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stackoverflow.com › questions › 7267226 › range-for-floats

You can either use:

[x / 10.0 for x in range(5, 50, 15)]

or use lambda / map:

map(lambda x: x/10.0, range(5, 50, 15))

Answer from Grzegorz Rożniecki on Stack Overflow

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stackoverflow.com › questions › 7267226 › range-for-floats

python - range() for floats - Stack Overflow

Top answer

1 of 16

185

You can either use:

[x / 10.0 for x in range(5, 50, 15)]

or use lambda / map:

map(lambda x: x/10.0, range(5, 50, 15))

2 of 16

117

I don't know a built-in function, but writing one like this shouldn't be too complicated.

def frange(x, y, jump):
  while x < y:
    yield x
    x += jump

---

As the comments mention, this could produce unpredictable results like:

>>> list(frange(0, 100, 0.1))[-1]
99.9999999999986

To get the expected result, you can use one of the other answers in this question, or as @Tadhg mentioned, you can use decimal.Decimal as the jump argument. Make sure to initialize it with a string rather than a float.

>>> import decimal
>>> list(frange(0, 100, decimal.Decimal('0.1')))[-1]
Decimal('99.9')

Or even:

import decimal

def drange(x, y, jump):
  while x < y:
    yield float(x)
    x += decimal.Decimal(jump)

And then:

>>> list(drange(0, 100, '0.1'))[-1]
99.9

[editor's not: if you only use positive jump and integer start and stop (x and y) , this works fine. For a more general solution see here.]

Codingem

codingem.com › home › range of floats in python: a step-by-step guide (3 ways to do it)

Range of Floats in Python: A Step-by-Step Guide (3 Ways to Do It)

November 1, 2022 - To create a range of floats in Python, use a list comprehension. For example: [(x/10) for x in range(0, 5)] returns [0.0, 0.1, 0.2, 0.3, 0.4]

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I have found that checking if a float number falls inside a range() doesn’t work, always giving False: >>> 1.0 in range (0, 2) True >>> 1.5 in range (0, 2) False I can understand that range() can only accept integer values, but checking if it contains a float number should works. More on discuss.python.org

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Yes, range(0, 101) literally gives the integers from 0 to 100. If you want to know if a number is between two values, use a chained comparison: while 0 <= score < 101: Although note you shouldn't get an actual error, just a False. What exact error message did you see? More on reddit.com

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A somewhat “hacky” way to accomplish this using range directly is by multiplying start/end/step by a power of 10 so they’re all integers, then dividing by that same power in your loop. Do note that range doesn’t include the right endpoint. e.g. for degrees in range(0,3600,225): print(degrees/10) You could also form the step-size on your own and use range to get a multiple of it. E.g. if I wanted to cut [1,2] into 17 pieces, I could do for multiple in range(18): x = 1+(multiple/17) print(x) or just use numpy.linspace. More on reddit.com

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Proposal: Add a fast arithmetic path for __contains__ check of floats on range objects. Why: Currently the range() object already performs an arithmetic-based fast path for __contains__ checks of int values, but not float and integral float values. This results in very long comparisons for ... More on discuss.python.org

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