To remove all integers, do this:
no_integers = [x for x in mylist if not isinstance(x, int)]
However, your example list does not actually contain integers. It contains only strings, some of which are composed only of digits. To filter those out, do the following:
no_integers = [x for x in mylist if not (x.isdigit()
or x[0] == '-' and x[1:].isdigit())]
Alternately:
is_integer = lambda s: s.isdigit() or (s[0] == '-' and s[1:].isdigit())
no_integers = filter(is_integer, mylist)
Top answer 1 of 8
42
To remove all integers, do this:
no_integers = [x for x in mylist if not isinstance(x, int)]
However, your example list does not actually contain integers. It contains only strings, some of which are composed only of digits. To filter those out, do the following:
no_integers = [x for x in mylist if not (x.isdigit()
or x[0] == '-' and x[1:].isdigit())]
Alternately:
is_integer = lambda s: s.isdigit() or (s[0] == '-' and s[1:].isdigit())
no_integers = filter(is_integer, mylist)
2 of 8
14
None of the items in your list are integers. They are strings which contain only digits. So you can use the isdigit string method to filter out these items.
items = ['1','introduction','to','molecular','8','the','learning','module','5']
new_items = [item for item in items if not item.isdigit()]
print new_items
Link to documentation: http://docs.python.org/library/stdtypes.html#str.isdigit
Reddit
reddit.com › r/learnpython › remove all numbers in a list below a value
r/learnpython on Reddit: Remove all numbers in a list below a value
November 21, 2021 -
I have this code:
list = [1,2,3,4,5,6,7,8,9]
for x in list:
if x<5:
list.remove(x)
listBut it returns [2,4,6,7,8,9] instead of [5,6,7,8,9]
Why does it do this and how do I fix it?
Top answer 1 of 5
10
Don't remove items from a list you iterate over unless you do it in reverse order. Better to create a new list with the items you want to retain.
2 of 5
9
Some good suggestions in the thread. You can use a list comprehension to create a new list of the items you want to keep. I renamed list to list_, list is the name of a python built-in function. list_ = [1,2,3,4,5,6,7,8,9] short_list = [x for x in list_ if x >= 5] print(short_list)
python - Removing number from list of numbers - Stack Overflow
I am trying to remove a number from a list of numbers but for the life of me I just can't make it work. I tried using list.remove() method and .pop() but it is some how not working. largest is a fu... More on stackoverflow.com
removing numbers form list by python - Stack Overflow
In frist method,it again got an index error .I have to remove the element from the list because that's my question on assignment 2022-01-19T09:22:01.343Z+00:00 ... You can use this if you want to remove numbers less than 10 from the list and Calculate the sum of the remaining numbers More on stackoverflow.com
Remove numbers from list with list comprehension
Are these numbers integers or strings? More on reddit.com
5
2
December 27, 2021Remove strings from a list that contains numbers in python - Stack Overflow
Is there a short way to remove all strings in a list that contains numbers? For example my_list = [ 'hello' , 'hi', '4tim', '342' ] would return my_list = [ 'hello' , 'hi'] More on stackoverflow.com
00:44
How to remove items from a list in Python 🐍 - YouTube
05:06
Python List - how to delete elements from a list - YouTube
06:15
Python: Remove Items from List | 3 ways - pop, del, remove - YouTube
03:32
How to Remove all occurrences of an Element in a List in Python?
00:38
How To Remove An Element From A List In Python - YouTube
ItSolutionstuff
itsolutionstuff.com › post › how-to-remove-all-numbers-values-from-list-in-pythonexample.html
How to Remove All Numbers Values from List in Python? - ItSolutionstuff.com
October 30, 2023 - # Create New List with Item myList = ["a", 1, 2, "b", "c", 4, 5, "d"] # Python list remove integer values newList = [val for val in myList if isinstance(val, str)] print(newList) ...
