam', 'eggs', 'ham', 'asdf'],
        'Number':[2, 2, 5, 2, 2, 3]}
df = pd.DataFrame.from_dict(data) 
df = df[['Text', 'Number']] # reordering df
print(df)

# Original question code:
# i=0
# for row1 in range(0,len(df)):
#     if df.iloc[row1]['Number']==2:
#         df.set_value(df.index[row1], 'Text',abc[i])
#         i=i+1

# Pseudocode: 
# if row value for the column 'number' is 2:
#     set the value for the column 'text' at an index to the value for abc[index]
for idx, row1 in enumerate(range(0, len(df))):
    if df.iloc[row1]['Number'] == 2:
        df.set_value(df.index[row1], 'Text', abc[idx])
print(df)

Please note that set_value is depreciated and will be removed in a future release.

Results:

    text  number
0     a       2
1     b       2
2  spam       5
3     d       2
4     e       2
5  asdf       3

FutureWarning: set_value is deprecated and will be removed in a future release. Please use .at[] or .iat[] accessors instead
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Reddit
reddit.com › r/learnpython › look up a list of different values and return all rows in dataset that has one of these values in a given column?
r/learnpython on Reddit: Look up a list of different values and return all rows in dataset that has one of these values in a given column?
October 22, 2023 -

I have a big data set, and I want to extract all rows that has certain values in one of the columns

Let's say I have 1000 rows, with 3 columns:

| Customer | Product | Number |

And I have a separate list of numbers (will match numbers found in column 3):

406597

504305

340405

305522

203400

Can I use python go through this separate list and return all rows from the dataset that matches either one of these numbers?

Top answer
1 of 1
3
You can use isin(). df[df['Number'].isin(my_list)]
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Reddit
reddit.com › r/learnpython › how can i print different items of a list in multiple lines?
r/learnpython on Reddit: how can I print different items of a list in multiple lines?
March 19, 2021 -

I am trying to create a chart in python using lists. I have a nested list (I think)

list = [[1, 2, 3], [4, 5, 6], [7,8,9]]

what I am trying to do is have each list in a different line so I want the output to be

1, 2, 3

4, 5, 6

7, 8, 9

so they are all in different lines and I have now created a 3x3 grid and i can access each number using its index which i think for example if I wanted to access the 5 on the middle of my chart I would do

[1][1]

row 2, position 2

(I used [1] because row 1 would be [0] and row 3 [2] (I believe))

the problem I have is that it prints it all in one single line so I am not able to create a 2d chart.

how would I create the chart using this method (or any other method sugested by you) and how would i acces each position and change its value (so for example if i wanted to access the position where the 5 currently is and turn it to a 7 so i would get

1, 2, 3

4, 7, 6

7, 8, 9

thanks.

Top answer
1 of 3
2
Several others have given similar responses. Here is another take, provided that you want to be able to format the items individually when printing them: chart = [[1, 2, 3], [4, 5, 6], [7,8,9]] def print_my_chart(chart): for line in chart: for item in line: print(f"{item}\t", end='') print("") print(f"Chart before change of 5") print_my_chart(chart) chart[1][1] = 7 print(f"Chart before change of 5 to 7") print_my_chart(chart) This will print like this: Chart before change of 5 1 2 3 4 5 6 7 8 9 Chart before change of 5 to 7 1 2 3 4 7 6 7 8 9 Also, strongly avoid naming a 'list' list. 'list' is a Python keyword and results will be different than expected.
2 of 3
1
To print each sublist on a different line just use a for loop: lst = [[1, 2, 3], [4, 5, 6], [7, 8, 9]] for sublist in list: print(sublist)
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GeeksforGeeks
geeksforgeeks.org › python › multi-dimensional-lists-in-python
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October 30, 2025 - In Python, a Multi-dimensional List is a list containing other lists, often used to represent structured data like matrices, tables or 2D arrays. It’s useful for storing and accessing data in rows and columns, commonly applied in data analysis, ...
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Stack Overflow
stackoverflow.com › questions › 40569402 › pandas-create-several-rows-from-column-that-is-a-list
Pandas: Create several rows from column that is a list - Stack Overflow
Top answer
1 of 1
1
import itertools
import pandas as pd
import numpy as np

def melt_series(s):
    lengths = s.str.len().values
    flat = [i for i in itertools.chain.from_iterable(s.values.tolist())]
    idx = np.repeat(s.index.values, lengths)
    return pd.Series(flat, idx, name=s.name)


melt_series(df.type).to_frame().join(df.drop('type', 1)).reindex_axis(df.columns, 1)

setup

df = pd.DataFrame({'key':[1,2,3],
                   'type':[[1,3],[1,2,3],[1,2]],
                   'value':[5,1,8]})
df

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Stack Overflow
stackoverflow.com › questions › 49147996 › explode-column-of-list-to-multiple-rows
python - Explode column of list to multiple rows - Stack Overflow
Top answer
1 of 2
8

Pandas >= 0.25

Pandas can do this in a single function call via df.explode.

df.explode('column_x')

  column_a column_b column_x
0      a_1      b_1      c_1
0      a_1      b_1      c_2
1      a_2      b_2      d_1
1      a_2      b_2      d_2

Note that you can only explode a Series/DataFrame on one column.

