Just for completeness, using the modern .format() syntax:

>>> numbers = [1, 15, 255]
>>> ''.join('{:02X}'.format(a) for a in numbers)
'010FFF'

You mean you have a string of bytes in my_hex which you want to print out as hex numbers, right? E.g., let's take your example:

>>> my_string = "deadbeef"
>>> my_hex = my_string.decode('hex')  # python 2 only
>>> print my_hex
Þ ­ ¾ ï

This construction only works on Python 2; but you could write the same string as a literal, in either Python 2 or Python 3, like this:

my_hex = "\xde\xad\xbe\xef"

So, to the answer. Here's one way to print the bytes as hex integers:

>>> print " ".join(hex(ord(n)) for n in my_hex)
0xde 0xad 0xbe 0xef

The comprehension breaks the string into bytes, ord() converts each byte to the corresponding integer, and hex() formats each integer in the from 0x##. Then we add spaces in between.

Bonus: If you use this method with unicode strings (or Python 3 strings), the comprehension will give you unicode characters (not bytes), and you'll get the appropriate hex values even if they're larger than two digits.

Addendum: Byte strings

In Python 3 it is more likely you'll want to do this with a byte string; in that case, the comprehension already returns ints, so you have to leave out the ord() part and simply call hex() on them:

>>> my_hex = b'\xde\xad\xbe\xef'
>>> print(" ".join(hex(n) for n in my_hex))
0xde 0xad 0xbe 0xef

print hex(value)

Just cast it to a hex value as you print it

You can transform your string to an integer generator. Apply hexadecimal formatting for each element and intercalate with a separator:

>>> s = "Hello, World!"
>>> ":".join("{:02x}".format(ord(c)) for c in s)
'48:65:6c:6c:6f:2c:20:57:6f:72:6c:64:21

hex(mem32[0xE000E400] & 0xffffffff)