Stack Overflow
stackoverflow.com › questions › 67589267 › removing-number-from-list-of-numbers
python - Removing number from list of numbers - Stack Overflow
remove() works in-place, which means l will be removed from c and that's it, it won't return a new list.
i2tutorials
i2tutorials.com › home › blogs › removing integers from a list in python
Removing integers from a List in python | i2tutorials
August 5, 2020 - We can remove integers or digits from the list by using python function isinstance(). By using this method, we can get items or elements which does not satisfies the function condition
Quora
quora.com › How-do-I-in-Python-remove-all-numbers-items-in-a-list-that-ends-with-a-specific-integer-s
How do I, in Python, remove all numbers (items) in a list that ends with a specific integer(s)? - Quora
Strictly speaking, we didn’t remove anything from s; we just made a new list, also called s, that omitted the numbers ending in 4. The expression on the right hand side in line 2 is a list comprehension. The % in line 2 is the modulus operator; c % 10 is the remainder of c when dividing by 10, which is the right-most integer in the decimal representation of c. ... Why can Python ...
Top answer 1 of 2
1
When you remove from same list, of course the index will be out of range items from list,
BUT you really don't need to remove those items from list, just don't include them in your sum calculation:
n = int(input("Enter number of elements : "))
a = list(map(int, input("\nEnter the numbers : ").strip().split()))
b = sum([num for num in a if num<= 9])
print(b)
2 of 2
1
You can use this if you want to remove numbers less than 10 from the list and Calculate the sum of the remaining numbers
n = int(input("Enter number of elements : "))
a = list(map(int, input("\nEnter the numbers : ").strip().split()))
if len(a) == n:
for num in a:
if num < 9:
a.remove(num)
print('sum',sum(a))
else:
print(f"You must enter {n} number")
Reddit
reddit.com › r/learnpython › remove numbers from list with list comprehension
r/learnpython on Reddit: Remove numbers from list with list comprehension
December 27, 2021 -
How could I complete this string comprehension?
words = [word for word in words if int(word)… # raises an error]
Thank you
Top answer 1 of 3
3
Are these numbers integers or strings?
2 of 3
3
You're likely best off using str.isnumeric as a filter. It won't work on strings with punctuation, but I don't know whether that matters in your case. words = [...] new_words = [ word for word in words if word.isnumeric() ] If you want more fine-tuned control, create a separate verification function and use that to filter out any non-numbers.
w3resource
w3resource.com › python-exercises › basic › python-basic-1-exercise-3.php
Python: Remove and print every third number from a list of numbers until the list becomes empty - w3resource
# Define a function named 'remove_nums' that takes a list 'int_list' as a parameter. def remove_nums(int_list): # Set the starting position for removal to the 3rd element (0-based index). position = 3 - 1 # Initialize the index variable to 0. ...
Top answer 1 of 6
39
Without regex:
[x for x in my_list if not any(c.isdigit() for c in x)]
2 of 6
7
I find using isalpha() the most elegant, but it will also remove items that contain other non-alphabetic characters:
Return true if all characters in the string are alphabetic and there is at least one character, false otherwise. Alphabetic characters are those characters defined in the Unicode character database as “Letter”
my_list = [item for item in my_list if item.isalpha()]
Top answer 1 of 3
1
If your only goal is to keep those two elements, you can do:
import string
number_list = ["December 31, 2020", "10.00%", "$50", "1,452", "7", "testing", "(1)", "(1000)"]
new_list = []
garbage_list = []
for elem in number_list:
new_list.append(elem) if set(elem.lower()) & set(string.ascii_lowercase) else garbage_list.append(elem)
print(new_list)
The key idea is that I use the & operator (intersection) between the set of lowercase characters and the element we have reached in our iteration. If the set is nonempty, then that means there is a character and we want to keep it in our new set.
Note that string.ascii_lowercase is just the string abcde...xyz.
Output:
['December 31, 2020', 'testing']
2 of 3
0
It would be much better if you could tell what all kind of values are kept in number_values like date/time (in other formats), currency (other formats like 500 won), etc which you may or may not want to keep.
I can see that you want to keep first a date format and a string, and exclude everything else, which can be done be like this:
number_list = ["December 31, 2020", "10.00%", "$50", "1,452", "7", "testing", "(1)", "(1000)"]
new_list = []
garbage_list = []
for i in number_list:
// only check for first or second character for digits
if i[0].isdigit() or i[1].isdigit():
garbage_list.append(i)
else:
new_list.append(i)
print(new_list)
Output:
['December 31, 2020', 'testing']
More information would require a robust solution.