Pandas < 0.25

Call np.repeat along the 0th axis for every column besides column_x.

df1 = pd.DataFrame(
    df.drop('column_x', 1).values.repeat(df['column_x'].str.len(), axis=0),
    columns=df.columns.difference(['column_x'])
)
df1['column_x'] = np.concatenate(df['column_x'].values)

df1

  column_a column_b column_x
0      a_1      b_1      c_1
1      a_1      b_1      c_2
2      a_2      b_2      d_1
3      a_2      b_2      d_2
2 of 2
2

You can repeat index values:

lens = df['column_x'].str.len()
a = np.repeat(df.index.values, lens)
print (a)
[0 0 1 1]

df = df.loc[a].assign(column_x=np.concatenate(df['column_x'].values)).reset_index(drop=True)
print (df)
  column_a column_b column_x
0      a_1      b_1      c_1
1      a_1      b_1      c_2
2      a_2      b_2      d_1
3      a_2      b_2      d_2
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stackoverflow.com › questions › 61987311 › looping-over-a-nested-list-with-multiple-rows-and-columns
python - looping over a nested list with multiple rows and columns - Stack Overflow
Instead of replacing the data, the elegant approach in Python is to create new data, using comprehensions: def with_nones_replaced(grid, replacement): return [ [ replacement if value is None else value for value in row ] for row in grid ] ... Sign up to request clarification or add additional context in comments. ... I have forgot to mention that I want to replace the data in the same list ...
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TutorialsPoint
tutorialspoint.com › python-rows-with-all-list-elements
Python – Rows with all List elements
my_list = [[8, 6, 3, 2], [1, 6], [2, 1,7], [8, 1, 2]] print("The list is :") print(my_list) sub_list = [1, 2] result = [] for row in my_list: flag = True for element in sub_list: if element not in row: flag = False if flag: result.append(row) print("The resultant list is :") print(result) The list is : [[8, 6, 3, 2], [1, 6], [2, 1, 7], [8, 1, 2]] The resultant list is : [[2, 1, 7], [8, 1, 2]] A list of list is defined and is displayed on the console. Another list with integer values is defined.
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Stack Overflow
stackoverflow.com › questions › 43658289 › store-a-number-of-list-together-in-rows-so-i-can-call-every-row-and-make-manipul
python - store a number of list together in rows so i can call every row and make manipulations - Stack Overflow
That is not valid python. ... i know , this is just part of my code, i just need to ask how can i store multiple rows together so that i can perform airthmetic operations to my rows ... from random import randint points = [] for i in range(8): points.append([randint(0, 10) for i in range(3)]) # now possible to access point i by points[i] print(points) ... Find the answer to your question by asking. Ask question ... See similar questions with these tags.
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Stack Overflow
stackoverflow.com › questions › 61447877 › python-split-list-into-several-lines-of-code
Python split list into several lines of code - Stack Overflow
Top answer
1 of 4
14

The first line should contain the first element, like this: 

list_of_elements = ['AA',
'BB',
'CC',
'DD',
'EE',
'FF', 
'GG']

or as Naufan Rusyda Faikar commented: Put backslash next to = Or put the left bracket next to =.

list_of_elements = \
['AA',
'BB',
'CC',
'DD',
'EE',
'FF', 
'GG']

list_of_elements = [
'AA',
'BB',
'CC',
'DD',
'EE',
'FF', 
'GG']

All three will work.

2 of 4
2

The best option :

list_of_elements =\
[
'AA',
'BB',
'CC',
'DD',
'EE',
'FF', 
'GG'
]
🌐
Medium
ianh6ll6n.medium.com › expanding-a-pandas-list-column-to-rows-41c69aaf9488
Expanding a pandas list column to rows | by Ian Hellen | Medium
March 19, 2021 - If the input data has rows with different numbers of list elements, we end up with Python None objects all over the place. We need to get rid of these but pandas doesn’t have any clever way of dropping them efficiently (as it can with NaN values). The pandas replace function can sort this out for us.