My answer is not exactly to your question but after you read this, I hope you can decide which type you need to choose for your needs.

Python’s lists are variable-length arrays, not Lisp-style linked lists. The implementation uses a contiguous array of references to other objects, and keeps a pointer to this array.

This makes indexing a list a[i] an operation whose cost is independent of the size of the list or the value of the index.

When items are appended or inserted, the array of references is resized. Some algorithm is applied to improve the performance of appending items repeatedly; when the array must be grown, some extra space is allocated so the next few times don’t require an actual resize i.e over-allocation. More Information

Removing vs Pop vs Delete:

At first glance it looks like all of them are doing the same thing.

Under the hood its behaving different.

removing : remove an element from the list by iterating from 0 index till the first match of the element is found. taking more time to iterate if the element is at the end.

pop : removing element from the list by using the index. taking less time.

del : is a python statement that removes a name from a namespace, or an item from a dictionary, or an item from a list by using the index.

REMOVE:

• it removes the first occurence of value.
• raises ValueError if the value is not present.
• it takes only one argument, so you can't remove multiple value in one shot.

POP:

• remove and return item at index (default last).
• Raises IndexError if list is empty or index is out of range.
• it takes only one argument, so you can't remove multiple value in one shot.

DEL:

• remove the item at index and return nothing.
• it can remove slices from a list or can clear the whole list.

Benchmark:

Worst case : deleting from the end of the list.

yopy:-> python -m timeit "x=range(1000)" "x.pop(999)"
100000 loops, best of 3: 10 usec per loop
yopy:-> python -m timeit "x=range(1000)" "x.remove(999)"
10000 loops, best of 3: 31.3 usec per loop
yopy:-> python -m timeit "x=range(1000)" "del x[999]"
100000 loops, best of 3: 9.86 usec per loop
yopy:->

Best case: begining of the list.

yopy:-> python -m timeit "x=range(1000)" "x.remove(1)"
100000 loops, best of 3: 10.3 usec per loop
yopy:-> python -m timeit "x=range(1000)" "x.pop(1)"
100000 loops, best of 3: 10.4 usec per loop
yopy:-> python -m timeit "x=range(1000)" "del x[1]"
100000 loops, best of 3: 10.4 usec per loop
yopy:->

Point to be noted:

if array grows or shrinks in the middle

• Realloc still depends on total length.
• But, All the trailing elements have to be copied

So, now I hope you can decide what you need to choose for your needs.

Here's the steps (my non-computer-savvy girlfriend had to figure this one out for me, but unlike all the far more complicated processes one can find online, this one works)

1. Open Control Panel
2. Click "Uninstall a Program"
3. Scroll down to Python and click uninstall for each version you don't want anymore.

This works on Windows 7 out of the box, no additional programs or scripts required.

Here's a nice Pythonic way to do it using list comprehensions and enumerate (note that enumerate is zero-indexed):

>>> y = [3,4,5,6]
>>> [x for i, x in enumerate(y) if i != 1] # remove the second element
[3, 5, 6]

The advantage of this approach is that you can do several things at once:

>>> # remove the first and second elements
>>> [x for i, x in enumerate(y) if i != 0 and i != 1]
[5, 6]
>>> # remove the first element and all instances of 6
>>> [x for i, x in enumerate(y) if i != 0 and x != 6]
[4, 5]