Removing the old and adding new key-value pair is the only option. And what do you mean by "I don't really want to have to keep updating it"? If value1 is passed by value, you'll have to update it anyway and if it's passed by reference, changing the key doesn't matter because your new key will point to the same object. More on reddit.com

list = {} Triggered. Sorry, mostly kidding, but list is a type, and definitely should not be used as the variable name for a dict. Also, using a try/except on EOFError for breaking out of your while loop is really weird. Are you trying to mess with people? =) Again, kidding, lol. I basically want to get the value of one key in my dict and add to it, but not to any of the other keys. I have searched all over the internet and can not find or just do not know how to word it to find a solution. What are you actually expecting to do? As written, your code doesn't attempt to change any value, and doing so is very simple. Let's say one of your inputs is "apple". This creates the following key/value pair in your dict: {"apple": 1}. To change this value to, say, 5, you'd simply do this: my_dict["apple"] = 5 That changes the value from 1 to 5. Now, if you want to add to it in the sense of a number, you can do this instead: my_dict["apple"] += 5 This will add 5 to the original value of 1, so your new dict will be this: {"apple": 1} Finally, if you mean "add" as in "add additional values", you need to convert your value into a type that allows for multiple values. The most common is to use a list like this: my_dict = {} dict_key = input() my_dict[dict_key] = [1] my_dict[dict_key].append(5) print(my_dict) # input: test # output: {'test': [1, 5]} If you gave some more details about what you are trying to do we can probably help more. Does that make sense? More on reddit.com

You need to reset add_one when you find a new name. More on reddit.com

Keep this paradigm in your head: dataframes are meant to be instantiated from a data source, they aren't meant to be created as a blank sheet and 'filled in' later on. So also in this case: don't build a dataframe upfront, instead create the dataframe using the dict as the basis for its data. From Create a Pandas DataFrame from List of Dicts:

cols = ['timestamp', 'name', 'adress', 'phone', 'website', 'rating', 'number_of_ratings', 'type']
df = pd.DataFrame(multidict, columns=cols)

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