When you define your function using this syntax:
def someFunc(*args):
for x in args
print x
You're telling it that you expect a variable number of arguments. If you want to pass in a List (Array from other languages) you'd do something like this:
def someFunc(myList = [], *args):
for x in myList:
print x
Then you can call it with this:
items = [1,2,3,4,5]
someFunc(items)
You need to define named arguments before variable arguments, and variable arguments before keyword arguments. You can also have this:
def someFunc(arg1, arg2, arg3, *args, **kwargs):
for x in args
print x
Which requires at least three arguments, and supports variable numbers of other arguments and keyword arguments.
Answer from g.d.d.c on Stack Overflowpassing a list as function arguments
python - How to pass list elements as arguments - Stack Overflow
python - Converting list to *args when calling function - Stack Overflow
When to use *args and when to take a list as argument?
Videos
When you define your function using this syntax:
def someFunc(*args):
for x in args
print x
You're telling it that you expect a variable number of arguments. If you want to pass in a List (Array from other languages) you'd do something like this:
def someFunc(myList = [], *args):
for x in myList:
print x
Then you can call it with this:
items = [1,2,3,4,5]
someFunc(items)
You need to define named arguments before variable arguments, and variable arguments before keyword arguments. You can also have this:
def someFunc(arg1, arg2, arg3, *args, **kwargs):
for x in args
print x
Which requires at least three arguments, and supports variable numbers of other arguments and keyword arguments.
You can pass lists just like other types:
l = [1,2,3]
def stuff(a):
for x in a:
print a
stuff(l)
This prints the list l. Keep in mind lists are passed as references not as a deep copy.
plants escape snatch angle bedroom liquid oatmeal library flag touch
This post was mass deleted and anonymized with Redact
You can use the * operator before an iterable to expand it within the function call. For example:
timeseries_list = [timeseries1 timeseries2 ...]
r = scikits.timeseries.lib.reportlib.Report(*timeseries_list)
(notice the * before timeseries_list)
From the python documentation:
If the syntax *expression appears in the function call, expression must evaluate to an iterable. Elements from this iterable are treated as if they were additional positional arguments; if there are positional arguments x1, ..., xN, and expression evaluates to a sequence y1, ..., yM, this is equivalent to a call with M+N positional arguments x1, ..., xN, y1, ..., yM.
This is also covered in the python tutorial, in a section titled Unpacking argument lists, where it also shows how to do a similar thing with dictionaries for keyword arguments with the ** operator.
yes, using *arg passing args to a function will make python unpack the values in arg and pass it to the function.
so:
>>> def printer(*args):
print args
>>> printer(2,3,4)
(2, 3, 4)
>>> printer(*range(2, 5))
(2, 3, 4)
>>> printer(range(2, 5))
([2, 3, 4],)
>>>