DataCamp
datacamp.com › tutorial › python-remove-item-from-list
How to Remove an Item from a List in Python: A Full Guide | DataCamp
August 1, 2024 - # Initialize a list containing sublists of integers list_of_lists = [[1, 2, 3], [4, 5, 6], [7, 8, 9]] # Create a flat list of even numbers by iterating through each sublist # and checking if each number is even flat_even_numbers = [num for sublist in list_of_lists for num in sublist if num % 2 == 0] print(flat_even_numbers) # Expected output: [2, 4, 6, 8] If you want to understand more about list manipulation in data analysis, go through our Data Analyst with Python career track to grow your analytical skills. When working with lists in Python, you may encounter scenarios when you need to remove multiple occurrences of items from a list.
Stack Overflow
stackoverflow.com › questions › 65246185 › python-removing-the-numbers-from-a-numbered-list-and-removing-items-with-certai
Python: Removing the numbers from a numbered list and removing items with certain characters - Stack Overflow
December 11, 2020 - import string alphabet = string.ascii_lowercase + string.ascii_uppercase YourFile = open("yourFile.txt", "r") listOfLines = YourFile.readlines() for lineIndex in range(len(listOfLines)): for char in listOfLines[lineIndex]: if char in alphabet: editedLine = listOfLines[lineIndex].split(char,1)[1] editedLine = str(lineIndex + 1) + " " + char + editedLine #(optional) If you need the Index numbers beside your items listOfLines[lineIndex] = editedLine break anotherFile = open("anotherFile.txt", "w") anotherFile.writelines(listOfLines) anotherFile.close
Python Forum
python-forum.io › thread-38695.html
Remove numbers from a list
November 12, 2022 - I've been working a problem in another forum and ran across something I don't understand. Giving a list of numbers as input and then removing the numbers that are less than or equal to a boundry, can'
Top answer 1 of 5
2
Use lookarounds to check if digits are not enclosed with letters or digits or underscores:
import re
list_1 = ['what are you 3 guys doing there on 5th avenue', 'my password is 5x35omega44',
'2 days ago I saw it', 'every day is a blessing',
' 345000 people have eaten here at the beach']
for l in list_1:
print(re.sub(r'(?<!\w)\d+(?!\w)', '', l))
Output:
what are you guys doing there on 5th avenue
my password is 5x35omega44
days ago I saw it
every day is a blessing
people have eaten here at the beach
Regex demo
2 of 5
1
One approach would be to use try and except:
def is_intable(x):
try:
int(x)
return True
except ValueError:
return False
[' '.join([word for word in sentence.split() if not is_intable(word)]) for sentence in list_1]
Substack
dailypythonprojects.substack.com › daily python projects › remove numbers from python list
Remove Numbers from Python List - by Ardit Sulce
March 18, 2025 - Pro tip: Use a function that gets a list and a threshold number as arguments and returns the filtered list. In the real world, you might work with lists of data that need to be cleaned before use. For instance, you may want to remove invalid or low-value entries from financial reports, user surveys, or even scientific data. Such data may be stored in text files, CSV files, etc, but you may load the data from such files into a Python ...
GeeksforGeeks
geeksforgeeks.org › python-remove-all-digits-from-a-list-of-strings
Python | Remove all digits from a list of strings - GeeksforGeeks
December 26, 2024 - 7 min read Python | Split strings and digits from string list · Sometimes, while working with String list, we can have a problem in which we need to remove the surrounding stray characters or noise from list of digits. This can be in form of Currency prefix, signs of numbers etc.
Top answer 1 of 2
1
Here's how you would do it:
Python
my_list = [5, 2, 1, True, 'abcdefg', 3, False, 4]
my_list = [x for x in my_list if type(x) == int]
2 of 2
1
isdigit() function returns True or False if there are only numbers in ---> String not for integers themselves, as the elements of my_list contain integers too, so isdigit() returns an error, you can fix that by if str(x).isdigit().
W3Schools
w3schools.com › python › python_lists_remove.asp
Python - Remove List Items
Python Lists Access List Items Change List Items Add List Items Remove List Items Loop Lists List Comprehension Sort Lists Copy Lists Join Lists List Methods List Exercises Code Challenge Python Tuples
HCL GUVI
studytonight.com › python-howtos › remove-numbers-from-string-in-python
HCL GUVI | Learn to code in your native language
Supports JavaScript, Python, Ruby, and 20+ programming languages.Explore IDE